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Chemistry

Chemistry Study Guide Expanded Edition

16 Units · 469 Quiz Questions · 155 Flashcards · Diagnostic · Full Reference Tables · Diagrams · Saved Progress

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Classification of matter
Matter is either a pure substance (fixed composition) or a mixture (variable composition). Elements are single atom types; compounds are chemically bonded elements in fixed ratios; mixtures are physically separable.
  • Element: one atom type; cannot be broken down chemically (Fe, O₂, Cu, Ne)
  • Compound: two or more elements chemically bonded in fixed ratio; separated only by chemical means (H₂O, NaCl, CO₂)
  • Homogeneous mixture (solution): uniform throughout, single phase (salt water, air, brass, vinegar)
  • Heterogeneous mixture: non-uniform, visible different parts (sand+water, salad, granite, blood)
  • Colloid: particles 1–1000 nm; Tyndall effect (milk, fog, gelatin) — between solution and suspension
  • Suspension: particles >1000 nm; settles on standing; filtered easily (muddy water, Italian dressing)
Separation techniques
All based on physical properties — no new substances form.
  • Filtration: separates insoluble solid from liquid (sand from water; coffee grounds from liquid)
  • Distillation: separates two miscible liquids with different boiling points (alcohol from water; crude oil refining)
  • Evaporation/crystallization: recovers dissolved solid from solution (salt from seawater)
  • Chromatography: separates dissolved substances by polarity/affinity differences (ink pigments, amino acids)
  • Magnetism: separates magnetic material from non-magnetic (iron filings from sand)
  • Centrifugation: separates by density using centrifugal force (cream from milk; blood components)
Allotropes
Allotropes are different structural forms of the SAME element. Same element, different molecular structure → different physical and chemical properties.
  • O₂ (oxygen) and O₃ (ozone): same element (oxygen), different molecular structures → different properties. O₃ is more reactive and has a distinct smell.
  • Diamond and graphite: both pure carbon, but different bonding structures → diamond is hardest known substance; graphite is soft and conducts electricity
  • White phosphorus (P₄) and red phosphorus: both pure P, different properties
  • Key point: allotropes of the same element have DIFFERENT molecular structures AND DIFFERENT properties
  • They have the same atomic number and are made of the same type of atom — only the bonding arrangement differs
Chemical vs physical change
Physical: form/phase changes, composition unchanged. Chemical: new substance with new properties forms.
  • Physical changes: melting, boiling, freezing, dissolving, cutting, crushing, bending, mixing
  • Chemical change indicators: color change, gas produced (bubbles), precipitate formed, irreversible temperature change, light/sound emitted, new odor
  • Dissolving is PHYSICAL — NaCl in water is still NaCl; evaporate the water and you get NaCl back
  • Burning is CHEMICAL — cellulose → CO₂ + H₂O; cannot recover the wood
  • Rusting is CHEMICAL — Fe + O₂ → Fe₂O₃; new substance with new properties
Physical vs chemical properties
  • Physical property: observable without changing composition — color, density, melting point, boiling point, conductivity, solubility, hardness, odor
  • Chemical property: describes how a substance reacts — flammability, reactivity with acids, ability to corrode, toxicity
  • Intensive property: independent of sample size — density, temperature, melting point, color, concentration
  • Extensive property: depends on amount — mass, volume, length, heat content
Dissolving is PHYSICAL — no new substance forms, fully reversible by evaporation.
Compounds separated only by CHEMICAL means; mixtures by PHYSICAL means.
Colloids show the Tyndall effect (light scattering); true solutions do not.
Intensive properties (density, BP) don't change when you cut a sample in half.
D = m / V
% error = |measured − accepted| / accepted × 100
Significant figures
Atlantic-Pacific Rule: decimal Present → count from Pacific side (left) starting at first nonzero; decimal Absent → count from Atlantic side (right) starting at first nonzero.
  • Non-zero digits: ALWAYS significant (245 → 3 sig figs)
  • Leading zeros: NEVER significant (0.0034 → 2 sig figs)
  • Captive zeros (between nonzeros): ALWAYS significant (2005 → 4 sig figs)
  • Trailing zeros WITH decimal point: significant (2.500 → 4 sig figs; 100. → 3 sig figs)
  • Trailing zeros WITHOUT decimal: ambiguous (1500 → 2 sig figs; write 1.500×10³ for 4 sig figs)
  • Exact numbers (counted/defined): infinite sig figs (12 eggs, 100 cm = 1 m)
Sig figs in calculations
  • Multiply/divide: answer has fewest sig figs of any factor (2.5 × 3.45 = 8.6, not 8.625)
  • Add/subtract: answer has fewest DECIMAL PLACES (12.5 + 3.45 = 16.0, not 15.95)
  • Mixed: follow order of operations, apply sig fig rule at each step
Accuracy vs precision
  • Accuracy: closeness to the true/accepted value → measured by % error
  • PrecisStudyion: closeness of repeated measurements to each other → measured by range/deviation
  • High precision, low accuracy: consistent but wrong (systematic error)
  • High accuracy, low precision: correct on average but scattered (random error)
  • Calibration improves accuracy; technique improves precision
Mole concept
A mole is 6.02×10²³ particles (Avogadro's number). It is chemistry's 'counting unit' — like a dozen = 12, a mole = 6.02×10²³.
  • 1 mol = 6.02×10²³ particles (atoms, molecules, ions, formula units)
  • 1 mol of any substance = its molar mass in grams (e.g., 1 mol H₂O = 18.0 g)
  • Moles→particles: × 6.02×10²³ | Particles→moles: ÷ 6.02×10²³
  • Moles→grams: × GFM | Grams→moles: ÷ GFM
  • GFM (gram formula mass) = sum of all atomic masses in formula
  • Example: GFM of Ca(NO₃)₂ = 40.1 + 2(14.0 + 3×16.0) = 164.1 g/mol
Scientific notation & dimensional analysis
  • Scientific notation: M × 10ⁿ where 1 ≤ M < 10 (e.g., 0.00034 = 3.4×10⁻⁴)
  • Dimensional analysis: cancel units by writing conversion factors as fractions
  • Always write units with every number; check that unwanted units cancel
  • Example: 5.0 km × (1000 m/1 km) × (100 cm/1 m) = 5.0×10⁵ cm
0.0034 has only 2 sig figs — leading zeros never count.
% error is ALWAYS positive — use absolute value.
1500 = 2 sig figs; 1500. = 4 sig figs (the decimal point matters).
Accuracy ≠ precision — you can be precise AND wrong.
n = m / GFM
% error = |measured − accepted| / accepted × 100
1 mol = 6.02×10²³ particles
History of atomic models
Each model was replaced when experimental evidence it couldn't explain emerged.
  • Dalton (1803): solid, indivisible sphere — explained fixed mass ratios; no substructure
  • Thomson (1897): plum pudding — discovered electrons via cathode ray tube; positive sphere with embedded e⁻
  • Rutherford (1911): nuclear model — gold foil experiment; dense positive nucleus, mostly empty space; most α passed through, few deflected back
  • Bohr (1913): planetary/shell model — electrons in fixed circular orbits at set energy levels; explained hydrogen bright-line spectrum
  • Wave-mechanical (quantum) model (current): electrons in probability clouds (orbitals), not fixed paths; explains all elements' spectra
Subatomic particles
  • Proton: charge +1, mass ≈1 amu, located in nucleus; atomic number = number of protons = element identity
  • Neutron: charge 0, mass ≈1 amu, located in nucleus; number of neutrons = mass number − atomic number
  • Electron: charge −1, mass ≈0 amu (1/1836 of proton), in orbitals outside nucleus
  • Neutral atom: protons = electrons
  • Cation (+): atom LOST electrons (Na → Na⁺ lost 1 e⁻)
  • Anion (−): atom GAINED electrons (Cl → Cl⁻ gained 1 e⁻)
Electron configuration
Electrons fill lowest energy levels first (aufbau principle). Each orbital holds max 2 electrons with opposite spins (Pauli). One electron per orbital before pairing (Hund's rule).
  • s sublevel: max 2 e⁻ (1 orbital) | p: max 6 e⁻ (3 orbitals) | d: max 10 e⁻ (5 orbitals) | f: max 14 e⁻ (7 orbitals)
  • Fill order: 1s, 2s, 2p, 3s, 3p, 4s, 3d, 4p, 5s, 4d, 5p, 6s, 4f, 5d, 6p
  • Ground state: lowest energy config (unique to each element, matches position on periodic table)
  • Excited state: electron absorbed energy and moved to a higher sublevel — total e⁻ count still equals atomic number
  • Special exceptions to know: Cr (24) = [Ar] 3d⁵ 4s¹; Cu (29) = [Ar] 3d¹⁰ 4s¹ (half-filled/filled d is extra stable)
Isotopes & atomic mass
Isotopes: same element (same protons), different neutrons, different mass number.
  • Isotope notation: ᴬ_Z X or element-mass (e.g., ¹²₆C or Carbon-12)
  • Same: atomic number, number of protons, chemical behavior, element identity
  • Different: mass number, number of neutrons, nuclear stability, physical mass
  • Atomic mass (on periodic table) = weighted average of all isotopes' masses × their natural abundances
  • Example: Cl has two isotopes — Cl-35 (75.77%) and Cl-37 (24.23%) → avg = 35.5 amu
Bright-line spectra
Excited electrons fall to lower energy levels → release energy as photons of specific wavelengths → unique spectral 'fingerprint' for each element.
  • Each element has a unique bright-line spectrum (used to identify elements in stars, flames)
  • Continuous spectrum: all wavelengths (white light through prism)
  • Bright-line (emission) spectrum: only specific wavelengths emitted
  • Higher jump → shorter wavelength → higher frequency → more energy
  • EM spectrum order (low→high energy): radio, microwave, infrared, visible (ROYGBIV), UV, X-ray, gamma
  • c = λν: speed of light = wavelength × frequency
Excited state is VALID — total electrons still equal atomic number; just not the lowest arrangement.
4s fills BEFORE 3d (4s is lower energy during filling); but 3d is listed below 4s in configs.
Rutherford DISPROVED Thomson's model.
Atomic mass ≠ mass number — atomic mass is a weighted average (often a decimal).
Atomic mass = Σ(isotope mass × fractional abundance)
Neutrons = mass number − atomic number
c = λν
Diagram
foil + α particles → ← few deflect

Rutherford gold-foil experiment — most α particles pass through (empty space); a few deflect off the dense positive nucleus.

Organization & groups
118 elements arranged by increasing atomic number. Properties repeat periodically (periodic law).
  • Period (row): elements in same period have same number of electron shells
  • Group/family (column): elements with same number of valence electrons, similar chemical properties
  • Group 1 (Alkali metals): 1 valence e⁻, very reactive, +1 ions, react violently with water
  • Group 2 (Alkaline earth): 2 valence e⁻, reactive, +2 ions
  • Groups 3–12 (Transition metals): variable oxidation states, colored compounds, use Table S for charges
  • Group 17 (Halogens): 7 valence e⁻, most reactive nonmetals, form −1 ions, diatomic molecules
  • Group 18 (Noble gases): full valence shell (8 e⁻, or 2 for He), nonreactive, monatomic
Metals, nonmetals, metalloids
The staircase line on the periodic table separates metals (left) from nonmetals (right).
  • Metals (~75% of elements): shiny luster, malleable, ductile, good conductors of heat & electricity, lose electrons to form cations
  • Nonmetals (upper right): dull/brittle, poor conductors (except graphite), gain/share electrons, form anions or covalent bonds
  • Metalloids (B, Si, Ge, As, Sb, Te — along the staircase): intermediate properties; semiconductors used in electronics
  • Hydrogen: unique — placed in Group 1 but is a nonmetal gas; can behave as +1 or −1
Periodic trends
All trends driven by nuclear charge (# protons) vs. shielding (inner electron shells). More protons = stronger pull on outer electrons. More shells = more shielding = weaker effective nuclear charge.
  • Atomic radius: DECREASES left→right (more protons, same shell), INCREASES top→bottom (more shells)
  • Ionization energy (energy to remove 1 e⁻): INCREASES left→right, DECREASES top→bottom
  • Electronegativity (pull on shared electrons): INCREASES left→right, DECREASES top→bottom; highest = F (4.0); lowest = Fr
  • Metallic character: DECREASES left→right, INCREASES top→bottom (opposite of EN)
  • Ionic radius: cations are SMALLER than parent atom (lost e⁻, same protons pull fewer e⁻ closer); anions are LARGER (gained e⁻, same protons spread over more e⁻)
Transition metal naming (Roman numerals)
Transition metals have variable oxidation states. Roman numerals in the name tell you which charge the metal has in that compound.
  • Format: metal name (Roman numeral) anion name — e.g., Iron(II) chloride = FeCl₂ (Fe²⁺); Iron(III) chloride = FeCl₃ (Fe³⁺)
  • The Roman numeral = the oxidation state/charge of the transition metal in that compound
  • To find the Roman numeral: use the anion charge to figure out what the metal charge must be so everything sums to zero
  • FeCl₂: Cl = −1 (×2 = −2) → Fe = +2 → iron(II). FeCl₃: Cl = −1 (×3 = −3) → Fe = +3 → iron(III)
  • PdO: O = −2 → Pd = +2 → palladium(II) oxide
  • CuO = copper(II) oxide; Cu₂O = copper(I) oxide — same elements, different ratios, different names
  • Common transition metals with multiple charges: Fe (2+,3+), Cu (1+,2+), Cr (2+,3+,6+), Mn (2+,4+,7+), Pb (2+,4+), Sn (2+,4+)
Valence electrons & ion charges
  • Main-group valence electrons = group number (Group 1 = 1, Group 2 = 2, Group 13 = 3 ... Group 18 = 8)
  • Metals lose valence electrons to reach noble gas config → cations
  • Nonmetals gain electrons to fill valence shell → anions
  • Isoelectronic: same electron configuration (Na⁺, Mg²⁺, Ne, O²⁻, F⁻ all have 10 electrons)
  • Transition metals: use Table S — most have multiple possible charges (Fe²⁺/Fe³⁺, Cu⁺/Cu²⁺)
Fluorine has the HIGHEST electronegativity (4.0).
Coulombic attraction (F = kq₁q₂/r²) is the underlying reason for ALL periodic trends.
Transition metals don't follow main-group valence-electron rules for charges.
Noble gases are in Group 18 — 8 valence electrons (not 0).
EN diff: <0.4 nonpolar covalent | 0.4–1.7 polar covalent | ≥1.7 ionic
Coulomb's Law: F = k(q₁q₂)/r²
Diagram
Periodic Table EN / IE increase → Radius increases ↓ F

Periodic trends: atomic radius grows ↓ and ←. Ionization energy and electronegativity grow ↑ and → (toward F in the top-right).

Bond types
Determined by electronegativity difference (ΔEN) between bonded atoms.
  • Ionic (ΔEN ≥ 1.7): metal + nonmetal; electron TRANSFER; forms ions; electrostatic attraction (NaCl, MgO, CaF₂)
  • Polar covalent (ΔEN 0.4–1.7): nonmetal + nonmetal of different EN; UNEQUAL sharing; δ⁺ and δ⁻ partial charges (HF, H₂O, NH₃, HCl)
  • Nonpolar covalent (ΔEN <0.4): same element or very similar EN; EQUAL sharing (Cl₂, O₂, N₂, CH₄, C-C bonds)
  • Metallic: sea of delocalized valence electrons around fixed positive metal ion cores; explains conductivity, malleability, luster
Lewis dot structures
Count total valence electrons → draw skeleton (central atom = least electronegative, usually) → add lone pairs to satisfy octets.
  • Octet rule: most atoms want 8 valence electrons in bonds + lone pairs (exceptions: H = 2, B = 6, expanded octets for period 3+)
  • Single bond = 2 shared electrons; double bond = 4; triple bond = 6
  • Lone pairs count toward octet but are not bonding
  • Resonance: when multiple valid Lewis structures exist (O₃, NO₃⁻, SO₄²⁻) — actual structure is average
  • Formal charge: valence e⁻ − (lone pair e⁻ + ½ bonding e⁻) — minimize on each atom
VSEPR & molecular geometry
Electron pairs repel → arrange to minimize repulsion. Lone pairs repel MORE than bonding pairs.
  • 2 electron groups: linear (180°) — CO₂, BeCl₂
  • 3 groups, 0 lone pairs: trigonal planar (120°) — BF₃, SO₃
  • 4 groups, 0 lone pairs: tetrahedral (109.5°) — CH₄, CCl₄
  • 4 groups, 1 lone pair: trigonal pyramidal (107°) — NH₃
  • 4 groups, 2 lone pairs: bent/V-shaped (104.5°) — H₂O
  • Lone pairs compress bond angles
Molecular polarity
A polar molecule requires BOTH polar bonds AND asymmetric geometry. Symmetric molecules with polar bonds can cancel out.
  • CO₂: linear → dipoles cancel → nonpolar molecule (despite polar C=O bonds)
  • H₂O: bent → dipoles don't cancel → polar molecule
  • CH₄: tetrahedral, symmetric → nonpolar
  • NH₃: pyramidal, asymmetric → polar
  • CCl₄: tetrahedral, symmetric → nonpolar despite polar C-Cl bonds
  • CHCl₃: tetrahedral but asymmetric → polar
Compounds with BOTH ionic and covalent bonds
When an ionic compound contains a polyatomic ion, it has BOTH types of bonds: ionic bonds between the metal cation and the polyatomic ion, AND covalent bonds within the polyatomic ion itself.
  • Rule: if the formula contains a polyatomic ion, it has both bond types
  • KClO₂ (potassium chlorite): K⁺ and ClO₂⁻ are held by IONIC bonds; inside ClO₂⁻ the Cl−O bonds are COVALENT
  • NaOH: Na⁺ and OH⁻ ionic; O−H inside hydroxide is covalent
  • Ca(NO₃)₂: Ca²⁺ and NO₃⁻ ionic; N−O bonds inside nitrate are covalent
  • NH₄Cl: NH₄⁺ and Cl⁻ ionic; N−H inside ammonium are covalent
  • Pure ionic only: CaCl₂, NaCl, MgO, Li₂S (no polyatomic ions)
  • Pure covalent only: H₂O, CO₂, CH₄, HCl (no ions at all)
Network solids & properties
  • Network covalent solid: atoms covalently bonded throughout in a giant network — diamond (C), quartz (SiO₂), graphite
  • Very high melting points; hard; poor conductors (except graphite which conducts along layers)
  • Ionic solids: high MP, hard, brittle, conduct when molten or dissolved, NOT as solid
  • Molecular solids: low MP, soft, poor conductors (IMFs hold together, not ionic/covalent bonds)
  • Metallic solids: variable MP, malleable, ductile, excellent conductors
Ionic solids DON'T conduct — ions locked in lattice. Must melt or dissolve for conductivity.
Symmetry is KEY: CO₂ has polar bonds but is nonpolar because it's linear and symmetric.
H and He need only 2 electrons (duet rule), not 8.
Lone pairs are NOT shown in the molecular geometry name — only bonding pairs determine the shape name.
ΔEN: <0.4 nonpolar cov | 0.4–1.7 polar cov | ≥1.7 ionic
Criss-cross rule: swap charge magnitudes as subscripts, reduce to simplest ratio
Diagram
CO₂ — nonpolar linear → dipoles cancel H₂O — polar bent → dipoles don't cancel

Molecular polarity: CO₂ is linear (symmetric → nonpolar); H₂O is bent (asymmetric → polar).

Molar mass (GFM)
Sum of atomic masses of all atoms in the formula. Look up atomic masses on the periodic table.
  • Example: H₂O = 2(1.0) + 16.0 = 18.0 g/mol
  • Example: Ca(NO₃)₂ = 40.1 + 2(14.0 + 3×16.0) = 164.1 g/mol
  • Parentheses mean multiply: Ca(OH)₂ has 2 O and 2 H from the (OH) group
  • GFM bridges grams ↔ moles
Percent composition
  • % element = (total mass of that element in 1 mol / GFM) × 100
  • Example: % H in H₂O = (2×1.0)/18.0 × 100 = 11.1%
  • Sum of all % compositions = 100% (good check)
Empirical & molecular formulas
Empirical = simplest whole-number ratio. Molecular = actual number of atoms.
  • Empirical steps: (1) % → g (assume 100 g); (2) g ÷ molar mass → moles; (3) ÷ by smallest; (4) × to get whole numbers
  • Molecular formula: n = molecular mass ÷ empirical formula mass; multiply subscripts by n
  • Example: empirical CH₂ (mass=14), molecular mass=56 → n=4 → C₄H₈
  • Empirical and molecular can be identical (H₂O, CO₂, CH₄)
Stoichiometry — the 4-step roadmap
Every stoichiometry problem follows the same path: grams → moles → moles → grams. Moles are always the bridge.
  • Step 1 (Given → mol): divide grams of given substance by its GFM
  • Step 2 (Mole ratio): multiply by the coefficient ratio from the balanced equation (wanted ÷ given)
  • Step 3 (mol → wanted): multiply by GFM of wanted substance (for mass) OR by 6.02×10²³ (for particles) OR by 22.4 L (for gas at STP)
  • Mass→mass example: 2H₂ + O₂ → 2H₂O. How many g H₂O from 4.0 g H₂? → 4.0/2.0 = 2.0 mol H₂ × (2 mol H₂O/2 mol H₂) × 18.0 g/mol = 36 g H₂O
  • Mass→volume (STP): g ÷ GFM × 22.4 L/mol = liters of gas at STP
  • Mass→particles: g ÷ GFM × 6.02×10²³ = number of particles
Limiting & excess reagent
When two reactants are given, find which runs out first — that is the limiting reagent and sets the ceiling on products.
  • Method: convert BOTH reactants to moles of product; whichever gives LESS product is the limiting reagent
  • Example: 4 mol H₂ and 3 mol O₂ react (2H₂+O₂→2H₂O). H₂ gives 4 mol H₂O; O₂ gives 6 mol H₂O → H₂ is limiting (gives less)
  • Excess reagent: the reactant that is NOT used up; some is left over after the reaction
  • Amount of excess = initial moles − moles consumed by limiting reagent × stoichiometric ratio
  • Theoretical yield = max product from the limiting reagent
  • % yield = (actual yield / theoretical yield) × 100 — cannot exceed 100%
  • Causes of <100% yield: incomplete reaction, side reactions, product lost during transfer/purification
Mole–mole, mole–volume, and volume–volume
At STP, gas volumes are directly proportional to moles. This allows volume ratios.
  • Mole–mole: use coefficient ratio directly (2 mol H₂ : 1 mol O₂ : 2 mol H₂O)
  • Mole–volume at STP: 1 mol any ideal gas = 22.4 L; use as a conversion factor
  • Volume–volume at STP (Gay-Lussac): gas volumes combine in same ratio as coefficients — 2 L H₂ + 1 L O₂ → 2 L H₂O
  • Example: 3 L N₂ + 9 L H₂ → 6 L NH₃ (ratio maintained: 1:3:2)
Hydrates
Ionic compounds with water molecules embedded in the crystal lattice.
  • Formula written as: ionic compound · nH₂O (e.g., CuSO₄·5H₂O = copper(II) sulfate pentahydrate)
  • % water = (mass of H₂O per formula unit / total molar mass) × 100
  • Heating a hydrate drives off water of crystallization → anhydrous compound remains
  • Mass lost when heated = mass of water in the hydrate
  • To find n: (mass lost / 18.0) ÷ (remaining mass / GFM of anhydrous salt)
Multiply through parentheses in formulas: Mg(OH)₂ has 2 O and 2 H.
Limiting reagent determines theoretical yield — excess is what's left over.
% yield cannot exceed 100% — if it does, there's a measurement or calculation error.
Always convert % to grams first when finding empirical formulas.
For limiting reagent: compare moles of PRODUCT each reactant could make, not just moles of reactant.
n = m/GFM
% composition = (mass of part / total mass) × 100
n_molecular = MW / EFM
% yield = (actual/theoretical) × 100
1 mol gas at STP = 22.4 L
g given ÷ GFM_given × (mol wanted/mol given) × GFM_wanted = g wanted
Reaction types
  • Synthesis (combination): A + B → AB (2H₂ + O₂ → 2H₂O)
  • Decomposition: AB → A + B (2H₂O → 2H₂ + O₂; CaCO₃ → CaO + CO₂)
  • Single replacement: A + BC → AC + B (Zn + CuSO₄ → ZnSO₄ + Cu) — use Table J
  • Double replacement (metathesis): AB + CD → AD + CB — ions switch partners (NaCl + AgNO₃ → AgCl↓ + NaNO₃)
  • Combustion: CₓHᵧ + O₂ → CO₂ + H₂O (complete combustion); CO or C produced if incomplete
  • Neutralization: acid + base → salt + water (special case of double replacement)
Balancing equations
Conservation of mass — atoms cannot be created or destroyed.
  • Only change COEFFICIENTS — NEVER subscripts (changing subscripts changes the substance)
  • Strategy: balance metals first → nonmetals → H → O
  • Diatomic elements (H₂, N₂, O₂, F₂, Cl₂, Br₂, I₂) — don't forget the subscript 2
  • Check: same number of each atom on both sides AND total charge balanced for ionic equations
Activity series & solubility rules
  • Table J (Activity series): single replacement is spontaneous only if the replacing element is HIGHER on the list
  • Halogens: F > Cl > Br > I (each displaces those below it)
  • If replacing element is LOWER → NR (no reaction)
  • Table F (Solubility): predicts precipitates in double replacement
  • Precipitate forms when product is listed as insoluble — write ↓ after its formula
  • Most nitrates (NO₃⁻), alkali metals, and NH₄⁺ compounds are soluble
Net ionic equations
  • Full ionic equation: write all soluble ionic compounds as separated ions
  • Spectator ions: appear on both sides unchanged — cancel them out
  • Net ionic equation: shows only species that actually change / react
  • Example: Pb²⁺(aq) + 2I⁻(aq) → PbI₂(s) (spectators Na⁺ and NO₃⁻ cancelled)
NEVER change subscripts — only coefficients.
Check Table J BEFORE predicting single replacement products. If lower on list → NR.
Table F for precipitate prediction — if the product ion combination is listed insoluble, ↓ forms.
Combustion of hydrocarbons ALWAYS produces CO₂ and H₂O (complete combustion).
g given ÷ GFM × mole ratio × GFM wanted = g product
% yield = actual/theoretical × 100
States of matter & particle motion
  • Solid: particles in fixed positions, vibrate in place; definite shape & volume; incompressible
  • Liquid: particles close but mobile; definite volume, no definite shape; slightly compressible
  • Gas: particles far apart, random rapid motion; no definite shape or volume; highly compressible
  • Plasma: high-energy ionized gas (4th state) — present in stars, lightning, fluorescent lights
  • Temperature = average kinetic energy of particles; KE = ½mv²
Potential energy during phase changes & evaporation
A common question type: what happens to KE and PE during phase changes and evaporation.
  • During a phase change (melting, boiling): KE (temperature) stays CONSTANT; PE INCREASES as particles overcome intermolecular forces
  • During evaporation: PE of water molecules INCREASES as they escape the liquid — they overcome attractive forces between molecules
  • The molecules that evaporate are the HIGH-energy ones — this lowers the average KE of the remaining liquid → evaporative cooling
  • Heat flows from HOT to COLD — always from higher temperature to lower temperature
  • Evaporation is endothermic: the liquid absorbs energy (cools down) as molecules escape
  • Condensation is exothermic: gas → liquid releases energy (warms surroundings)
Experimental design in lab questions
Lab questions always ask about controls, variables, and what conclusions can be drawn.
  • Control group: the group where the independent variable is NOT applied — establishes a baseline for comparison
  • Independent variable: what the experimenter deliberately changes
  • Dependent variable: what is measured/observed as a result
  • A dry towel (no water) in an evaporation experiment = control — shows temperature change is due to evaporation, not other factors
  • 'State why the student left one towel dry' → it serves as a control to compare against
Heating/cooling curve — 5 segments
  • Segment 1 (sloped): solid heating — KE increases, temperature rises, q = mCΔT (C_ice = 2.09 J/g·K)
  • Segment 2 (flat at MP): melting — PE increases (bonds between particles weaken), T constant, q = mH_f
  • Segment 3 (sloped): liquid heating — KE increases, T rises, q = mCΔT (C_water = 4.18 J/g·K)
  • Segment 4 (flat at BP): boiling — PE increases (particles escape), T constant, q = mH_v
  • Segment 5 (sloped): gas heating — KE increases, T rises, q = mCΔT (C_steam = 2.01 J/g·K)
  • Cooling curve is the exact reverse — energy released, segments run backward
Intermolecular forces (IMFs)
Forces BETWEEN molecules. Stronger IMF → higher BP, higher MP, lower vapor pressure, lower evaporation rate, higher surface tension, higher viscosity.
  • Hydrogen bonds (STRONGEST): only when H is directly bonded to N, O, or F (H-N, H-O, H-F)
  • Examples: H₂O, NH₃, HF, alcohols, DNA base pairing
  • Dipole-dipole: between polar molecules that lack H bonded to N/O/F
  • London dispersion forces (LDF/van der Waals): present in ALL molecules; ONLY force in nonpolar; increases with molar mass and surface area (more electrons → stronger temporary dipoles)
  • Strength: H-bond > dipole-dipole > LDF
Vapor pressure & boiling
  • Vapor pressure: pressure exerted by vapor above a liquid in a closed system
  • Higher temperature → higher vapor pressure (more molecules have enough energy to escape)
  • Weaker IMFs → higher vapor pressure (easier to escape)
  • Boiling point: temperature where vapor pressure = atmospheric pressure (Table H gives curves)
  • Normal BP: temp where VP = 101.3 kPa (1 atm)
  • At higher altitude (lower P_atm): water boils at LOWER temperature
During a phase change, T does NOT change — heat changes PE only, not KE.
LDF exists in ALL molecules — not just nonpolar ones.
Flat segment on heating curve → use q = mH (NOT q = mCΔT, because ΔT = 0).
Higher vapor pressure means WEAKER IMFs and LOWER boiling point.
K = °C + 273
q = mCΔT (sloped — T changing)
q = mH_f (melting/freezing) | q = mH_v (boiling/condensing)
Table B: C_water=4.18 J/g·K, H_f=334 J/g, H_v=2260 J/g
Diagram
Heat added → Temp (°C) solid ↑ melting liquid ↑ boiling gas ↑

Heating curve: sloped = KE↑ (q=mCΔT); flat plateaus = phase change, PE↑, T constant (q=mH).

Kinetic Molecular Theory (KMT)
Ideal gas assumptions — real gases approximate these under high T and low P.
  • Gas particles in constant, random, straight-line motion
  • Particle volume is negligible compared to container
  • No attractive or repulsive forces between gas particles
  • All collisions are perfectly elastic (no net energy lost)
  • Average kinetic energy is directly proportional to Kelvin temperature (KE ∝ T)
Gas laws — ALWAYS convert to Kelvin!
  • Boyle's Law: P₁V₁ = P₂V₂ (constant T and n) — inverse relationship (↑P → ↓V)
  • Charles's Law: V₁/T₁ = V₂/T₂ (constant P and n) — direct relationship (↑T → ↑V)
  • Gay-Lussac's Law: P₁/T₁ = P₂/T₂ (constant V and n) — direct relationship (↑T → ↑P)
  • Combined Gas Law: P₁V₁/T₁ = P₂V₂/T₂ (covers all three above; covers any two changing)
  • Avogadro's Law: equal volumes of gas at same T and P contain equal numbers of molecules
STP, molar volume, and ideal vs real
  • STP (Standard Temperature and Pressure): 273 K (0°C) and 101.3 kPa (Table A)
  • 1 mole of ANY ideal gas at STP = 22.4 L
  • Most ideal conditions: HIGH temperature, LOW pressure (particles far apart, minimal attractions)
  • Most ideal gases: small, nonpolar molecules (H₂, He, Ne) with very weak IMFs
  • Real gases deviate most at: LOW temperature, HIGH pressure — particles close, attractions matter
Dalton's Law & Graham's Law
  • Dalton's Law of Partial Pressures: P_total = P₁ + P₂ + P₃ + ...
  • Each gas in a mixture exerts pressure independently
  • Graham's Law (diffusion/effusion): lighter molecules move faster at same temperature
  • Effusion rate ∝ 1/√(molar mass) — H₂ diffuses much faster than O₂
ALWAYS convert °C to Kelvin BEFORE using any gas law formula (K = °C + 273).
Absolute zero (0 K = −273°C) is the lowest possible temperature — KE = 0.
Gas volume calculations: if T or P is not given/changing, use STP values.
P₁V₁/T₁ = P₂V₂/T₂
K = °C + 273
1 mol gas = 22.4 L at STP
P_total = P₁ + P₂ + ...
Solution vocabulary
  • Solute: what is dissolved (smaller quantity)
  • Solvent: what does the dissolving (larger quantity) — water is the universal solvent
  • Aqueous solution: solute dissolved in water
  • Like dissolves like: polar/ionic solutes dissolve in polar solvents; nonpolar in nonpolar
  • Solvation (hydration): water molecules surround and separate solute ions/molecules
  • Electrolyte: substance that produces ions in solution → conducts electricity (NaCl, HCl, NaOH)
  • Nonelectrolyte: does not ionize → does not conduct (sugar, ethanol, urea)
Factors affecting solubility
  • Temperature ↑ for SOLIDS: solubility usually increases (more thermal energy to break solute-solute bonds)
  • Temperature ↑ for GASES: solubility DECREASES (gas molecules have more energy to escape)
  • Pressure ↑ for GASES only: solubility increases (Henry's Law: S = kP) — explains carbonated drinks
  • Pressure has negligible effect on solid/liquid solubility
  • Stirring: increases rate of dissolving ONLY — not the maximum amount
  • Particle size (crushing): increases rate ONLY — more surface area exposed
Solubility curves (Table G)
  • On the line: saturated — maximum solute dissolved at that temperature
  • Below the line: unsaturated — more solute can still dissolve
  • Above the line: supersaturated — UNSTABLE; extra solute will crystallize out
  • Most solid solubility curves slope upward (higher T → more dissolves)
  • Gas solubility curves slope downward (higher T → less dissolves)
  • Reading Table G: find the temperature on the x-axis → read up to the curve → read left to get g solute per 100 g H₂O
  • How much crystallizes: dissolve at high T (saturated) → cool to lower T → excess = (solubility at T_high) − (solubility at T_low)
Crystallization
Crystallization is the process by which dissolved solute comes out of solution and forms solid crystals. It is a physical change and a key separation technique.
  • Occurs when a solution becomes supersaturated — more solute is dissolved than the solvent can hold at that temperature
  • Trigger methods: (1) Cool a hot saturated solution — solubility drops, excess solute crystallizes out; (2) Evaporate solvent — solution becomes concentrated until supersaturated; (3) Add a seed crystal — gives particles a surface to nucleate on
  • Seed crystal: a small crystal of the same substance added to a supersaturated solution to initiate crystallization
  • Fractional crystallization: using temperature changes to selectively crystallize one substance out of a mixture of dissolved solids (exploits different solubility curves)
  • Example (Table G): KNO₃ dissolves 110 g/100 g H₂O at 60°C. Cooled to 20°C, only 32 g dissolves → 78 g crystallizes out
  • Example: NaCl solubility barely changes with temperature → not easily purified by crystallization; KNO₃ solubility changes greatly → ideal for recrystallization
  • Crystallization vs. precipitation: crystallization is slow, produces well-formed crystals; precipitation is fast, produces amorphous solid
  • Crystal lattice: ions arrange in a repeating 3D pattern as they come out of solution — minimizing potential energy
Concentration
  • Molarity (M): M = moles of solute / liters of solution (mol/L)
  • ppm: (mass solute / mass solution) × 10⁶ (used for very dilute solutions, e.g., water quality)
  • Dilution: M₁V₁ = M₂V₂ (moles of solute stay constant when diluting)
Colligative properties
Properties that depend on the NUMBER of dissolved particles, not their identity.
  • Boiling point elevation: adding solute raises the boiling point (ΔBP = K_b × m × i)
  • Freezing point depression: adding solute lowers the freezing point — roads, antifreeze
  • Vapor pressure lowering: solute lowers VP of solvent
  • Osmotic pressure: water moves from low to high solute concentration through semipermeable membrane
  • Ionic solutes have greater effect: 1 mol NaCl → 2 mol ions; 1 mol CaCl₂ → 3 mol ions
Saturated ≠ concentrated; saturated just means at maximum capacity (on the curve line).
Stirring and crushing only affect RATE, not final equilibrium amount dissolved.
Gases become less soluble as temperature rises (opposite of most solids).
Molarity uses LITERS of solution, not solvent — convert mL to L.
Crystallization is a PHYSICAL change — the same substance is recovered, just in solid form.
Amount that crystallizes = solubility at T_high − solubility at T_low (per 100 g H₂O).
M = mol solute / L solution
ppm = (mass solute / mass solution) × 10⁶
M₁V₁ = M₂V₂ (dilution)
g crystallized = solubility(T₁) − solubility(T₂), per 100 g H₂O
Diagram
Temperature → g / 100g H₂O supersaturated ↑ ← saturated (on line) unsaturated ↓

Solubility curve zones. On the line = saturated; below = unsaturated; above = supersaturated (unstable).

Endothermic vs exothermic
ENDOthermic = Energy goes IN. EXOthermic = Energy EXits.
  • Endothermic: absorbs energy from surroundings; ΔH = positive (+); heat is a REACTANT; surroundings feel cold; products at HIGHER PE than reactants
  • Exothermic: releases energy to surroundings; ΔH = negative (−); heat is a PRODUCT; surroundings feel warm; products at LOWER PE
  • Real-world endothermic: cold packs, photosynthesis, evaporation, melting ice, dissolving NH₄NO₃
  • Real-world exothermic: combustion, hand warmers, neutralization, respiration, dissolving NaOH, nuclear fission
Potential energy diagrams
Reactants on left, products on right. Peak = activated complex (transition state). The curve shows PE as reaction proceeds.
  • Activation energy (Ea forward): peak height ABOVE reactants = minimum energy to start reaction
  • Activation energy (Ea reverse): peak height ABOVE products = energy to reverse the reaction
  • ΔH = H_products − H_reactants (can be + or −)
  • Exothermic diagram: products LOWER than reactants; ΔH negative
  • Endothermic diagram: products HIGHER than reactants; ΔH positive
  • Catalyst: lowers Ea for BOTH directions, does NOT change ΔH or reactant/product energy levels
  • Activated complex (transition state): at the peak; highly unstable, cannot be isolated
Bond energy & ΔH
Breaking bonds requires energy (endothermic). Forming bonds releases energy (exothermic).
  • ΔH = energy of bonds BROKEN − energy of bonds FORMED
  • If broken > formed → ΔH positive → endothermic
  • If formed > broken → ΔH negative → exothermic
  • Bond energy values come from Table I
Table I — Heats of reaction & dissolving
Table I gives ΔH values for specific reactions at 298 K and 101.3 kPa. Know how to read it for dissolving reactions.
  • Negative ΔH in Table I = exothermic process (releases heat — surroundings warm up)
  • Positive ΔH in Table I = endothermic process (absorbs heat — surroundings cool down)
  • Dissolving NaOH(s): ΔH is negative → exothermic — the solution gets WARM
  • Dissolving NH₄NO₃(s): ΔH is positive → endothermic — the solution gets COLD (used in cold packs)
  • Dissolving KNO₃(s): ΔH is positive → endothermic
  • Dissolving NH₄Cl(s): ΔH is positive → endothermic
  • Key: if the question asks which dissolving process is exothermic → find the one with NEGATIVE ΔH in Table I
Entropy (S)
Entropy = measure of disorder/randomness of a system.
  • Entropy increases: solid→liquid→gas, dissolving, more moles of gas produced, higher temperature
  • Entropy decreases: gas→liquid→solid, crystallization, fewer moles of gas, lower temperature
  • Spontaneous reactions tend toward lower energy AND higher entropy
  • ΔG = ΔH − TΔS (Gibbs free energy) — spontaneous when ΔG < 0
Activation energy is measured from REACTANTS up to peak — NOT from a zero baseline.
Catalyst lowers Ea but does NOT change ΔH or the energy of reactants/products.
Exothermic = −ΔH (releases energy). Don't flip the sign.
ΔH = bonds broken MINUS bonds formed (not the other way around).
ΔH = H_products − H_reactants
ΔH = bonds broken − bonds formed
Ea(forward) = peak − reactants | Ea(reverse) = peak − products
Diagram
Reaction progress → PE Ea → RP — catalyzed (lower Ea)

PE diagram: Ea = peak−reactants; ΔH = products−reactants. Dashed = catalyzed pathway (lower Ea, same ΔH).

Collision theory
For a reaction to occur, three conditions MUST ALL be met:
  • 1. Particles must collide with each other
  • 2. Collisions must have proper geometric orientation
  • 3. Collisions must have energy ≥ activation energy (Ea)
  • Effective collision: meets all three conditions → products form
  • Ineffective collision: wrong orientation OR insufficient energy → no reaction
Factors affecting reaction rate
  • Temperature ↑: particles move faster → more frequent AND higher-energy collisions
  • Concentration ↑ (or pressure ↑ for gases): more particles per volume → more frequent collisions
  • Surface area ↑ (grinding/crushing): more exposed particles for collisions
  • Catalyst: provides alternate lower-Ea pathway → more collisions succeed (does NOT change ΔH)
  • Nature of reactants: ionic reactions in solution are faster than molecular reactions
Physical vs chemical equilibrium
Both involve a balance of opposing processes in a closed system. Exams test both.
  • Physical equilibrium: balance between opposing physical processes — no chemical reaction occurring
  • Example: sealed flask with liquid water → evaporation rate = condensation rate → liquid-vapor equilibrium
  • Evidence of physical equilibrium: liquid level stays constant in a sealed container; no net change observed
  • Chemical equilibrium: balance between forward and reverse chemical reactions at equal rates
  • Both types: occur in CLOSED systems, appear static but are dynamic, concentrations/amounts stay constant
Reading concentration vs. time graphs
A concentration-vs-time graph shows equilibrium when the lines become FLAT and stop changing.
  • Before equilibrium: concentrations changing (reactants decreasing, products increasing, or vice versa)
  • At equilibrium: ALL concentration lines become horizontal (flat) — no further net change
  • The time at which lines flatten = the time equilibrium is reached
  • After equilibrium: concentrations remain constant (flat lines) unless a stress is applied
  • Key: look for where the curves level off and stay flat — that is when equilibrium is established
Chemical equilibrium
A dynamic equilibrium: both forward and reverse reactions occur simultaneously at EQUAL rates.
  • Forward rate = reverse rate at equilibrium
  • Concentrations remain CONSTANT (not necessarily equal to each other)
  • Requires a CLOSED system (nothing enters or leaves)
  • Equilibrium does NOT mean the reaction stopped — both directions still occurring
  • Keq = [products]^coefficients / [reactants]^coefficients (pure solids/liquids excluded)
Le Chatelier's Principle
A system at equilibrium, when stressed, will shift to RELIEVE that stress. Treat heat as a reactant (endo) or product (exo).
  • Add reactant → shifts RIGHT (toward products)
  • Remove reactant → shifts LEFT (toward reactants)
  • Add product → shifts LEFT | Remove product → shifts RIGHT
  • Exothermic + add heat → heat is a product → shifts LEFT
  • Endothermic + add heat → heat is a reactant → shifts RIGHT
  • ↑ Pressure (gas) → shifts toward side with FEWER moles of gas
  • ↓ Pressure → shifts toward MORE moles of gas
  • Catalyst → does NOT shift equilibrium, only reaches it FASTER
  • Inert gas added at constant volume → NO shift (doesn't affect partial pressures of reactants/products)
Equilibrium means RATES are equal, not CONCENTRATIONS.
Catalyst speeds both directions equally — does NOT shift equilibrium position.
Pressure changes only affect GAS-phase equilibria.
Inert gas added at constant volume has NO effect on equilibrium.
A catalyst does NOT appear in the equilibrium constant expression.
Keq = [C]^c[D]^d / [A]^a[B]^b
Le Chatelier: treat heat as substance; exo: product; endo: reactant
Diagram
A + B ⇌ C + D + heat (exothermic) Shift RIGHT if: + more A or B − remove C or D ↓ temperature Shift LEFT if: + more C or D − remove A or B ↑ temperature

Le Chatelier stresses: adding reactant → shift right; adding product → shift left; ↑T for exo → shift left; ↑P → shift toward fewer gas moles.

Acid-base theories
Arrhenius is the most restrictive (water only). Brønsted-Lowry is broader (non-aqueous too).
  • Arrhenius acid: releases H⁺ (H₃O⁺) in aqueous solution (HCl, HNO₃, H₂SO₄, HF)
  • Arrhenius base: releases OH⁻ in aqueous solution (NaOH, KOH, Ca(OH)₂)
  • Brønsted-Lowry acid: proton (H⁺) DONOR
  • Brønsted-Lowry base: proton (H⁺) ACCEPTOR
  • Conjugate acid-base pair: differ by one H⁺ (HCl / Cl⁻; NH₄⁺ / NH₃; H₂O / OH⁻)
  • Amphoteric substances: can act as BOTH acid and base — water (H₂O), bicarbonate (HCO₃⁻)
Properties & identification
  • Acids: sour taste; turn blue litmus RED; pH < 7; react with metals → H₂ gas; react with bases
  • Bases: bitter taste, slippery feel; turn red litmus BLUE; pH > 7; react with acids
  • Strong acids (100% ionized in water): HCl, HBr, HI, HNO₃, H₂SO₄, HClO₄ (memorize these 6)
  • Strong bases: NaOH, KOH, Ca(OH)₂, Ba(OH)₂, LiOH
  • Weak acids/bases: partially ionize — reach equilibrium (HF, CH₃COOH/acetic acid, NH₃)
  • Strength = % ionization; concentration = mol/L (a dilute strong acid is still 100% ionized)
pH scale & calculations
pH scale runs 0–14 at 25°C. Logarithmic — each unit = 10× change in [H⁺].
  • pH = −log[H⁺] → [H⁺] = 10^(−pH)
  • pOH = −log[OH⁻] → [OH⁻] = 10^(−pOH)
  • pH + pOH = 14 (at 25°C)
  • Kw = [H⁺][OH⁻] = 1×10⁻¹⁴ (at 25°C)
  • pH < 7 = acidic; pH = 7 = neutral; pH > 7 = basic
  • How much more acidic: pH 3 vs pH 5 → difference of 2 → 10² = 100× more acidic
Neutralization & titration
Acid + Base → Salt + Water. In a titration, a solution of known concentration (titrant) is added to determine unknown concentration.
  • Equivalence point: moles H⁺ = moles OH⁻ (complete neutralization)
  • Indicator selection: choose an indicator whose range brackets the equivalence point pH
  • Titration formula (1:1 molar ratio): M_A × V_A = M_B × V_B
  • Salt formed = cation from base + anion from acid
  • Example: HCl + NaOH → NaCl + H₂O
  • Indicators from Table M: phenolphthalein (colorless→pink at pH 8.2–10); litmus (red→blue at 4.5–8.3)
Strength ≠ concentration — a dilute HCl solution is still a strong acid (100% ionized).
pH scale is LOGARITHMIC — a pH difference of 2 = 100× concentration difference, not 2×.
Titration formula only works for 1:1 molar ratios; adjust for H₂SO₄ (2 H⁺) etc.
Conjugate pairs differ by exactly one H⁺.
pH = −log[H⁺]
pH + pOH = 14
[H⁺][OH⁻] = 1×10⁻¹⁴
M_A × V_A = M_B × V_B (1:1 ratio)
ppm = (mass solute/mass solution) × 10⁶
Oxidation & reduction
OIL RIG: Oxidation Is Loss (of electrons), Reduction Is Gain (of electrons). They always occur together.
  • Oxidation: loss of electrons → oxidation number INCREASES → species becomes more positive
  • Reduction: gain of electrons → oxidation number DECREASES → species becomes more negative
  • Oxidizing agent: accepts electrons (gets REDUCED itself) — causes oxidation of the other
  • Reducing agent: donates electrons (gets OXIDIZED itself) — causes reduction of the other
  • LEO the lion says GER: Loses Electrons Oxidation | Gains Electrons Reduction
Oxidation number rules
Follow in priority order:
  • Rule 1: Free elements = 0 (Na, O₂, Fe, Cl₂)
  • Rule 2: Monatomic ions = ion charge (Na⁺ = +1, O²⁻ = −2)
  • Rule 3: Group 1 in compounds = +1 always
  • Rule 4: Group 2 in compounds = +2 always
  • Rule 5: F in compounds = −1 always (most electronegative)
  • Rule 6: H = +1 usually; −1 in metal hydrides (NaH, CaH₂)
  • Rule 7: O = −2 usually; −1 in peroxides (H₂O₂, Na₂O₂)
  • Rule 8: Sum of oxidation numbers = 0 for neutral compound; = ion charge for polyatomic ion
Half-reactions & balancing
Split redox into oxidation half-reaction and reduction half-reaction. Balance electrons gained = electrons lost.
  • Write the two half-reactions separately
  • Balance atoms (add H⁺ or H₂O if needed for acidic; OH⁻ and H₂O for basic)
  • Balance charge by adding electrons (e⁻)
  • Multiply each half-reaction so e⁻ lost = e⁻ gained (LCM of electrons)
  • Add the two half-reactions; cancel spectators and electrons that appear on both sides
Electrochemical cells
  • Voltaic (galvanic) cell: SPONTANEOUS redox reaction → converts chemical energy to electrical energy (batteries)
  • Anode = oxidation (both start with vowels) — in voltaic cell: NEGATIVE terminal
  • Cathode = reduction (both start with consonants... remember RED-CAT) — in voltaic cell: POSITIVE terminal
  • Electrons flow: anode → external wire → cathode
  • Salt bridge: allows ion flow to maintain electrical neutrality of each half-cell
  • Electrolytic cell: NONSPONTANEOUS reaction driven by external power source — electroplating, electrolysis of water
  • In electrolytic cell: anode = POSITIVE terminal, cathode = NEGATIVE (signs FLIP from voltaic)
  • Oxidation is ALWAYS at the anode; reduction ALWAYS at the cathode (regardless of cell type)
Anode signs flip between voltaic and electrolytic cells — but oxidation is ALWAYS at the anode.
Reducing agent is the species that gets oxidized (it reduces something else by giving up electrons).
In oxidation, the oxidation number INCREASES (more positive).
Electrons flow through the wire from anode to cathode — ions flow through the salt bridge.
e⁻ lost by reducing agent = e⁻ gained by oxidizing agent
Table J activity series: higher = more active = more easily oxidized
Diagram
V salt bridge ANODE (−) CATHODE (+) e⁻ → oxidation reduction

Voltaic cell: anode (−) = oxidation; cathode (+) = reduction. Electrons flow anode→cathode via wire; ions flow through salt bridge.

Types of radiation
  • Alpha (α, ⁴₂He): helium nucleus; charge +2; mass 4 amu; LOW penetrating power (stopped by paper/skin); mass −4, atomic # −2
  • Beta (β⁻, ⁰₋₁e): high-speed electron; charge −1; mass ≈0; moderate penetrating power (stopped by aluminum); mass unchanged, atomic # +1
  • Gamma (γ, ⁰₀γ): high-energy photon; no charge, no mass; HIGHEST penetrating power (needs lead/concrete); no change to mass or atomic #
  • Positron (β⁺, ⁰₊₁e): antimatter electron; charge +1; mass ≈0; mass unchanged, atomic # −1
  • Neutron emission: ¹₀n released; mass −1, atomic # unchanged (rare but possible)
Nuclear equations & conservation
In ANY nuclear equation, BOTH must be conserved:
  • Mass number conservation: sum of superscripts (top) equal on both sides
  • Atomic number conservation: sum of subscripts (bottom) equal on both sides
  • Strategy: find the missing particle by subtraction
  • Example: ²³⁸₉₂U → ⁴₂He + ²³⁴₉₀Th (alpha decay: mass 238−4=234; atomic# 92−2=90)
  • Example: ¹⁴₆C → ⁰₋₁e + ¹⁴₇N (beta decay: mass 14−0=14; atomic# 6+1=7)
  • Transmutation: one element changing into another through nuclear decay or bombardment
Half-life calculations
Half-life (t₁/₂) = time for exactly half the sample to decay. It is CONSTANT and independent of temperature, pressure, or chemical state.
  • Amount remaining = original × (½)^(t/t₁/₂) = original × (½)^(number of half-lives)
  • Number of half-lives = total time ÷ t₁/₂
  • Each half-life: 100%→50%→25%→12.5%→6.25%→3.125%
  • Table N lists radioisotopes, their half-lives, decay modes, and uses
  • Half-life is NOT affected by temperature, pressure, or the chemical form of the element
Fission, fusion & applications
  • Fission: splitting a HEAVY nucleus into smaller ones + neutrons + energy (U-235, Pu-239 in reactors)
  • Chain reaction: neutrons from one fission trigger more fissions — controlled in reactors, uncontrolled in bombs
  • Fusion: combining LIGHT nuclei into heavier one + energy (H + H → He in the sun); requires extreme T and P
  • Fusion releases MORE energy per gram than fission
  • Nuclear energy comes from mass-energy conversion: E = mc² (small mass loss = huge energy)
  • Medical uses (Table N): I-131 (thyroid treatment/imaging), Tc-99m (diagnostic imaging), Co-60 (cancer radiation)
  • C-14 (t₁/₂ = 5715 yr): carbon dating of organic material; U-238 (t₁/₂ = 4.5×10⁹ yr): geological dating
Both mass numbers AND atomic numbers must balance in nuclear equations — check BOTH.
Half-life is constant regardless of temperature, pressure, or chemical state.
Alpha has LOWEST penetrating power; gamma has HIGHEST.
Fusion powers the sun; fission powers nuclear reactors.
In beta decay: atomic # goes UP by 1 (neutron→proton); in positron emission: atomic # goes DOWN by 1.
Amount remaining = initial × (½)^(t/t₁/₂)
Alpha: mass −4, atomic# −2 | Beta: mass 0, atomic# +1 | Gamma: no change | Positron: mass 0, atomic# −1
Diagram
Penetrating Power Alpha (α): stopped by PAPER — low penetration, high ionization Beta (β): stopped by ALUMINUM sheet — medium penetration Gamma (γ): needs LEAD or CONCRETE — highest penetrating power Ionization power (opposite): α > β > γ

Radioactive decay types: alpha loses ⁴₂He (mass−4, Z−2); beta emits e⁻ (Z+1); gamma emits photon (no change); penetrating power: γ > β > α.

What makes a compound organic
Organic compounds contain carbon. Carbon is unique because it forms 4 covalent bonds and can bond to itself in long chains and rings.
  • All organic compounds contain carbon (and usually hydrogen)
  • Carbon always forms 4 covalent bonds — never more, never less
  • The backbone of organic molecules is a chain or ring of carbon-carbon bonds
  • Organic chemistry is the chemistry of carbon-containing compounds
  • Exceptions that are NOT considered organic: CO, CO₂, carbonates (CO₃²⁻), cyanides (CN⁻)
Homologous series & naming prefixes (Table Q)
A homologous series is a family of organic compounds with the same general formula, differing by one CH₂ unit. Each member has similar chemical properties.
  • Prefix meth- = 1 carbon | eth- = 2 | prop- = 3 | but- = 4 | pent- = 5 | hex- = 6 | hept- = 7 | oct- = 8
  • Alkanes (CₙH₂ₙ₊₂): single bonds only; -ane suffix (methane, ethane, propane...)
  • Alkenes (CₙH₂ₙ): one double bond; -ene suffix (ethene, propene, butene...)
  • Alkynes (CₙH₂ₙ₋₂): one triple bond; -yne suffix (ethyne = acetylene)
  • Cycloalkanes (CₙH₂ₙ): carbon ring with all single bonds
  • Each successive member differs by one CH₂ unit (14 g/mol higher molar mass)
Functional groups (Table P)
A functional group is an atom or group of atoms that determines the chemical properties of an organic compound.
  • Alcohol (−OH): R−OH; suffix -ol; e.g., ethanol (CH₃CH₂OH). Formed by: fermentation, substitution of halogen.
  • Aldehyde (−CHO): R−CHO; suffix -al; e.g., methanal (formaldehyde). Contains C=O at end of chain.
  • Ketone (C=O in chain): R−CO−R; suffix -one; e.g., propanone (acetone).
  • Carboxylic acid (−COOH): R−COOH; suffix -oic acid; e.g., methanoic acid (formic), ethanoic acid (acetic).
  • Ester (−COO−): R−COO−R'; suffix -anoate; e.g., ethyl ethanoate. Formed from acid + alcohol.
  • Ether (−O−): R−O−R'; e.g., diethyl ether.
  • Amine (−NH₂): R−NH₂; e.g., methylamine. Weak bases.
  • Amide (−CONH₂): R−CONH₂; found in proteins and nylon.
  • Halide: one or more H replaced by halogen (F, Cl, Br, I)
Organic reactions (Table R)
  • Fermentation: C₆H₁₂O₆ → 2C₂H₅OH + 2CO₂ (glucose → ethanol + CO₂; yeast catalyst; no O₂ — anaerobic)
  • Esterification: carboxylic acid + alcohol → ester + water (R−COOH + HO−R' → R−COO−R' + H₂O)
  • Saponification: ester + base (NaOH) → soap (salt of fatty acid) + alcohol
  • Substitution: one atom replaces another; e.g., alkane + Cl₂ → chloroalkane + HCl
  • Addition: atoms added across a double or triple bond; alkene + H₂ → alkane (hydrogenation)
  • Combustion: CₓHᵧ + O₂ → CO₂ + H₂O + energy
  • Polymerization: many monomers join → polymer; e.g., ethene → polyethylene; nylon, proteins, DNA
Isomers
Isomers have the SAME molecular formula but DIFFERENT structural formulas — the atoms are connected differently.
  • Same: molecular formula (same # of each atom), molar mass
  • Different: structural formula (arrangement), physical properties (BP, MP), sometimes chemical properties
  • Example: C₄H₁₀ → butane (straight chain) and 2-methylpropane (branched) are isomers
  • Example: propanoic acid (CH₃CH₂COOH) and ethyl methanoate (HCOOCH₂CH₃) are isomers — both C₃H₆O₂
  • To identify: count atoms in each formula; if totals match, they are isomers
Organic naming rules
Use Table Q for prefixes. Name the longest continuous carbon chain, then number from the end closest to a branch.
  • Step 1: Find the longest continuous C chain → gives base name (hex = 6 carbons)
  • Step 2: Number from end closest to branches/substituents (gives them lowest numbers)
  • Step 3: Name substituents with number: 2-methyl (CH₃ on C2), 3-ethyl, etc.
  • Multiple substituents: alphabetical order (ethyl before methyl); di/tri if same substituent twice
  • Example: 3-methylhexane = 6-carbon chain with a CH₃ branch on carbon 3
  • Example: 2,3-dimethylpentane = 5-carbon chain with CH₃ on C2 and C3
CₙH₂ₙ is ALKENES (one double bond) — not alkanes (CₙH₂ₙ₊₂).
Fermentation produces ETHANOL (alcohol), not just any product.
Esterification = acid + alcohol → ester + WATER (not H₂).
Isomers have the SAME molecular formula but different structural formulas.
Carbon is always in organic compounds — but CO and CO₂ are NOT organic.
When naming: pick the LONGEST chain, then number from end closest to the branch.
Alkanes: CₙH₂ₙ₊₂ | Alkenes: CₙH₂ₙ | Alkynes: CₙH₂ₙ₋₂
Fermentation: C₆H₁₂O₆ → 2C₂H₅OH + 2CO₂
Esterification: acid + alcohol → ester + H₂O
Practice Question Bank — 469 questions
Unit 1: Matter & Change (26)
  1. Which sample is a pure substance?

    • Nitrogen gas (N₂)
    • Salt water
    • Air
    • Granite

    N₂ is a pure substance (element). Salt water, air, and granite are mixtures.

  2. Which separation technique separates two liquids with different boiling points?

    • Filtration
    • Distillation
    • Magnetism
    • Chromatography

    Distillation separates based on different boiling points.

  3. Dissolving salt in water is best classified as a physical change because the

    • salt reacts with water to form a new substance
    • process releases a large amount of heat
    • original substance can be recovered by evaporation
    • chemical composition of the salt changes

    Dissolving is physical — NaCl is still NaCl. Evaporate the water and the salt is recovered unchanged.

  4. Which is a chemical change?

    • Ice melting
    • Sugar dissolving in water
    • Aluminum foil being cut
    • Iron rusting

    Rusting is a chemical change (Fe + O₂ → Fe₂O₃). A new substance with new properties forms.

  5. Which statement correctly describes the property of density?

    • It is intensive because it does not depend on sample size
    • It is extensive because it depends on sample size
    • It is a chemical property because it involves reactions
    • It changes when the sample is divided in half

    Density is an intensive property — a small gold ring and a large gold bar have the same density.

  6. Which is an extensive property?

    • Density
    • Mass
    • Melting point
    • Color

    Mass depends on the amount of substance present → extensive.

  7. Heterogeneous mixtures can be identified because they:

    • Have fixed composition
    • Look uniform throughout
    • Have visible different components
    • Cannot be separated

    Heterogeneous mixtures have visibly different parts (e.g., salad, granite).

  8. Which process separates ink pigments by polarity?

    • Distillation
    • Filtration
    • Magnetism
    • Chromatography

    Chromatography separates substances based on their polarity/affinity for the stationary phase.

  9. Which is a physical property?

    • Boiling point
    • Flammability
    • Reactivity with acid
    • Ability to corrode

    Boiling point is observable without changing the substance's identity.

  10. A compound differs from a mixture because a compound:

    • Can be separated physically
    • Has components bonded in fixed ratios
    • Has variable composition
    • Contains only one element

    Compounds have fixed ratios of elements, chemically bonded. Mixtures have variable composition.

  11. Which substance is an example of a homogeneous mixture?

    • Sand and water
    • Oil and water
    • Brass (copper + zinc)
    • Granite

    Brass is a homogeneous mixture (alloy) — uniform throughout at the macroscopic level.

  12. What evidence indicates a chemical change occurred?

    • Ice melting
    • Salt dissolving
    • Water boiling
    • A gas being produced

    Gas production indicates new substances formed → chemical change.

  13. Filtration is used to separate:

    • An insoluble solid from a liquid
    • Two miscible liquids
    • A dissolved solid from solution
    • Two gases

    Filtration separates insoluble solids (like sand) from liquid (like water).

  14. Which is a chemical property?

    • Conductivity
    • Flammability
    • Density
    • Melting point

    Flammability describes HOW a substance reacts (combustion) → chemical property.

  15. The Tyndall effect (light scattering) is characteristic of a:

    • True solution
    • Element
    • Colloid
    • Compound

    Colloids scatter light (Tyndall effect); true solutions do not.

  16. Which change requires breaking chemical bonds?

    • Melting wax
    • Crushing a rock
    • Dissolving sugar
    • Burning wood

    Burning involves breaking C-H bonds and forming new bonds (CO₂, H₂O) → chemical change.

  17. A pure substance can be classified as either:

    • Element or compound
    • Homogeneous or heterogeneous
    • Mixture or solution
    • Solid or liquid

    Pure substances are either elements (one atom type) or compounds (chemically bonded elements).

  18. Centrifugation separates components based on differences in:

    • Boiling point
    • Density
    • Polarity
    • Magnetic properties

    Centrifugation uses centrifugal force to separate by density differences.

  19. Which substance cannot be broken down by chemical means?

    • Water
    • Salt (NaCl)
    • Carbon (C)
    • Ammonia (NH₃)

    Carbon is an element — cannot be broken down chemically into simpler substances.

  20. Color change during a reaction most likely indicates:

    • A physical change
    • A mixture was formed
    • The density changed
    • A chemical change occurred

    Color change (new substance forming) is a sign of a chemical change.

  21. O₂ and O₃ are both forms of the element oxygen. These two substances have:

    • Different molecular structures, different properties
    • Same molecular structures, same properties
    • Same molecular structures, different properties
    • Different molecular structures, same properties

    O₂ and O₃ are allotropes — same element, but different molecular structures → different chemical and physical properties.

  22. Which phrase best describes a compound?

    • A mixture with variable proportions
    • Two or more elements chemically combined in fixed ratios
    • A mixture with fixed proportions
    • Two or more elements physically combined

    A compound is two or more elements chemically combined in fixed ratios. It can only be separated by chemical means.

  23. When a molecule of H₂ and a molecule of I₂ collide with proper orientation and sufficient energy, the most likely result is

    • a physical change because an element forms
    • a chemical change because an element forms
    • a chemical change because a compound forms
    • a physical change because a compound forms

    H₂ + I₂ → 2HI: a new compound (HI) forms. New substance with different properties = chemical change.

  24. A mixture of crystals of salt and sugar is dissolved in water. Which statement best describes the resulting mixture?

    • Heterogeneous and cannot be separated by filtration
    • Homogeneous and can be separated by filtration
    • Heterogeneous and can be separated by filtration
    • Homogeneous and cannot be separated by filtration

    The resulting solution is homogeneous (uniform throughout). Since both solids dissolved, filtration would not separate them — both pass through filter paper.

  25. Distillation of crude oil from various parts of the world yields different percentages of hydrocarbons. Which statement explains this?

    • The proportions of components in a mixture can vary
    • Each component in a mixture has a different solubility in water
    • Hydrocarbons are organic compounds
    • The carbons in hydrocarbons may be bonded in chains or rings

    Crude oil is a mixture. Mixtures have variable proportions — crude oil composition differs by location.

  26. When a mixture of water, sand, and salt is filtered, what passes through the filter paper?

    • Water and sand only
    • Water and salt only
    • Water, sand, and salt
    • Water only

    Sand is insoluble and is caught by the filter. Salt and water (solution) pass through. Answer: water and dissolved salt.

Unit 2: Measurements & Math (24)
  1. How many significant figures are in 0.00240?

    • 2
    • 5
    • 3
    • 6

    Leading zeros are never sig figs. Trailing zero after decimal IS significant. 2, 4, 0 → 3 sig figs.

  2. How many sig figs in 1500.?

    • 2
    • 3
    • 5
    • 4

    The decimal point makes all trailing zeros significant: 1, 5, 0, 0 = 4 sig figs.

  3. A measurement of 12.5 + 3.45 should be reported as:

    • 16.0
    • 15.95
    • 15.9
    • 16

    Add/subtract: round to fewest decimal places. 12.5 has 1 decimal → answer = 16.0.

  4. 2.5 × 3.45 = ? (correct sig figs)

    • 8.625
    • 8.6
    • 8.63
    • 9

    Multiply: fewest sig figs is 2 (in 2.5) → 8.6.

  5. A student measures 9.8 g; accepted value is 10.0 g. % error is:

    • 0.2%
    • 20%
    • 2%
    • 1.96%

    |9.8−10.0|/10.0 × 100 = 0.2/10.0 × 100 = 2%.

  6. How many moles are in 36.0 g of water (H₂O, GFM=18.0)?

    • 0.50 mol
    • 1.0 mol
    • 18.0 mol
    • 2.0 mol

    n = m/GFM = 36.0/18.0 = 2.0 mol.

  7. How many particles are in 2.0 mol of CO₂?

    • 1.20×10²⁴
    • 3.01×10²³
    • 6.02×10²³
    • 2.40×10²⁴

    2.0 mol × 6.02×10²³ = 1.20×10²⁴ molecules.

  8. The gram formula mass (GFM) of NaCl (Na=23, Cl=35.5) is:

    • 23 g/mol
    • 58.5 g/mol
    • 35.5 g/mol
    • 69 g/mol

    GFM = 23 + 35.5 = 58.5 g/mol.

  9. Measurements that are close to each other but far from the true value show:

    • High accuracy, low precision
    • Low accuracy, low precision
    • High precision, low accuracy
    • High accuracy, high precision

    Close to each other = precise; far from true = inaccurate. High precision, low accuracy.

  10. 0.000345 in scientific notation is:

    • 3.45×10²
    • 3.45×10⁻³
    • 3.45×10⁻⁵
    • 3.45×10⁻⁴

    Move decimal 4 places right → 3.45×10⁻⁴.

  11. How many grams are in 3.0 mol of NaOH (GFM = 40.0 g/mol)?

    • 120 g
    • 13.3 g
    • 40.0 g
    • 80.0 g

    g = mol × GFM = 3.0 × 40.0 = 120 g.

  12. How many sig figs are in 2005?

    • 2
    • 4
    • 3
    • 5

    Captive zeros (between nonzero digits) are always significant: 2, 0, 0, 5 = 4 sig figs.

  13. % error is always:

    • Negative
    • Zero
    • Positive
    • Variable

    % error uses absolute value — always positive (deviation from accepted value).

  14. How many atoms are in 1 mole of O₂?

    • 6.02×10²³
    • 3.01×10²³
    • 2 atoms
    • 1.20×10²⁴

    1 mol O₂ = 6.02×10²³ molecules. Each has 2 O atoms → 1.20×10²⁴ O atoms.

  15. GFM of Ca(OH)₂ (Ca=40, O=16, H=1) is:

    • 74 g/mol
    • 57 g/mol
    • 56 g/mol
    • 58 g/mol

    40 + 2(16+1) = 40 + 34 = 74 g/mol.

  16. Trailing zeros in 1500 (no decimal) are:

    • Always significant
    • Ambiguous — can't tell without more info
    • Never significant
    • Always 2 sig figs

    Without a decimal, trailing zeros are ambiguous. Scientific notation clarifies: 1.5×10³ (2 s.f.) or 1.500×10³ (4 s.f.).

  17. Which instrument measures the most precise volume?

    • Beaker
    • Graduated cylinder
    • Buret
    • Erlenmeyer flask

    A buret has the smallest gradations and reads to 0.01 mL — most precise.

  18. A student gets 9.5, 9.4, 9.6 g (accepted = 12.0 g). The results are:

    • Accurate and precise
    • Accurate but not precise
    • Neither accurate nor precise
    • PrecisStudye but not accurate

    Results cluster closely (precise) but are far from 12.0 (not accurate).

  19. The number of moles in 6.02×10²³ molecules of glucose is:

    • 1
    • 6.02×10²³
    • 2
    • 0.5

    By definition, 6.02×10²³ particles = 1 mole.

  20. If D = m/V and m = 24 g and V = 8 mL, D equals:

    • 192 g/mL
    • 3.0 g/mL
    • 0.33 g/mL
    • 16 g/mL

    D = 24/8 = 3.0 g/mL.

  21. Which kelvin temperature is equivalent to −24°C?

    • 226 K
    • 273 K
    • 249 K
    • 297 K

    K = °C + 273 = −24 + 273 = 249 K.

  22. Which measurement contains exactly three significant figures?

    • 0.12
    • 012
    • 120
    • 120.

    120. — the decimal point makes all three digits significant (1, 2, 0). Without the decimal, trailing zeros are ambiguous.

  23. A student measures 22.5 g of H₂O in an 8.28 mL sample. What is the density, to the correct number of significant figures?

    • 2.72 g/mL
    • 2.717 g/mL
    • 3 g/mL
    • 2.7 g/mL

    D = m/V = 22.5 g ÷ 8.28 mL = 2.717... g/mL. Both measurements have 3 sig figs, so the answer is rounded to 3 sig figs → 2.72 g/mL.

  24. When 1.255 g of X reacts with 3.2 g of Y, only product Z forms. What is the total mass of Z to the correct number of significant figures?

    • 4.46 g
    • 4.5 g
    • 4.455 g
    • 5 g

    Conservation of mass: 1.255 + 3.2 = 4.455 g. Rounded to fewest decimal places in addition: 3.2 has 1 decimal place → 4.5 g.

Unit 3: Atomic Concepts (29)
  1. The atomic number of an element equals the number of:

    • Neutrons
    • Protons + neutrons
    • Electrons in a neutral atom
    • Neutrons + electrons

    Atomic number = proton count = electron count in a neutral atom.

  2. Two atoms are isotopes if they have the same:

    • Mass number
    • Number of neutrons
    • Electron configuration
    • Number of protons

    Isotopes have the same atomic number (protons) but different mass numbers (different neutrons).

  3. How many neutrons are in ⁸⁰₃₅Br?

    • 45
    • 35
    • 80
    • 115

    Neutrons = mass number − atomic number = 80 − 35 = 45.

  4. An atom in the excited state has:

    • More electrons than normal
    • Electrons in higher energy levels than ground state
    • Fewer electrons than normal
    • Electrons only in the lowest levels

    Excited = one or more electrons at higher energy level than ground state. Total count same.

  5. Rutherford's gold foil experiment showed that:

    • Electrons are in fixed orbits
    • Atoms are solid spheres
    • Atoms are mostly empty space with a dense nucleus
    • Electrons have wave properties

    Most alpha particles passed through → atoms are mostly empty space; few deflected → small dense positive nucleus.

  6. The atomic mass of an element is a:

    • Whole number equal to protons
    • Whole number equal to protons + neutrons
    • The mass of the most common isotope
    • Weighted average of isotope masses × abundances

    Atomic mass = weighted average based on relative abundance of all naturally occurring isotopes.

  7. Chlorine-35 has 17 protons. How many neutrons?

    • 18
    • 17
    • 35
    • 52

    Neutrons = 35 − 17 = 18.

  8. The current atomic model describes electrons as:

    • Particles in fixed circular orbits
    • Waves in probability clouds (orbitals)
    • Embedded in a positive sphere
    • Stationary charges

    The wave-mechanical model: electrons exist in orbitals — regions of probability, not fixed paths.

  9. In a bright-line spectrum, each line represents:

    • An electron being removed
    • A proton being emitted
    • An electron transitioning to a lower energy level
    • An electron added to the atom

    When an excited electron falls to a lower energy level, it emits a photon of specific wavelength → bright line.

  10. The fill order 1s 2s 2p 3s 3p 4s 3d 4p shows that 4s fills:

    • After 3d
    • Before 3s
    • At the same time as 3d
    • Before 3d

    4s has lower energy than 3d during filling → 4s fills BEFORE 3d.

  11. Which subshell holds a maximum of 6 electrons?

    • p
    • s
    • d
    • f

    p sublevel has 3 orbitals × 2 electrons each = 6 max.

  12. Thomson's plum pudding model was replaced because:

    • It couldn't explain chemical bonding
    • Rutherford's gold foil showed most mass is in a small nucleus
    • Electrons don't exist
    • Atoms are too large

    Rutherford proved the nuclear model — most mass/charge concentrated in a tiny nucleus, not spread throughout.

  13. An ion of Na has 11 protons and 10 electrons. Its charge is:

    • 0
    • -1
    • +1
    • +2

    11 protons (+ charges) − 10 electrons (− charges) = net +1 → Na⁺.

  14. Which has the highest energy per photon in the visible spectrum?

    • Red light
    • Green light
    • Yellow light
    • Violet light

    ROYGBIV: violet is highest frequency → shortest wavelength → most energy per photon.

  15. Carbon-12 and Carbon-14 are isotopes. They differ in:

    • Number of neutrons
    • Number of protons
    • Chemical properties
    • Electron configuration

    Same protons (6) → same element; different mass numbers (12 vs 14) → different neutron counts.

  16. What is the maximum number of electrons that can occupy the d sublevel?

    • 2
    • 10
    • 6
    • 14

    The d sublevel: 5 orbitals × 2 electrons = 10 max.

  17. Electron configuration 1s²2s²2p⁶3s²3p³ describes which element?

    • N (nitrogen)
    • As (arsenic)
    • P (phosphorus)
    • Si (silicon)

    Count electrons: 2+2+6+2+3 = 15 electrons → element #15 = Phosphorus (P).

  18. In the EM spectrum, which has the shortest wavelength?

    • Radio waves
    • Microwaves
    • Visible light
    • Gamma rays

    Gamma rays have the highest frequency and shortest wavelength → most energy.

  19. An atom's electron configuration is 1s²2s²2p⁶3s²3p⁶4s²3d¹⁰4p⁶5s¹. This atom most likely is:

    • Rubidium
    • Potassium
    • Cesium
    • Sodium

    Count electrons: 2+2+6+2+6+2+10+6+1 = 37 electrons → element 37 = Rubidium (Rb).

  20. Dalton's atomic model depicted atoms as:

    • Having a dense nucleus
    • Indivisible solid spheres
    • Planetary-like with orbiting electrons
    • Probability clouds

    Dalton (1803): atoms are solid, indivisible spheres — no internal structure.

  21. Which conclusion resulted directly from the gold foil experiment?

    • Atoms are hard, indivisible spheres
    • Electrons are negatively charged
    • Atoms contain a small, dense, positive nucleus
    • Electrons occupy shells with different energies

    Rutherford's gold foil experiment: most α particles passed through → mostly empty space; few deflected → small, dense, positive nucleus.

  22. An atom has 37 protons and 49 neutrons. How many electrons does it have in the neutral state?

    • 12
    • 49
    • 86
    • 37

    Neutral atom: electrons = protons = 37.

  23. In the wave-mechanical model, electrons are found in regions called:

    • Orbitals
    • Spectra
    • Quanta
    • Nuclei

    Wave-mechanical model: electrons exist in orbitals — regions of probability, not fixed paths.

  24. Which electron configuration represents a lithium atom in the excited state?

    • 2-1
    • 1-1-1
    • 2-2
    • 1-2-1

    Ground state Li: 2-1 (shells 1 and 2). Excited state: an electron jumped to a higher shell. 1-2-1 has 4 electrons — wrong count. 2-2 has 4 electrons — wrong. 1-1-1 has 3 electrons and an electron in the 3rd shell → excited state for Li (3 electrons, but in higher-than-ground arrangement). Answer: 1-1-1.

  25. In the ground state, ions of which two elements each have the same electron configuration as neon?

    • Lithium and fluorine
    • Sodium and chlorine
    • Magnesium and oxygen
    • Calcium and sulfur

    Ne has 10 electrons. Mg²⁺ loses 2 electrons (12−2=10); O²⁻ gains 2 electrons (8+2=10). Both are isoelectronic with Ne.

  26. Which electron configuration represents a sulfur atom in an excited state? (Sulfur ground state: 2-8-6)

    • 2-8-7
    • 2-8-6
    • 2-7-8
    • 2-7-7

    S has 16 electrons. Ground state = 2-8-6. An excited state has the same 16 electrons in a non-ground arrangement. 2-7-7 = 2+7+7 = 16 electrons, but an electron jumped from shell 3 to shell 2 → excited state.

  27. An orbital is best described as a region in an atom where there is a high probability of finding

    • an electron
    • a positron
    • an alpha particle
    • a neutron

    An orbital is a region of probability for finding an electron. It is NOT a fixed circular path.

  28. Most alpha particles directed at the gold foil in Rutherford's experiment passed through because

    • the foil was too thin
    • most of each atom is empty space
    • alpha particles have no charge
    • gold atoms are very small

    Rutherford concluded that atoms are mostly empty space — which is why most alpha particles passed straight through without deflection.

  29. Which particles are found in the nucleus of an argon atom?

    • Protons and electrons
    • Positrons and neutrons
    • Protons and neutrons
    • Positrons and electrons

    The nucleus contains only protons and neutrons. Electrons are found in orbitals outside the nucleus.

Unit 4: Periodic Table (26)
  1. Across a period from left to right, atomic radius:

    • Increases
    • Stays the same
    • First increases then decreases
    • Decreases

    More protons across a period pull electrons closer → decreasing atomic radius.

  2. Which element has the highest electronegativity?

    • Fluorine
    • Oxygen
    • Chlorine
    • Cesium

    Fluorine has EN = 4.0 — highest of all elements. Located top-right of the periodic table.

  3. Down a group, ionization energy:

    • Increases
    • Decreases
    • Stays the same
    • Doubles

    Down a group: more electron shells = greater shielding = outer electrons held less tightly → lower IE.

  4. Group 17 elements are called:

    • Alkali metals
    • Noble gases
    • Halogens
    • Alkaline earth metals

    Group 17 = halogens: F, Cl, Br, I, At. 7 valence electrons. Form −1 ions.

  5. Which group contains elements that are completely nonreactive?

    • Group 1
    • Group 2
    • Group 17
    • Group 18

    Group 18 = noble gases: full valence shells → chemically inert (He, Ne, Ar, Kr, Xe, Rn).

  6. Compared to a sodium atom, a sodium ion (Na⁺) has a

    • smaller radius because fewer electrons are pulled by the same nuclear charge
    • larger radius because it gained electrons
    • larger radius because it gained a proton
    • smaller radius because it lost a proton

    Na⁺ lost 1 electron. The same 11 protons now pull 10 electrons more tightly → smaller radius.

  7. Metalloids are located along:

    • The left side of the periodic table
    • The staircase line separating metals and nonmetals
    • The bottom row
    • The top row

    Metalloids (B, Si, Ge, As, Sb, Te) run along the staircase/zigzag line on the right side.

  8. Which best explains why atomic radius decreases across a period?

    • More electron shells are added
    • Electrons are lost
    • More protons create stronger nuclear attraction on the same shell
    • Fewer neutrons

    Across a period: adding protons increases nuclear charge pulling all electrons in the same shell closer.

  9. The trend in metallic character going down a group is:

    • Decreasing
    • Constant
    • Zigzag
    • Increasing

    Down a group: electrons farther from nucleus, easier to lose → increased metallic character.

  10. Which element is a metalloid?

    • Silicon (Si)
    • Sodium (Na)
    • Sulfur (S)
    • Selenium (Se)

    Silicon (Si) is a metalloid — along the staircase. Used in semiconductors.

  11. Elements in the same group have similar chemical properties because they have:

    • Same number of protons
    • Same number of valence electrons
    • Same atomic mass
    • Same number of neutrons

    Same group = same number of valence electrons → similar reactivity and bonding.

  12. Chlorine (Cl) most commonly forms which ion?

    • Cl⁺
    • Cl²⁻
    • Cl⁻
    • Cl²⁺

    Cl has 7 valence electrons → gains 1 to complete octet → forms Cl⁻.

  13. Which property increases across a period (left to right)?

    • Atomic radius
    • Metallic character
    • Number of electron shells
    • Ionization energy

    Ionization energy increases left to right (more protons hold outer electrons more tightly).

  14. Compared to a chlorine atom, a chloride ion (Cl⁻) has a

    • larger radius because the same nuclear charge now acts on more electrons
    • smaller radius because it lost an electron
    • smaller radius because it gained a proton
    • larger radius because it gained a proton

    Cl⁻ gained 1 electron. The same 17 protons now attract 18 electrons → larger atomic radius.

  15. The Coulomb's Law force between nucleus and electrons decreases when:

    • Atomic number increases
    • Distance increases (more electron shells)
    • Electrons are removed
    • Temperature increases

    F ∝ 1/r² — as distance (shells) increases, the nuclear pull on outer electrons decreases.

  16. Which is a property of metals?

    • Poor conductor of electricity
    • Brittle solid
    • Malleable and ductile
    • Gains electrons to form anions

    Metals are malleable (can be hammered), ductile (can be drawn into wire), and good conductors.

  17. Alkali metals (Group 1) react vigorously with water to form:

    • Acids
    • Metal oxides only
    • No reaction
    • Metal hydroxide + H₂ gas

    2Na + 2H₂O → 2NaOH + H₂↑. Alkali metals react violently with water.

  18. Transition metals are in Groups:

    • 3–12
    • 1 and 2
    • 13–18
    • 17 and 18

    Transition metals occupy the d-block, Groups 3–12.

  19. Na⁺, Mg²⁺, and F⁻ are isoelectronic. This means they:

    • Are in the same period
    • Have the same number of electrons (10)
    • Have the same mass
    • React identically

    All three have 10 electrons and the configuration 1s²2s²2p⁶ (same as Ne).

  20. Which best predicts the charge of an aluminum (Al, Group 13) ion?

    • Al⁻
    • Al²⁺
    • Al³⁺
    • Al⁴⁺

    Al has 3 valence electrons → loses all 3 → Al³⁺.

  21. At STP, a sample of potassium can be differentiated from rubidium based on:

    • Phase
    • Temperature
    • Pressure
    • Density

    Both K and Rb are solid metals at STP (same phase). Density is an intensive physical property that differs between the two and can be measured to tell them apart.

  22. What is the chemical name for PdO?

    • Palladium (II) oxide
    • Palladium (IV) oxide
    • Palladium peroxide
    • Palladium hydroxide

    O = −2, so Pd must be +2 for the compound to be neutral. Roman numeral II → palladium(II) oxide.

  23. Which element in the formula X₂O would X most likely be?

    • Cd
    • Cs
    • Cr
    • Ca

    X₂O means 2 X atoms balance 1 oxygen (charge −2) → each X = +1. Group 1 elements have +1 charge. Cs is Group 1.

  24. On the periodic table, the number of protons in an atom of an element is indicated by its

    • atomic mass
    • number of valence electrons
    • atomic number
    • selected oxidation states

    Atomic number = number of protons. This is the fundamental definition of atomic number and element identity.

  25. When an atom loses an electron, the atom's radius and charge both change. Which correctly describes this change?

    • Radius increases, atom becomes positively charged
    • Radius decreases, atom becomes negatively charged
    • Radius increases, atom becomes negatively charged
    • Radius decreases, atom becomes positively charged

    Losing an electron: fewer electrons means same nuclear charge pulls remaining electrons more tightly → smaller radius; net positive charge → cation.

  26. Which element has metallic bonds at room temperature?

    • Cesium
    • Chlorine
    • Sulfur
    • Krypton

    Cesium is a metal → held together by metallic bonding (sea of delocalized electrons). Cl, S are nonmetals; Kr is a noble gas.

Unit 5: Chemical Bonding (28)
  1. Which type of bond forms between sodium and chlorine?

    • Nonpolar covalent
    • Ionic
    • Polar covalent
    • Metallic

    Na (metal) + Cl (nonmetal), ΔEN = 3.0−0.9 = 2.1 ≥ 1.7 → ionic bond.

  2. A bond between two identical atoms (e.g., Cl₂) is:

    • Ionic
    • Polar covalent
    • Nonpolar covalent
    • Metallic

    Identical atoms → same EN → ΔEN = 0 → equal sharing → nonpolar covalent.

  3. In which compound does hydrogen bonding occur?

    • CH₄
    • CCl₄
    • HCl
    • HF

    H-bond requires H bonded directly to F, O, or N. Only HF has H bonded to F.

  4. CO₂ has polar bonds but is a nonpolar molecule because:

    • Linear geometry causes dipoles to cancel
    • The bonds are identical
    • C and O have the same EN
    • It has no lone pairs

    CO₂ is linear and symmetric → two C=O dipoles point in opposite directions → cancel → nonpolar molecule.

  5. An ionic solid (e.g., NaCl) conducts electricity:

    • Always
    • Only when dissolved or melted
    • Only as a solid
    • Never

    Ionic solids: ions are locked in lattice → can't conduct. Dissolved or molten: ions are mobile → conduct.

  6. Which molecule is polar?

    • CO₂ (linear)
    • CH₄ (tetrahedral)
    • NH₃ (trigonal pyramidal)
    • CCl₄ (tetrahedral)

    NH₃ is pyramidal with a lone pair → asymmetric → net dipole → polar molecule.

  7. The 'sea of electrons' model describes:

    • Ionic bonding
    • Covalent bonding
    • Hydrogen bonding
    • Metallic bonding

    Metallic bonding: delocalized valence electrons form a sea surrounding positive metal ion cores.

  8. London dispersion forces are present in which type of substance?

    • ALL molecules
    • Only ionic compounds
    • Only polar molecules
    • Only nonpolar molecules

    LDFs are present in ALL molecules — polar and nonpolar. They're the only force in nonpolar molecules.

  9. The molecular geometry of H₂O is:

    • Linear
    • Bent/V-shaped
    • Trigonal planar
    • Tetrahedral

    H₂O: 2 bonding pairs + 2 lone pairs → bent geometry (~104.5°).

  10. Which bond is the most polar?

    • C-H
    • N-H
    • F-H
    • O-H

    F has EN = 4.0 (highest). H-F has the largest ΔEN → most polar bond among common bonds.

  11. Which property is explained by metallic bonding?

    • High melting point of NaCl
    • Brittleness of ionic crystals
    • Low boiling point of CH₄
    • Electrical conductivity of copper wire

    Metals conduct electricity because of delocalized (free-moving) electrons in the metallic bond.

  12. The electronegativity difference for a polar covalent bond is:

    • 0.4 to 1.7
    • < 0.4
    • ≥ 1.7
    • Equal to 0

    ΔEN 0.4–1.7 = polar covalent bond. Less than 0.4 = nonpolar covalent. ≥1.7 = ionic.

  13. In a Lewis structure for H₂O, how many lone pairs are on oxygen?

    • 0
    • 2
    • 1
    • 3

    O has 6 valence electrons. 2 used in bonds with H. Remaining 4 = 2 lone pairs.

  14. Which substance has the strongest intermolecular forces?

    • CH₄
    • HCl
    • H₂O
    • CO₂

    H₂O has hydrogen bonding (H bonded to O) → strongest IMFs among these → highest BP.

  15. Diamond (pure carbon) has a very high melting point because:

    • It's an ionic solid
    • It has hydrogen bonds
    • Metallic bonding holds it together
    • It's a network covalent solid with strong C-C bonds throughout

    Diamond is a network covalent solid — every C is covalently bonded to 4 others in a 3D network → extremely high MP.

  16. The molecular geometry around N in NH₃ is:

    • Trigonal pyramidal
    • Linear
    • Trigonal planar
    • Tetrahedral

    NH₃: 3 bonding pairs + 1 lone pair → trigonal pyramidal shape (the lone pair is NOT included in the geometry name).

  17. Which substance has the highest boiling point due to hydrogen bonding?

    • H₂S
    • H₂O
    • H₂Se
    • H₂Te

    H₂O has H-bonding (H bonded to O) → much stronger IMFs than the heavier H₂S, H₂Se, H₂Te which only have dipole/LDF.

  18. A double bond between two atoms consists of how many shared electrons?

    • 2
    • 6
    • 4
    • 8

    A double bond = 2 pairs of shared electrons = 4 electrons.

  19. BF₃ has polar B-F bonds but is a nonpolar molecule. Why?

    • B and F have identical EN
    • It has only single bonds
    • F is more electronegative than B
    • Trigonal planar geometry → dipoles cancel

    BF₃ is trigonal planar (120° symmetric) → 3 equal B-F dipoles cancel → nonpolar overall.

  20. Which substance has the lowest boiling point?

    • CH₄
    • H₂O
    • NaCl
    • NH₃

    CH₄ is a small, nonpolar molecule with only weak LDFs → lowest BP of these substances.

  21. Which compound contains both ionic and covalent bonds?

    • CaCl₂
    • KClO₂
    • Li₂S
    • MnO₂

    KClO₂: K⁺ and ClO₂⁻ joined by ionic bond; inside ClO₂⁻ the Cl−O bonds are covalent. CaCl₂, Li₂S, MnO₂ have only ionic bonds (no polyatomic ions).

  22. Which element has diatomic molecules that each contain a multiple (double) covalent bond?

    • Bromine
    • Hydrogen
    • Oxygen
    • Iodine

    O₂ contains a double bond (O=O). H₂, Br₂, I₂ contain only single bonds. N₂ has a triple bond.

  23. Which formula represents an asymmetrical (polar) molecule?

    • CO₂
    • Cl₂
    • CH₄
    • HCl

    HCl: two different atoms → unequal EN → polar bond AND asymmetric (linear with two different ends) → polar molecule. CO₂, Cl₂, CH₄ are all symmetric (nonpolar).

  24. When N + N → N₂ occurs, what happens to energy?

    • Energy released as bonds form
    • Energy absorbed as bonds break
    • Energy absorbed as bonds form
    • Energy released as bonds break

    Forming bonds ALWAYS releases energy (exothermic). N + N → N₂ involves forming the N≡N triple bond → energy released.

  25. Which statement explains why CH₄ is a nonpolar molecule?

    • Electrons are shared between C and H atoms
    • The distribution of charge in the molecule is symmetrical
    • The distribution of charge in the molecule is asymmetrical
    • Electrons are transferred from C to H atoms

    CH₄ has 4 equal C-H bonds arranged symmetrically (tetrahedral) → dipoles cancel → nonpolar. Symmetry is the key reason.

  26. The bond between Br atoms in a Br₂ molecule is best described as

    • ionic, formed by transferring two valence electrons
    • ionic, formed by sharing two valence electrons
    • covalent, formed by sharing two valence electrons
    • covalent, formed by transferring two valence electrons

    Br₂: same element, ΔEN = 0 → nonpolar covalent bond. Electrons are equally shared (not transferred).

  27. A barium atom attains a stable electron configuration when it bonds with

    • one chlorine atom
    • one sodium atom
    • two sodium atoms
    • two chlorine atoms

    Ba is in Group 2 → loses 2 electrons → Ba²⁺. Each Cl gains 1 electron → Cl⁻. Two Cl atoms are needed to balance the 2+ charge → BaCl₂.

  28. Which type of bonding is present in a sample of an element that is malleable?

    • Metallic
    • Polar covalent
    • Nonpolar covalent
    • Ionic

    Malleability is a property of metals, explained by metallic bonding — the delocalized electron sea allows layers of ions to slide without breaking bonds.

Unit 6: Chemical Quantities (39)
  1. GFM of SO₂ (S=32, O=16) is:

    • 48 g/mol
    • 64 g/mol
    • 80 g/mol
    • 32 g/mol

    GFM = 32 + 2(16) = 32 + 32 = 64 g/mol.

  2. % O in CO₂ (C=12, O=16) is:

    • 27.3%
    • 36.4%
    • 72.7%
    • 50%

    % O = (2×16)/44 × 100 = 32/44 × 100 = 72.7%.

  3. A compound is 40% C, 6.7% H, 53.3% O. The empirical formula is:

    • CHO
    • C₂H₄O₂
    • C₃H₆O₃
    • CH₂O

    Mol C=40/12=3.33; H=6.7/1=6.7; O=53.3/16=3.33. Ratio: 1:2:1 → CH₂O.

  4. The empirical formula mass of CH₂O is 30 g/mol. If MW = 180, the molecular formula is:

    • C₆H₁₂O₆
    • CH₂O
    • C₂H₄O₂
    • C₃H₆O₃

    n = 180/30 = 6. Multiply CH₂O × 6 = C₆H₁₂O₆ (glucose).

  5. How many moles are in 44.0 g of CO₂ (GFM=44.0)?

    • 0.5 mol
    • 1.0 mol
    • 2.0 mol
    • 44.0 mol

    n = 44.0/44.0 = 1.0 mol.

  6. CuSO₄·5H₂O: how many grams of water per formula unit? (H₂O = 18 g/mol)

    • 18 g/mol
    • 36 g/mol
    • 90 g/mol
    • 72 g/mol

    5 moles of H₂O × 18 g/mol = 90 g/mol of water.

  7. In stoichiometry, coefficients in the balanced equation represent:

    • Mass ratios
    • Volume ratios
    • Particle diameters
    • Mole ratios

    Coefficients represent the mole ratios of substances in the reaction.

  8. N₂ + 3H₂ → 2NH₃. How many moles of NH₃ from 2 mol N₂?

    • 4 mol
    • 1 mol
    • 2 mol
    • 3 mol

    Mole ratio N₂:NH₃ = 1:2. So 2 mol N₂ × (2 mol NH₃/1 mol N₂) = 4 mol NH₃.

  9. The limiting reagent in a reaction is:

    • The reactant present in largest amount
    • The reactant that is completely consumed and limits product formed
    • The product formed in largest amount
    • The most expensive reactant

    Limiting reagent = runs out first → determines theoretical yield.

  10. GFM of Al₂(SO₄)₃ (Al=27, S=32, O=16) is:

    • 123 g/mol
    • 246 g/mol
    • 342 g/mol
    • 150 g/mol

    2(27) + 3(32 + 4×16) = 54 + 3(96) = 54 + 288 = 342 g/mol.

  11. Theoretical yield = 25 g; actual yield = 20 g. % yield = ?

    • 125%
    • 25%
    • 5%
    • 80%

    % yield = 20/25 × 100 = 80%.

  12. The first step in finding empirical formula from percent composition is:

    • Convert percentages to grams (assume 100 g sample)
    • Convert mol ratios to whole numbers
    • Divide all percentages by the smallest
    • Calculate the molecular mass

    Assume 100 g sample → % becomes grams directly. Then divide each by its molar mass to get moles.

  13. How many liters does 3.0 mol of gas occupy at STP?

    • 3.0 L
    • 67.2 L
    • 22.4 L
    • 44.8 L

    3.0 mol × 22.4 L/mol = 67.2 L at STP.

  14. Which formula contains the highest % of nitrogen? (N=14)

    • NH₃ (GFM=17)
    • NO₂ (GFM=46)
    • N₂H₄ (GFM=32)
    • N₂O (GFM=44)

    % N = (mass N/GFM)×100 for each: NH₃ = 14/17 = 82.4%; N₂H₄ = 28/32 = 87.5%; NO₂ = 14/46 = 30.4%; N₂O = 28/44 = 63.6%. N₂H₄ has the highest percent nitrogen at 87.5%.

  15. If actual yield > theoretical yield, this means:

    • Reaction was very efficient
    • Extra product appeared from nothing
    • The limiting reagent was used up twice
    • There was an error in measurement or calculation

    Actual yield cannot exceed theoretical yield — if it does, there's a measurement or calculation error.

  16. The percent water in CaCl₂·2H₂O (CaCl₂=111, H₂O=18) is:

    • 24.5%
    • 14.4%
    • 32.4%
    • 36.0%

    % water = 2(18)/(111+36) × 100 = 36/147 × 100 = 24.5%.

  17. To find the molecular formula from empirical formula, you need:

    • The atomic masses only
    • The molecular (molar) mass of the compound
    • The percent composition
    • The boiling point

    n = MW/EFM. You need the actual molecular mass to find n, then multiply subscripts.

  18. GFM of Mg(NO₃)₂ (Mg=24, N=14, O=16) is:

    • 86 g/mol
    • 108 g/mol
    • 148 g/mol
    • 162 g/mol

    24 + 2(14 + 3×16) = 24 + 2(62) = 24 + 124 = 148 g/mol.

  19. How many grams of H₂O are in 0.50 mol? (GFM=18 g/mol)

    • 18.0 g
    • 36.0 g
    • 0.028 g
    • 9.0 g

    g = 0.50 mol × 18 g/mol = 9.0 g.

  20. In 2H₂ + O₂ → 2H₂O, if 4 mol H₂ reacts, how many mol H₂O forms?

    • 4 mol
    • 1 mol
    • 2 mol
    • 8 mol

    Ratio H₂:H₂O = 2:2 = 1:1. So 4 mol H₂ → 4 mol H₂O.

  21. The first step in any mass-to-mass stoichiometry problem is:

    • Multiply by the mole ratio
    • Convert grams of given to moles using its GFM
    • Find the GFM of the wanted substance
    • Multiply by Avogadro's number

    Always start by converting grams → moles (÷ GFM). Moles are the universal bridge in stoichiometry.

  22. N₂ + 3H₂ → 2NH₃. How many grams of NH₃ (GFM=17) form from 28 g N₂ (GFM=28)?

    • 17 g
    • 28 g
    • 34 g
    • 51 g

    28 g N₂ ÷ 28 g/mol = 1 mol N₂ × (2 mol NH₃/1 mol N₂) × 17 g/mol = 34 g NH₃.

  23. In 2H₂ + O₂ → 2H₂O, you have 6 mol H₂ and 2 mol O₂. Which is the limiting reagent?

    • H₂
    • H₂O
    • Neither — they are equal
    • O₂

    6 mol H₂ requires 3 mol O₂. Only 2 mol O₂ available → O₂ runs out first → O₂ is limiting.

  24. Using the same reaction above (6 mol H₂, 2 mol O₂, limiting = O₂), how many mol H₂O form?

    • 4 mol
    • 2 mol
    • 6 mol
    • 3 mol

    2 mol O₂ × (2 mol H₂O / 1 mol O₂) = 4 mol H₂O.

  25. How many moles of excess H₂ remain after the reaction above?

    • 0 mol
    • 2 mol
    • 4 mol
    • 6 mol

    O₂ is limiting. 2 mol O₂ uses 2×2 = 4 mol H₂. Started with 6 mol H₂ → 6−4 = 2 mol H₂ left over.

  26. Theoretical yield is 50.0 g but only 38.0 g is collected. % yield = ?

    • 131%
    • 24%
    • 76%
    • 50%

    % yield = 38.0/50.0 × 100 = 76%.

  27. At STP, how many liters does 3.5 mol CO₂ occupy?

    • 3.5 L
    • 22.4 L
    • 44.8 L
    • 78.4 L

    3.5 mol × 22.4 L/mol = 78.4 L at STP.

  28. In N₂ + 3H₂ → 2NH₃, what is the mole ratio of H₂ to NH₃?

    • 3:2
    • 1:1
    • 2:3
    • 1:2

    Coefficient of H₂ = 3; coefficient of NH₃ = 2 → ratio H₂:NH₃ = 3:2.

  29. How many molecules are in 4.0 g of H₂ (GFM = 2.0)?

    • 2.0 mol
    • 1.20×10²⁴
    • 6.02×10²³
    • 3.01×10²³

    4.0 g ÷ 2.0 g/mol = 2.0 mol × 6.02×10²³ = 1.20×10²⁴ molecules.

  30. Which statement about excess reagent is correct?

    • It determines the theoretical yield
    • It is completely consumed
    • Some of it remains after the reaction
    • It is always the cheaper reactant

    The excess reagent is NOT completely consumed — some remains after the limiting reagent runs out.

  31. 2Al + 3Cl₂ → 2AlCl₃. How many grams of AlCl₃ (GFM=133.5) form from 27 g Al (GFM=27)?

    • 27 g
    • 67 g
    • 267 g
    • 133.5 g

    27 g Al ÷ 27 g/mol = 1 mol Al × (2 mol AlCl₃/2 mol Al) × 133.5 g/mol = 133.5 g.

  32. Given: CH₄ + 2O₂ → 2H₂O + CO₂ + energy. 12 g CH₄ and 48 g O₂ react to produce 33 g CO₂. How many grams of H₂O are produced?

    • 27 g
    • 12 g
    • 60 g
    • 69 g

    Conservation of mass: total reactants = 12+48 = 60 g. Total products = 33 g CO₂ + x g H₂O = 60 g → x = 27 g H₂O.

  33. What is the gram-formula mass of P₂O₅? (P=31, O=16)

    • 47 g/mol
    • 142 g/mol
    • 111 g/mol
    • 187 g/mol

    GFM = 2(31) + 5(16) = 62 + 80 = 142 g/mol.

  34. What is the percent composition by mass of Cu in CuSO₄? (GFM = 160 g/mol, Cu = 64)

    • 25%
    • 50%
    • 40%
    • 64%

    % Cu = (64/160) × 100 = 40%.

  35. N₂ + 3H₂ → 2NH₃. How many moles of H₂ are needed to produce 10.0 mol NH₃?

    • 5.0 mol
    • 10.0 mol
    • 20.0 mol
    • 15.0 mol

    Mole ratio H₂:NH₃ = 3:2. 10.0 mol NH₃ × (3 mol H₂/2 mol NH₃) = 15.0 mol H₂.

  36. What is the gram-formula mass of Fe(NO₃)₃? (Fe=56, N=14, O=16)

    • 242 g/mol
    • 146 g/mol
    • 194 g/mol
    • 214 g/mol

    Fe(NO₃)₃ = 56 + 3(14 + 3×16) = 56 + 3(62) = 56 + 186 = 242 g/mol.

  37. What is the mass in grams of 2.0 moles of NO₂? (N=14, O=16)

    • 46 g
    • 92 g
    • 60. g
    • 30. g

    GFM of NO₂ = 14 + 2(16) = 46 g/mol. 2.0 mol × 46 g/mol = 92 g.

  38. What is the mass of 1.5 moles of CO₂? (C=12, O=16)

    • 44 g
    • 33 g
    • 66 g
    • 29 g

    GFM of CO₂ = 12 + 2(16) = 44 g/mol. 1.5 × 44 = 66 g.

  39. A compound has a molecular mass of 54 and an empirical formula of CH (mass = 13). What is the molecular formula?

    • CH
    • C₂H₂
    • C₃H₃
    • C₄H₄

    n = 54/13 ≈ 4.15 → round to 4. Molecular formula = (CH)₄ = C₄H₄.

Unit 7: Chemical Reactions (23)
  1. Which type of reaction is: 2H₂ + O₂ → 2H₂O?

    • Synthesis
    • Decomposition
    • Single replacement
    • Combustion

    Two reactants combine to form one product → synthesis (combination) reaction.

  2. The reaction Zn + CuSO₄ → ZnSO₄ + Cu is best classified as a

    • synthesis reaction
    • single replacement reaction
    • double replacement reaction
    • combustion reaction

    One element (Zn) displaces another element (Cu) from a compound → single replacement reaction.

  3. In balancing equations, you can change only the

    • Subscripts
    • Both subscripts and coefficients
    • Coefficients
    • The products

    Only coefficients can be changed — changing subscripts would change the identity of the substance.

  4. Fe + ZnSO₄ → ? (use Table J)

    • FeSO₄ + Zn
    • Fe₂SO₄ + Zn
    • FeZn + SO₄
    • No reaction (NR)

    Zn is ABOVE Fe on Table J (zinc is more active than iron) → Fe cannot displace Zn from solution → No reaction (NR).

  5. Cu + FeSO₄ → ? (use Table J)

    • No reaction (NR)
    • CuSO₄ + Fe
    • Cu₂SO₄ + Fe
    • CuFe + SO₄

    Cu is BELOW Fe on Table J → Cu cannot displace Fe → NR.

  6. The balanced equation for: H₂ + N₂ → NH₃ is:

    • H₂ + N₂ → 2NH₃
    • 3H₂ + N₂ → 2NH₃
    • H₂ + N₂ → NH₃
    • 2H₂ + N₂ → 2NH₃

    3H₂ + N₂ → 2NH₃. Check: 6H and 2N on each side. ✓

  7. Which pair would produce a precipitate? (Table F: AgCl is insoluble)

    • NaNO₃ + KCl
    • NaCl + KNO₃
    • AgNO₃ + NaCl
    • Na₂SO₄ + KNO₃

    AgNO₃ + NaCl → AgCl↓ + NaNO₃. AgCl is insoluble → precipitate forms.

  8. Combustion of C₃H₈ (propane) produces:

    • CO and H₂
    • C and H₂O
    • CO₂ and O₂
    • CO₂ and H₂O

    Complete combustion of hydrocarbons always produces CO₂ and H₂O.

  9. Which type of reaction is: CaCO₃ → CaO + CO₂?

    • Decomposition
    • Synthesis
    • Single replacement
    • Double replacement

    One compound breaks into two simpler substances → decomposition.

  10. Spectator ions are:

    • Ions that react to form the precipitate
    • Ions that appear unchanged on both sides of the equation
    • Ions that donate electrons
    • The most reactive ions

    Spectator ions don't participate in the reaction — they're present but unchanged on both sides.

  11. The net ionic equation for Pb(NO₃)₂ + 2KI → PbI₂↓ + 2KNO₃ is:

    • NO₃⁻ + K⁺ → KNO₃
    • All ions react
    • Pb²⁺ + 2I⁻ → PbI₂
    • Pb²⁺ + K⁺ → products

    K⁺ and NO₃⁻ are spectators. Only Pb²⁺ and I⁻ react to form the insoluble precipitate.

  12. F₂ + 2KBr → 2KF + Br₂. F₂ displaces Br because:

    • Br is more electronegative
    • Br is a larger atom
    • F is a metal
    • F is more active than Br (higher on Table J)

    Table J halogens: F > Cl > Br > I. F is highest → displaces Br.

  13. Which is a double replacement reaction?

    • AgNO₃ + NaCl → AgCl + NaNO₃
    • 2Na + Cl₂ → 2NaCl
    • Fe + CuSO₄ → FeSO₄ + Cu
    • CH₄ + 2O₂ → CO₂ + 2H₂O

    AgNO₃ + NaCl → AgCl + NaNO₃: ions from two compounds switch partners → double replacement.

  14. Table F is used to predict:

    • Reaction rate
    • Whether a precipitate forms in double replacement
    • The activity of metals
    • Half-life of isotopes

    Table F lists solubility rules — used to predict precipitates in double replacement reactions.

  15. A balanced chemical equation demonstrates the law of:

    • Definite proportions
    • Multiple proportions
    • Conservation of mass
    • Conservation of energy

    Balancing equations ensures the same number of each atom on both sides → conservation of mass.

  16. Diatomic elements include:

    • Na, K, Ca
    • He, Ne, Ar
    • H₂, CO₂, H₂O
    • H₂, N₂, O₂, F₂, Cl₂, Br₂, I₂

    The 7 diatomic elements: H₂, N₂, O₂, F₂, Cl₂, Br₂, I₂. Always write with subscript 2 when uncombined.

  17. Which is an example of a synthesis reaction?

    • SO₂ + H₂O → H₂SO₃
    • 2KClO₃ → 2KCl + 3O₂
    • Fe + CuSO₄ → FeSO₄ + Cu
    • HCl + NaOH → NaCl + H₂O

    SO₂ + H₂O → H₂SO₃: two reactants combine to form one product → synthesis.

  18. In a neutralization reaction between HNO₃ and KOH, the salt produced is:

    • KCl
    • KNO₃
    • HCl
    • K₂SO₄

    Acid anion (NO₃⁻) + base cation (K⁺) → KNO₃ (potassium nitrate).

  19. What are the correct coefficients to balance: Al + O₂ → Al₂O₃?

    • 1, 1, 1
    • 2, 3, 2
    • 4, 3, 2
    • 2, 1, 1

    4Al + 3O₂ → 2Al₂O₃. Check: 4 Al and 6 O on each side. ✓

  20. Which statement about single replacement reactions is true?

    • They always occur regardless of activity
    • A less active element can displace a more active one
    • They require both reactants to be ionic
    • A more active element displaces a less active one from solution

    Table J: single replacement is spontaneous only when the replacing element is HIGHER (more active) on the list.

  21. Given: Ba(NO₃)₂(aq) + Na₂SO₄(aq) → 2NaNO₃(aq) + BaSO₄(s). What type of reaction is shown?

    • Double replacement
    • Single replacement
    • Synthesis
    • Decomposition

    Two ionic compounds exchange partners (Ba²⁺ pairs with SO₄²⁻; Na⁺ pairs with NO₃⁻) → double replacement. BaSO₄ precipitates.

  22. Which equation represents a single replacement reaction?

    • 2AlCl₃(s) → 2Al(s) + 3Cl₂(g)
    • 2Al(s) + 6HCl(aq) → 2AlCl₃(aq) + 3H₂(g)
    • AlCl₃(aq) + 3KOH(aq) → Al(OH)₃(s) + 3KCl(aq)
    • 2Al(s) + 3Cl₂(g) → 2AlCl₃(s)

    Al replaces H in HCl → single replacement. Al + HCl: one element displaces another from a compound.

  23. Based on Table J, which element will replace Pb from Pb(NO₃)₂(aq)?

    • Cu(s)
    • Ag(s)
    • Mg(s)
    • Au(s)

    Table J activity series: Mg is more active than Pb (higher on the list) → Mg spontaneously replaces Pb. Cu, Ag, and Au are below Pb → cannot replace it.

Unit 8: Phases of Matter (34)
  1. During a phase change (e.g., melting), temperature:

    • Increases
    • Decreases
    • Fluctuates randomly
    • Remains constant

    At a phase change, energy goes into or out of the system as potential energy (breaking/forming intermolecular attractions). KE (temperature) stays constant.

  2. Which formula is used during the sloped section of a heating curve?

    • q = mCΔT
    • q = mH_f
    • q = mH_v
    • q = mCT

    Sloped section = temperature is changing → q = mCΔT.

  3. The specific heat of water is 4.18 J/g·K. How much heat to raise 10.0 g from 20°C to 30°C?

    • 41.8 J
    • 418 J
    • 83.6 J
    • 4.18 J

    q = mCΔT = 10.0 × 4.18 × 10 = 418 J.

  4. The flat section at the boiling point on a heating curve uses:

    • q = mCΔT
    • q = mH_f
    • q = mH_v
    • q = CΔT

    Flat at BP = liquid→gas phase change → q = mH_v (heat of vaporization).

  5. London dispersion forces increase with increasing:

    • Temperature
    • Molecular polarity
    • Pressure
    • Molar mass (more electrons)

    Larger molecules have more electrons → stronger temporary dipoles → stronger LDFs.

  6. Which substance has the strongest intermolecular forces?

    • HF
    • CH₄
    • HCl
    • Cl₂

    HF has H bonded directly to F → hydrogen bonding → strongest IMFs among these.

  7. The conversion to Kelvin is required before using gas law formulas because

    • the Celsius scale gives less accurate measurements
    • gas laws require an absolute scale where 0 K represents zero kinetic energy
    • Kelvin only applies to calorimetry calculations
    • gas law formulas only work above 0°C

    Gas laws require an absolute temperature scale. At 0 K, KE = 0. Using Celsius (which can be 0 or negative) would give nonsensical results.

  8. Which substance has the lowest boiling point, indicating weakest IMFs?

    • H₂O (100°C)
    • HF (19.5°C)
    • CH₄ (−161°C)
    • NH₃ (−33°C)

    CH₄ is nonpolar with only weak LDFs → lowest BP among these.

  9. At what region of the heating curve does PE increase while KE stays constant?

    • Sloped sections only
    • Throughout the entire curve
    • Only when temperature = 0°C
    • Flat sections (phase changes) only

    At flat sections (phase changes): energy goes into overcoming IMFs (PE ↑), not increasing motion (KE/T constant).

  10. A substance has a high vapor pressure. This indicates:

    • Weak IMFs and evaporates easily
    • Strong IMFs
    • High boiling point
    • High surface tension

    High VP = molecules escape easily = weak IMFs. Lower IMFs → lower BP and higher VP.

  11. Ice melts at 0°C. The heat absorbed during melting is calculated by:

    • q = mCΔT
    • q = mH_f
    • q = mH_v
    • q = mC(273)

    Melting = solid→liquid phase change → flat on heating curve → q = mH_f.

  12. Which is a GAS at room temperature (25°C)?

    • Water (BP=100°C)
    • Mercury (BP=357°C)
    • Nitrogen (BP=−196°C)
    • NaCl (MP=801°C)

    Nitrogen boils at −196°C → is a gas at room temperature (25°C > −196°C).

  13. Temperature is a measure of:

    • Total kinetic energy
    • Total heat content
    • Total potential energy
    • Average kinetic energy of particles

    Temperature measures the AVERAGE KE of particles — not total (which would depend on sample size).

  14. As water evaporates, the remaining water becomes:

    • Cooler (evaporative cooling)
    • Warmer
    • The same temperature
    • More dense

    High-energy molecules escape (evaporate) → average KE of remaining molecules decreases → cooling effect.

  15. Which state of matter has a definite volume but no definite shape?

    • Solid
    • Liquid
    • Gas
    • Plasma

    Liquids have definite volume (incompressible) but take the shape of their container.

  16. The boiling point of a liquid is the temperature where:

    • All molecules have enough KE to escape
    • IMFs become zero
    • Vapor pressure equals atmospheric pressure
    • The liquid reaches 100°C

    Boiling occurs when vapor pressure = atmospheric pressure. The 'normal' BP is at 101.3 kPa.

  17. H₂O has an unusually high boiling point for its molecular mass because:

    • It is very heavy
    • It has strong London dispersion forces
    • It is ionic
    • It forms hydrogen bonds between molecules

    H₂O molecules form H-bonds (H bonded to O) — much stronger than the LDFs of similar-size molecules.

  18. On Table H, which substance has the highest vapor pressure at 50°C?

    • The one with the lowest boiling point
    • The one with the strongest IMFs
    • The one with the highest boiling point
    • The one with the most mass

    Lower BP = weaker IMFs = higher VP. On Table H, the curve highest on the y-axis at any given T has highest VP.

  19. During the cooling curve, the flat section at the freezing point represents:

    • KE decreasing
    • PE decreasing as liquid→solid (bonds forming, energy released)
    • ΔH = 0
    • Temperature increasing

    Freezing = liquid→solid: IMFs form, PE decreases, energy is released to surroundings. T stays constant.

  20. The heat of vaporization of water is 2260 J/g. How much heat to boil 5.0 g of water at 100°C?

    • 452 J
    • 2260 J
    • 11300 J
    • 5000 J

    q = mH_v = 5.0 g × 2260 J/g = 11300 J.

  21. Which process requires the most energy?

    • Melting 1 mol of ice
    • Heating 1 mol of water from 0°C to 100°C
    • Freezing 1 mol of water
    • Vaporizing 1 mol of liquid water

    H_v (2260 J/g) >> H_f (334 J/g) >> heating through 100°C (418 J). Vaporization requires the most energy.

  22. Substances with strong IMFs tend to have:

    • High boiling point, low vapor pressure
    • Low boiling point, high vapor pressure
    • High boiling point, high vapor pressure
    • Low boiling point, low vapor pressure

    Strong IMFs → harder to separate molecules → higher BP and lower VP (less evaporation tendency).

  23. What type of particles are found in a plasma?

    • Atoms only
    • Positively and negatively charged ions and free electrons
    • Molecules only
    • Neutral atoms and molecules

    Plasma is a high-energy ionized gas consisting of free electrons and positive ions.

  24. During condensation (gas → liquid), energy is:

    • Absorbed by the substance
    • Neither absorbed nor released
    • Released to surroundings
    • Converted to mass

    Condensation = gas→liquid: IMFs form (exothermic) → energy released. This is the reverse of vaporization.

  25. In the heating curve, all five regions in order are:

    • Solid, liquid, gas, plasma, liquid
    • Heating, cooling, melting, freezing, boiling
    • Boiling, melting, heating, cooling, freezing
    • Solid heating, melting, liquid heating, boiling, gas heating

    Solid heating → flat (melting) → liquid heating → flat (boiling) → gas heating. These are the 5 segments.

  26. What happens to the potential energy of water molecules as water evaporates from a wet surface?

    • PE increases
    • PE decreases
    • PE stays the same
    • PE becomes zero

    Evaporating molecules overcome intermolecular attractions → PE increases as they escape the liquid surface. This is why evaporation is endothermic and cools the surface.

  27. A student left one paper towel dry in an evaporation experiment. In terms of experimental design, why?

    • To speed up evaporation
    • To serve as a control — a baseline showing temperature without evaporation
    • To increase surface area
    • To test a different variable

    The dry towel is the control group — it shows what temperature change (if any) occurs WITHOUT evaporation, so results can be compared fairly.

  28. Heat flows between two objects in contact. In which direction does heat flow?

    • From cold to hot
    • From high PE to low PE
    • From the object at higher temperature to the object at lower temperature
    • In both directions equally

    Heat always flows from higher temperature (more average KE) to lower temperature — this is the second law of thermodynamics.

  29. At standard pressure, which 5.0-gram sample of xenon has the greatest entropy?

    • Xe(s) at 161 K
    • Xe(ℓ) at 161 K
    • Xe(ℓ) at 165 K
    • Xe(g) at 165 K

    Gas state = greatest disorder = highest entropy. Among gas samples, Xe(g) at 165 K has the most disordered particles.

  30. Which physical changes are endothermic (absorb energy)?

    • Melting and evaporating
    • Condensation and deposition
    • Melting and freezing
    • Condensation and sublimation

    Endothermic phase changes require energy input: melting (solid→liquid) and evaporating/vaporizing (liquid→gas). Condensation and freezing release energy (exothermic).

  31. On a heating curve, segment CD (boiling plateau) is longer than segment AB (melting plateau) because

    • Potential energy is released during boiling
    • Heat of vaporization is greater than heat of fusion
    • Average KE increases faster during boiling than melting
    • Boiling occurs at a higher temperature than melting

    H_v (2260 J/g for water) >> H_f (334 J/g). More energy is required to vaporize than to melt → the boiling plateau takes longer at the same constant heating rate.

  32. What is the minimum heat required to completely melt 200. grams of H₂O(s) at its melting point? (H_f = 334 J/g)

    • 334 J
    • 452,000 J
    • 66,800 J
    • 836 J

    q = mH_f = 200. g × 334 J/g = 66,800 J.

  33. When an ice cube is placed in 100 mL of water at 25°C, which describes the heat transfer?

    • Both the ice and water gain heat
    • Both the ice and water lose heat
    • The ice loses heat and the water gains heat
    • The ice gains heat and the water loses heat

    Heat flows from hot to cold. The warmer water loses heat energy to the colder ice. The ice gains heat and melts; the water cools.

  34. At STP, a 12.0-liter sample of CH₄(g) has the same total number of molecules as

    • 12.0 L of CO₂(g) at STP
    • 6.0 L of H₂(g) at STP
    • 18.0 L of HCl(g) at STP
    • 24.0 L of O₂(g) at STP

    Avogadro's Law: equal volumes of gas at the same T and P contain equal numbers of molecules. 12.0 L CH₄ = 12.0 L CO₂ (both at STP).

Unit 9: Gas Laws (28)
  1. A gas at 2 atm and 4 L is compressed to 1 L at constant T. New pressure?

    • 1 atm
    • 8 atm
    • 4 atm
    • 2 L

    Boyle's Law: P₁V₁=P₂V₂ → 2×4 = P₂×1 → P₂ = 8 atm.

  2. A gas at 300 K occupies 6 L. At 600 K (constant P), it occupies:

    • 3 L
    • 6 L
    • 12 L
    • 18 L

    Charles's Law: V₁/T₁=V₂/T₂ → 6/300 = V₂/600 → V₂ = 12 L.

  3. 25°C in Kelvin is:

    • 25 K
    • 248 K
    • 325 K
    • 298 K

    K = °C + 273 = 25 + 273 = 298 K.

  4. Gases deviate most from ideal behavior under:

    • Low T, high P
    • High T, low P
    • Low T, low P
    • High T, high P

    Low T (molecules slow, attractions matter) + high P (molecules compressed close together) → most deviation from ideal.

  5. At STP, 2 mol of any gas occupies:

    • 11.2 L
    • 44.8 L
    • 22.4 L
    • 2.0 L

    1 mol = 22.4 L at STP, so 2 mol = 2 × 22.4 = 44.8 L.

  6. According to the kinetic molecular theory, which assumption is made about ideal gas molecules?

    • They don't collide
    • Real gases behave perfectly at all conditions
    • This is an assumption; real gases do have some attraction
    • They can be compressed infinitely

    Zero IMF is an ideal gas ASSUMPTION. Real gases have some IMFs — this is why they deviate from ideal behavior.

  7. If pressure of a gas increases at constant volume, temperature:

    • Decreases
    • Stays the same
    • Drops to zero
    • Increases

    Gay-Lussac's Law: P∝T at constant V. Higher pressure → higher temperature.

  8. A gas at 1 atm and 546 K is cooled to 273 K at constant V. New pressure?

    • 0.5 atm
    • 1 atm
    • 2 atm
    • 4 atm

    Gay-Lussac's: P₁/T₁=P₂/T₂ → 1/546=P₂/273 → P₂=0.5 atm.

  9. Which gas behaves most like an ideal gas?

    • H₂O vapor
    • He
    • SO₂
    • NH₃

    He: smallest atom, monatomic, nonpolar, very weak LDFs → closest to ideal gas behavior.

  10. Boyle's Law applies at constant:

    • Pressure
    • Volume
    • Temperature
    • Number of moles

    Boyle's Law: P₁V₁=P₂V₂ at constant TEMPERATURE (and constant n).

  11. Equal volumes of H₂ and O₂ at the same T and P contain:

    • Equal masses
    • More H₂ molecules
    • More O₂ molecules
    • Equal numbers of molecules

    Avogadro's Law: equal volumes at same T and P contain equal numbers of molecules (regardless of mass).

  12. The units of pressure in Table A (STP) are:

    • kPa and atm
    • atm and mmHg
    • kPa and torr
    • atm and bar

    Table A: STP = 101.3 kPa = 1 atm = 760 mmHg = 760 torr.

  13. Combined gas law: P₁=2 atm, V₁=5 L, T₁=300 K, T₂=600 K, P₂=4 atm. V₂=?

    • 2.5 L
    • 5 L
    • 10 L
    • 20 L

    P₁V₁/T₁=P₂V₂/T₂ → (2×5)/300=(4×V₂)/600 → 10/300=4V₂/600 → V₂=5 L.

  14. According to KMT, all gas molecules at the same temperature have:

    • Same velocity
    • Same mass
    • Same average kinetic energy
    • Same pressure

    KMT: average KE depends only on temperature. All gases at same T have same average KE (not same speed — lighter molecules move faster).

  15. Dalton's Law of Partial Pressures states:

    • P × V = constant
    • Gas pressure depends on mass
    • All gases have equal pressure
    • P_total = sum of all individual partial pressures

    Each gas in a mixture exerts pressure independently; total = sum of all partial pressures.

  16. At absolute zero (0 K), according to theory:

    • All particle motion would stop
    • Gases liquefy
    • Gas pressure reaches a maximum
    • Gases explode

    0 K = absolute zero: theoretically all particle motion (KE) = 0. Cannot actually be achieved.

  17. P₁=3 atm, V₁=2 L, T₁=273 K, P₂=1 atm, T₂=546 K. V₂=?

    • 2 L
    • 12 L
    • 4 L
    • 6 L

    P₁V₁/T₁=P₂V₂/T₂ → (3×2)/273=(1×V₂)/546 → 6/273=V₂/546 → V₂=12 L.

  18. Which correctly states Charles's Law?

    • V ∝ 1/P (constant T)
    • P ∝ T (constant V)
    • V ∝ T (constant P) — using Kelvin
    • V ∝ n (constant T, P)

    Charles's Law: volume and temperature (Kelvin) are directly proportional at constant pressure.

  19. Standard temperature for STP is:

    • 25°C (298 K)
    • 100°C (373 K)
    • −40°C (233 K)
    • 0°C (273 K)

    STP = 0°C (273 K) and 101.3 kPa. (Note: IUPAC changed this to 0°C/100 kPa in 1982, but this course still uses 273 K/101.3 kPa from Table A.)

  20. Which gas behaves most like an ideal gas, and why?

    • NH₃ has hydrogen bonding; H₂ has only very weak LDFs
    • H₂ is heavier
    • H₂ is polar
    • NH₃ is smaller

    NH₃ has strong H-bonding (H to N) → significant IMFs → large deviation from ideal. H₂ has negligible IMFs.

  21. A 320-mL sample of N₂ is at 300 K and 100 kPa. The temperature changes to 450 K and pressure to 60.0 kPa. What is the new volume?

    • 240 mL
    • 800 mL
    • 480 mL
    • 960 mL

    Combined gas law: V₂ = P₁V₁T₂/(T₁P₂) = (100×320×450)/(300×60.0) = 14,400,000/18,000 = 800 mL.

  22. At 300 K, gas particles collide with a certain force. How does the force of collisions change at 450 K?

    • Force decreases
    • Force stays the same
    • Force increases — particles move faster at higher temperature
    • Force becomes zero

    Higher temperature → higher average KE → particles move faster → collide with greater force.

  23. Which change causes a real gas to behave more like an ideal gas?

    • Decrease temperature, increase pressure
    • Decrease both temperature and pressure
    • Increase both temperature and pressure
    • Increase temperature, decrease pressure

    Ideal behavior: high T (fast-moving, less interaction) + low P (far apart, less volume). Increasing T and decreasing P pushes toward ideal conditions.

  24. A nitrogen gas sample is in a sealed rigid cylinder (constant volume). How many significant figures are in the temperature '300. K'?

    • 3
    • 1
    • 2
    • 4

    300. K — the decimal point makes all three digits significant → 3 sig figs.

  25. A gas sample has P = 240 kPa, V = 70.0 mL, T = 300 K. When T = 150 K and P = 160 kPa, what is the new volume?

    • 35.0 mL
    • 52.5 mL
    • 70.0 mL
    • 105 mL

    V₂ = P₁V₁T₂/(T₁P₂) = (240×70.0×150)/(300×160) = 2,520,000/48,000 = 52.5 mL.

  26. A rigid cylinder contains a gas at STP. The gas is heated to 410 K. What is the new pressure?

    • 0.67 atm
    • 0.50 atm
    • 1.5 atm
    • 2.0 atm

    Gay-Lussac's Law: P₁/T₁ = P₂/T₂ → P₂ = P₁T₂/T₁ = 1.0 × 410/273 = 1.50 atm ≈ 1.5 atm.

  27. A gas is heated from 293 K to 303 K at constant pressure of 1.0 atm. Original volume is 6.0 L. New volume is

    • 9.0 L
    • 5.8 L
    • 4.0 L
    • 6.2 L

    Charles's Law: V₂ = V₁T₂/T₁ = 6.0 × 303/293 = 6.2 L.

  28. Which graph correctly shows the relationship between pressure and Kelvin temperature for an ideal gas at constant volume?

    • A straight line through the origin (direct relationship)
    • A curved line (inverse relationship)
    • A horizontal line
    • A vertical line

    Gay-Lussac's Law: P ∝ T (Kelvin) at constant volume → straight line through the origin (direct proportion).

Unit 10: Solutions (33)
  1. A solution is below the solubility curve. It is:

    • Supersaturated
    • Unsaturated
    • Saturated
    • Saturated only at high temperature

    Below the curve = unsaturated: more solute can still dissolve at that temperature.

  2. How does increasing temperature affect the solubility of CO₂ gas?

    • Increases it
    • Has no effect
    • Decreases it
    • First increases then decreases

    Gas solubility DECREASES with increasing temperature (molecules gain enough energy to escape the solvent). This is why warm soda goes flat.

  3. The molarity of a solution with 0.50 mol NaCl in 250 mL solution is:

    • 0.50 M
    • 1.0 M
    • 0.125 M
    • 2.0 M

    M = mol/L = 0.50 mol / 0.250 L = 2.0 M.

  4. The statement 'like dissolves like' means that

    • Polar solutes dissolve in polar solvents; nonpolar in nonpolar
    • Water dissolves everything
    • Ionic compounds don't dissolve
    • Temperature doesn't matter

    Polar/ionic solutes dissolve in polar solvents (water). Nonpolar solutes dissolve in nonpolar solvents (hexane, oil).

  5. Stirring a solution increases the rate of dissolving because:

    • It raises the temperature
    • It brings fresh solvent into contact with solute more frequently
    • It increases the surface area
    • It changes the solubility

    Stirring moves saturated solution away from the solute surface and brings fresh solvent into contact — only increases RATE, not total solubility.

  6. Which colligative property explains why salt lowers the freezing point of water on roads?

    • Boiling point elevation
    • Osmotic pressure
    • Freezing point depression
    • Vapor pressure elevation

    Dissolving NaCl in water lowers the freezing point (FP depression) — prevents ice formation.

  7. An electrolyte solution conducts electricity because:

    • Water molecules carry charge
    • Electrons flow through water
    • The solution is acidic
    • Dissolved ions are mobile charge carriers

    Ions in solution are free to move and carry electrical current → electrolytic conduction.

  8. A supersaturated solution is:

    • Above the curve, unstable — will crystallize out
    • Below the curve, stable
    • On the curve, stable
    • The most concentrated possible at any temperature

    Supersaturated = above the solubility curve = more dissolved than maximum → unstable → excess crystallizes out.

  9. Henry's Law states that as pressure increases, gas solubility:

    • Decreases
    • Increases proportionally
    • Stays the same
    • Decreases then increases

    Henry's Law: S = kP. Higher pressure → more gas molecules forced into solution → greater solubility.

  10. If 500 mL of 2.0 M NaCl is diluted to 2.0 L, the new molarity is:

    • 1.0 M
    • 2.0 M
    • 0.50 M
    • 4.0 M

    M₁V₁=M₂V₂ → 2.0×0.500=M₂×2.0 → M₂=0.50 M.

  11. Which has a greater effect on boiling point elevation — 1 mol NaCl or 1 mol sugar dissolved in water?

    • 1 mol sugar — heavier molecule
    • Equal effect — colligative depends only on moles
    • 1 mol NaCl — it's ionic
    • 1 mol NaCl — dissociates into 2 mol ions

    1 mol NaCl → 2 mol particles (Na⁺ + Cl⁻). Colligative properties depend on particle COUNT → NaCl has greater effect.

  12. A saturated solution is best described as:

    • A solution containing the maximum amount of dissolved solute at that temperature
    • A concentrated solution
    • An unstable solution
    • A solution of a strong electrolyte

    Saturated means at maximum capacity for that temperature — on the solubility curve line.

  13. What does ppm measure?

    • Moles per liter
    • (mass solute / mass solution) × 10⁶
    • Grams per 100 g
    • Milligrams per liter always

    ppm = (mass solute / mass solution) × 10⁶. Used for very dilute concentrations (water quality, etc.).

  14. Which factor affects both the rate of dissolving and the equilibrium amount (solubility)?

    • Stirring
    • Particle size (crushing)
    • Temperature (for most solids)
    • Both stirring and crushing

    Temperature affects solubility (the equilibrium position). Stirring and crushing only affect rate, not the final amount.

  15. At 40°C, KNO₃ solubility is about 65 g/100 g H₂O (from Table G). If 50 g is dissolved at 40°C, the solution is:

    • Supersaturated
    • Saturated
    • Cannot be determined
    • Unsaturated

    50 g < 65 g maximum → below the curve → unsaturated.

  16. Water is called the universal solvent because:

    • It is polar and can dissolve many polar and ionic substances
    • It dissolves everything
    • It has a high boiling point
    • It has low vapor pressure

    Water's polarity and H-bonding ability allow it to dissolve many polar and ionic compounds. Not literally universal — nonpolar substances don't dissolve well.

  17. During osmosis, water moves through a semipermeable membrane from a region of

    • high solute concentration to low solute concentration
    • low solute concentration to high solute concentration
    • equal solute concentration to equal solute concentration
    • high temperature to low temperature

    Osmosis: water moves from low solute concentration (high water concentration) to high solute concentration (low water concentration).

  18. What is the concentration of a solution made by dissolving 117 g of NaCl (GFM=58.5) in 2.0 L?

    • 0.50 M
    • 2.0 M
    • 1.0 M
    • 58.5 M

    mol NaCl = 117/58.5 = 2.0 mol. M = 2.0/2.0 = 1.0 M.

  19. A nonelectrolyte in water:

    • Ionizes completely
    • Is always a base
    • Increases conductivity
    • Does not ionize, does not conduct electricity

    Nonelectrolytes (sugar, ethanol) dissolve but don't produce ions → no electrical conductivity.

  20. Which solution has the lowest freezing point?

    • 1 mol CaCl₂ in 1 L water
    • 1 mol sugar in 1 L water
    • 1 mol NaCl in 1 L water
    • 1 mol ethanol in 1 L water

    CaCl₂ → Ca²⁺ + 2Cl⁻ = 3 mol particles (most particles) → greatest FP depression.

  21. Crystallization occurs when a solution becomes:

    • Unsaturated
    • Supersaturated
    • Saturated
    • Dilute

    Crystallization is triggered when a solution becomes supersaturated — more solute is dissolved than the solvent can hold at that temperature.

  22. A hot saturated KNO₃ solution is slowly cooled. What happens?

    • More KNO₃ dissolves
    • Nothing changes
    • Excess KNO₃ crystallizes out
    • The solution becomes unsaturated immediately

    Cooling lowers solubility → solution goes above the curve (supersaturated) → excess KNO₃ crystallizes out.

  23. KNO₃ solubility is 110 g/100 g H₂O at 60°C and 32 g at 20°C. How much crystallizes when cooled from 60°C to 20°C (starting with a saturated solution at 60°C)?

    • 32 g
    • 110 g
    • 142 g
    • 78 g

    Amount that crystallizes = 110 − 32 = 78 g per 100 g H₂O.

  24. A seed crystal is added to a supersaturated solution. It will:

    • Initiate crystallization — solute deposits on it
    • Dissolve instantly
    • Have no effect
    • Make the solution unsaturated

    A seed crystal provides a surface (nucleation site) for solute molecules to begin crystallizing onto.

  25. When a dissolved solute crystallizes out of solution, this process is classified as a

    • chemical change because new bonds form
    • physical change because the same substance is recovered in solid form
    • nuclear change because energy is released
    • electrochemical change

    Crystallization is a physical change — the solute changes from dissolved to solid form, but its chemical identity is unchanged.

  26. Which substance is best purified by fractional crystallization from Table G?

    • NaCl (nearly flat solubility curve)
    • CO₂ (gas, decreasing curve)
    • KNO₃ (steeply rising solubility curve)
    • NaOH

    KNO₃ has a steeply rising solubility curve → large difference between hot and cold solubility → crystallizes out easily and in large amounts on cooling.

  27. What is the primary driving force for crystallization when a solution is cooled?

    • Increased pressure
    • Increased surface area
    • Addition of more solvent
    • Decreased solubility at lower temperature — excess solute can no longer stay dissolved

    Solubility of most solids decreases as temperature falls → what was dissolved now exceeds capacity → crystallizes.

  28. After crystallization, the crystals are separated from the remaining solution (mother liquor) by:

    • Filtration
    • Distillation
    • Chromatography
    • Evaporation

    Filtration separates the solid crystals from the liquid mother liquor — the crystals are too large to pass through filter paper.

  29. According to Table G, how many grams of KNO₃ are needed to saturate 200 grams of water at 70°C?

    • 86 g
    • 268 g
    • 134 g
    • 43 g

    Table G: KNO₃ solubility at 70°C is about 134 g per 100 g H₂O. Since we have 200 g of water (double the reference amount), we need double the solute: 134 × 2 = 268 g.

  30. A flask of water with solid KCl visible at the bottom is sealed. The solid KCl does not dissolve further. The solution is best described as

    • saturated but not at equilibrium
    • unsaturated and at equilibrium
    • saturated and at equilibrium with the solid
    • unsaturated and not at equilibrium

    Solid present with no more dissolving = saturated. The system is at equilibrium: dissolving rate = crystallizing rate.

  31. Why is potassium nitrate classified as an electrolyte?

    • It is a molecular compound
    • It contains a metal
    • It conducts electricity as a solid
    • It releases ions in an aqueous solution

    Electrolytes release ions when dissolved in water → solution conducts electricity. KNO₃ dissociates: K⁺ + NO₃⁻.

  32. Compared to pure water, a solution of CaCl₂ in water at standard pressure has

    • higher BP and lower FP
    • higher BP and higher FP
    • lower BP and lower FP
    • lower BP and higher FP

    Colligative properties: any dissolved solute raises BP and lowers FP. CaCl₂ → 3 particles → larger effect.

  33. Which compound is an electrolyte?

    • C₂H₆
    • H₃PO₄
    • CH₃OH
    • H₂O

    H₃PO₄ is an acid that ionizes in water → electrolyte. C₂H₆ (ethane) and CH₃OH (methanol) are nonelectrolytes. Pure H₂O is a very weak electrolyte.

Unit 11: Thermochemistry (28)
  1. ΔH = +85 kJ. This reaction is:

    • Exothermic
    • At equilibrium
    • Endothermic
    • Spontaneous always

    Positive ΔH = energy absorbed = endothermic.

  2. In an endothermic reaction, the surroundings feel:

    • Warm
    • No change
    • Very hot
    • Cold

    Endothermic absorbs heat from surroundings → surroundings lose energy → surroundings feel cold.

  3. A catalyst affects a PE diagram by:

    • Lowering activation energy (Ea) for both directions
    • Lowering ΔH
    • Raising ΔH
    • Changing reactant/product energies

    A catalyst lowers Ea for BOTH forward and reverse reactions. ΔH (difference between reactant and product PE) does NOT change.

  4. Activation energy is measured from:

    • Zero to the peak
    • Reactants to the peak
    • Products to the peak
    • Reactants to products

    Ea (forward) = peak height ABOVE reactants level. This is the energy needed to reach the activated complex.

  5. If bonds broken require 400 kJ and bonds formed release 550 kJ, ΔH is:

    • +150 kJ (endothermic)
    • +950 kJ
    • −150 kJ (exothermic)
    • −950 kJ

    ΔH = bonds broken − bonds formed = 400 − 550 = −150 kJ → exothermic (formed > broken).

  6. In an exothermic PE diagram, the products are positioned:

    • Higher than reactants
    • At the same level
    • At the peak
    • Lower than reactants

    Exothermic: energy is released → products end at LOWER PE than reactants.

  7. Heat is treated as a reactant in which type of reaction?

    • Endothermic
    • Exothermic
    • Catalyzed
    • Nuclear

    Endothermic: heat is absorbed → write heat on the reactant side (as if it's a substance being consumed).

  8. Entropy increases when:

    • Water freezes
    • A solid dissolves to form a solution
    • Gas condenses to liquid
    • Crystals form from solution

    Dissolving spreads particles throughout solution → more disorder → increased entropy.

  9. Combustion of methane (CH₄ + 2O₂ → CO₂ + 2H₂O) is:

    • Endothermic, +ΔH
    • Neither
    • Exothermic, −ΔH
    • Endothermic with a catalyst

    Combustion is always exothermic (releases heat) → ΔH is negative.

  10. On a PE diagram, the activated complex is located:

    • At the reactants level
    • At the products level
    • Below the reactants
    • At the peak (highest point)

    The activated complex (transition state) is at the maximum energy point — the peak of the PE curve.

  11. For a reaction where ΔH = −200 kJ, which statement correctly describes the potential energy?

    • Products have less PE than reactants
    • Products have more PE than reactants
    • Products and reactants have equal PE
    • PE cannot be compared using ΔH

    ΔH = PE_products − PE_reactants = −200 kJ → products are 200 kJ lower in PE than reactants → exothermic.

  12. Which process results in a decrease in entropy?

    • Melting ice
    • Liquid water freezing to ice
    • Dissolving sugar
    • Dry ice subliming (solid → gas)

    Freezing: liquid → solid = less disorder → decreased entropy (ΔS < 0).

  13. The reverse activation energy (Ea reverse) is measured from:

    • Reactants to peak
    • Zero to peak
    • Products to peak
    • Peak to reactants

    Ea(reverse) = energy needed to go from products back to the activated complex = peak height above products.

  14. Photosynthesis (6CO₂ + 6H₂O → C₆H₁₂O₆ + 6O₂) is:

    • Exothermic, −ΔH
    • At equilibrium
    • Catalyzed by H₂
    • Endothermic, +ΔH

    Photosynthesis absorbs light energy to build glucose → endothermic, +ΔH.

  15. A catalyst speeds up a reaction by:

    • Lowering the activation energy
    • Increasing reactant concentration
    • Adding more particles
    • Raising the temperature

    A catalyst provides an alternate reaction pathway with lower Ea → more collisions have sufficient energy → faster rate.

  16. In an exothermic reaction at equilibrium, heat is treated as a:

    • Reactant
    • Product
    • Catalyst
    • Solvent

    Exothermic: heat is released → heat appears as a PRODUCT in the reaction equation.

  17. The Gibbs free energy equation is ΔG = ΔH − TΔS. A reaction is spontaneous when:

    • ΔG > 0
    • ΔG = 0
    • ΔG < 0
    • ΔH = 0

    ΔG < 0 (negative Gibbs free energy) indicates a spontaneous reaction under the given conditions.

  18. Which statement correctly describes the breaking of the O=O bond in O₂?

    • It releases energy and is exothermic
    • It is a physical change and involves no energy
    • It is catalyzed by a transition metal
    • It requires energy and is endothermic

    Breaking bonds always requires energy input → endothermic. Only forming bonds releases energy.

  19. For a reaction: ΔH = +50 kJ. At higher temperature, Le Chatelier predicts equilibrium shifts:

    • Right (toward products) because heat is a reactant
    • Left (toward reactants)
    • No shift
    • Stops the reaction

    Endothermic (+ΔH): heat is a reactant. Adding heat (raising T) shifts toward products (right).

  20. Which correctly describes Hess's Law?

    • ΔH depends on pathway
    • ΔH of a reaction = sum of ΔH values for individual steps (state function)
    • Catalysts change ΔH
    • Only exothermic reactions have ΔH

    Hess's Law: overall ΔH = sum of ΔH values for each step. ΔH is a state function — path-independent.

  21. Based on Table I, which compound produces an exothermic process when dissolved in water at 298 K?

    • KNO₃(s)
    • NH₄Cl(s)
    • NaOH(s)
    • NH₄NO₃(s)

    NaOH dissolving has a negative ΔH in Table I → exothermic (solution warms). The others have positive ΔH → endothermic.

  22. Systems in nature tend to undergo changes that result in:

    • Lower energy and less disorder
    • Higher energy and less disorder
    • Higher energy and greater disorder
    • Lower energy and greater disorder

    Nature favors: lower potential energy (exothermic) AND greater disorder (higher entropy). ΔG = ΔH − TΔS → spontaneous when ΔG < 0.

  23. The heat of reaction equals PE of products minus PE of reactants. If this value is negative:

    • The reaction is exothermic
    • The reaction is endothermic
    • No energy change occurred
    • The catalyst was used

    ΔH = PE_products − PE_reactants. Negative value → products are lower in energy than reactants → energy released → exothermic.

  24. What is the heat required to completely vaporize 12.5 g of H₂O at 100°C? (H_v = 2260 J/g)

    • 4180 J
    • 28300 J
    • 5230 J
    • 19500 J

    q = mH_v = 12.5 g × 2260 J/g = 28,250 J ≈ 28,300 J. Use H_v because it's a phase change (flat section).

  25. In the equation Cu + S → CuS + energy, why is the energy term written to the right of the arrow?

    • CuS is composed of two metals
    • CuS is composed of two nonmetals
    • Energy is released as bonds in CuS form
    • Energy is absorbed as bonds in CuS form

    Forming bonds releases energy (exothermic). Energy appears as a product when bond formation releases it → written on the product side.

  26. Which change is exothermic (releases energy)?

    • Sublimation of iodine
    • Melting of iron
    • Vaporization of ethanol
    • Freezing of water

    Freezing = liquid→solid: IMFs form, PE decreases, energy released to surroundings → exothermic. Sublimation, melting, and vaporization all absorb energy (endothermic).

  27. Salt A is dissolved in water and the solution temperature decreases. Salt B is dissolved and temperature increases. Which conclusion is correct?

    • Dissolving Salt A is endothermic; Salt B is exothermic
    • Dissolving Salt A is exothermic; Salt B is endothermic
    • Both are exothermic
    • Both are endothermic

    Solution cooling = heat absorbed from surroundings = endothermic (Salt A). Solution warming = heat released = exothermic (Salt B).

  28. Which change results in an increase in disorder (entropy)?

    • H₂O(g) → H₂O(l)
    • I₂(s) → I₂(g)
    • NaCl(aq) → NaCl(s)
    • CO₂(g) → CO₂(s)

    Solid → gas (sublimation) greatly increases disorder → entropy increases. All other options go from more to less disordered states.

Unit 12: Equilibrium & Kinetics (28)
  1. At equilibrium, the forward and reverse rates are:

    • Zero
    • Unequal
    • Equal to each other
    • Constantly changing

    Chemical equilibrium: forward rate = reverse rate. Both reactions continue but at equal speeds.

  2. Which change does not affect the equilibrium position?

    • Adding reactant
    • Changing temperature
    • Increasing pressure (for gas reactions)
    • Adding a catalyst

    A catalyst speeds attainment of equilibrium but does NOT change the equilibrium position (concentrations at equilibrium).

  3. For N₂ + 3H₂ ⇌ 2NH₃ + heat, increasing temperature shifts equilibrium:

    • Left, toward N₂ and H₂
    • Right, toward more NH₃
    • No shift
    • Toward a catalyst

    Heat is a product (exothermic). Adding heat = adding product → system shifts LEFT to relieve stress.

  4. Collision theory states that which three conditions must be met for a reaction to occur?

    • High T, pressure, catalyst
    • Collision + proper orientation + energy ≥ Ea
    • Collision + color change + temperature drop
    • Large surface area, pressure, concentration

    All three required: (1) collision, (2) proper orientation, (3) energy ≥ Ea. Missing any = no reaction.

  5. Removing a product from an equilibrium mixture shifts it:

    • Toward reactants
    • No effect
    • Toward products (to replace the removed product)
    • Toward the catalyst

    Removing product = stress on product side → system shifts RIGHT to replace it (toward products).

  6. For the reaction: N₂(g) + 3H₂(g) ⇌ 2NH₃(g), increasing pressure shifts equilibrium:

    • Left (toward 4 mol gas)
    • No effect
    • Only if temperature changes
    • Right (toward 2 mol gas — fewer moles)

    Higher pressure → shift toward fewer moles of gas. Left side has 4 mol gas, right has 2 → shifts RIGHT.

  7. Which statement best describes a system at dynamic equilibrium?

    • Both reactions proceed at equal rates; concentrations remain constant
    • The forward reaction has stopped completely
    • Only the forward reaction occurs
    • Equilibrium shifts continuously

    Dynamic = still occurring in both directions at equal rates. Not static — concentrations stay constant but both reactions continue.

  8. Increasing surface area of a solid reactant affects:

    • Only equilibrium position
    • Only the reaction rate (more collision sites)
    • Both rate and equilibrium
    • The Keq value

    Greater surface area = more exposed particles = faster rate. Doesn't change Keq or equilibrium concentrations.

  9. Which factor increases reaction rate AND shifts equilibrium for an endothermic reaction?

    • Adding a catalyst
    • Adding an inert gas
    • Increasing temperature
    • Decreasing pressure

    Temperature increase: speeds reaction (rate ↑) AND shifts equilibrium toward products for an endothermic reaction (heat is reactant).

  10. For an exothermic reaction at equilibrium, adding more reactant shifts equilibrium:

    • Left
    • No shift
    • Depends on temperature
    • Right (to consume excess reactant and form more product)

    Adding reactant = stress on reactant side → system shifts AWAY from it (right), toward products.

  11. Keq = [C]²[D] / [A][B]³ is the expression for: aA + bB ⇌ cC + dD. What are a, b, c, d?

    • a=1, b=3, c=2, d=1
    • a=3, b=1, c=1, d=2
    • a=2, b=1, c=1, d=3
    • a=1, b=2, c=3, d=1

    Keq = [products]^coefficients / [reactants]^coefficients. So a=1 (A¹), b=3 (B³), c=2 (C²), d=1 (D¹).

  12. An inert gas added to a sealed container at constant volume:

    • Shifts equilibrium right
    • Does not affect equilibrium
    • Shifts equilibrium left
    • Increases Keq

    Inert gas at constant volume doesn't change partial pressures of reactants/products → no equilibrium shift.

  13. Ionic reactions in aqueous solution are generally faster than molecular reactions because:

    • Ions are heavier
    • Ions are nonpolar
    • No bonds need to be broken before ions can react
    • Molecular reactions require high temperature

    Ions in solution interact immediately through electrostatic attraction — no covalent bonds to break first.

  14. Which is true of a catalyst in an equilibrium system?

    • It shifts equilibrium toward products
    • It increases Keq
    • It changes ΔH
    • It lowers Ea for both directions, reaching equilibrium faster but not shifting it

    A catalyst lowers Ea equally for forward and reverse → reaches equilibrium faster → same equilibrium position and same Keq.

  15. For CO(g) + 3H₂(g) ⇌ CH₄(g) + H₂O(g), decreasing pressure shifts equilibrium:

    • Left (toward more moles of gas — 4 mol)
    • Right (fewer moles)
    • No shift
    • Only if T changes

    Left side: 4 mol gas. Right side: 2 mol gas. Decrease pressure → shift toward MORE moles → LEFT.

  16. The equilibrium expression excludes:

    • Gaseous species
    • Pure solids and pure liquids
    • Dissolved ions
    • Spectator ions

    Keq excludes pure solids and pure liquids — their concentrations don't change and are incorporated into the constant.

  17. Which correctly explains why crushing a solid increases reaction rate?

    • It lowers the activation energy
    • It increases the temperature
    • It exposes more surface area, allowing more collision sites
    • It changes the equilibrium constant

    Smaller particles = greater surface area = more surface molecules available to collide with reactant → faster rate.

  18. At equilibrium, concentrations of reactants and products are:

    • Equal
    • Both zero
    • Always 50/50
    • Constant (not necessarily equal)

    At equilibrium: concentrations remain CONSTANT over time, but they're not necessarily equal to each other.

  19. Which factor will shift the position of a chemical equilibrium?

    • Changing the temperature
    • Adding a catalyst
    • Adding an inert gas at constant V
    • Changing the container material

    Temperature change alters the rate of both reactions differently (activating Arrhenius dependence) → equilibrium position shifts.

  20. If concentration of product is increased, Keq:

    • Increases
    • Stays the same
    • Decreases
    • Doubles

    Keq is a constant at a given temperature — it doesn't change when concentrations change. The system just shifts to re-establish the same ratio.

  21. A sealed 100-mL flask contains 50 g of water at 25°C. Which term best describes this system?

    • Chemical equilibrium only
    • Condensation only
    • Physical equilibrium only
    • Evaporation only

    Sealed flask with liquid water: evaporation rate = condensation rate → liquid-vapor physical equilibrium. No chemical reaction occurs.

  22. On a concentration-vs-time graph, equilibrium is established at the point where:

    • Reactant concentration reaches zero
    • Concentrations of reactants and products become equal
    • The forward rate becomes zero
    • All concentration curves become flat and stop changing

    Equilibrium = no further net change in concentrations → all curves level off and stay flat. Rates are equal (not zero), concentrations are constant (not necessarily equal).

  23. Given: H₂(g) + I₂(g) + energy ⇌ 2HI(g). When the temperature is increased, the equilibrium shifts to the

    • right, and the concentration of HI(g) increases
    • right, and the concentration of HI(g) decreases
    • left, and the concentration of HI(g) decreases
    • left, and the concentration of HI(g) increases

    Heat is a reactant (endothermic — energy on the left). Adding heat → shift RIGHT (toward products) → more HI forms → HI concentration increases.

  24. In the reaction Fe(s) + HCl(aq), which conditions produce the fastest rate?

    • Iron strip at 273 K
    • Powdered iron at 303 K
    • Iron strip at 303 K
    • Powdered iron at 273 K

    Fastest rate: maximum surface area (powder) + maximum temperature (303 K). Both factors increase collision frequency and energy.

  25. Hydrochloric acid reacts faster with powdered zinc than with an equal mass of zinc strips because powdered zinc has

    • lower activation energy
    • higher temperature
    • greater surface area exposed to the acid
    • a different molecular formula

    Crushing/powdering increases surface area → more Zn atoms exposed to HCl → more frequent collisions → faster reaction rate.

  26. A catalyst increases the rate of a reaction by

    • providing an alternate pathway with a higher activation energy
    • providing the same pathway with a higher activation energy
    • increasing the concentration of reactants
    • providing an alternate pathway with a lower activation energy

    A catalyst provides an alternate reaction pathway with a LOWER activation energy → more collisions have sufficient energy → faster rate.

  27. Increasing the temperature of a reaction increases the rate by

    • increasing the frequency of effective collisions
    • lowering the activation energy
    • increasing the activation energy
    • decreasing the frequency of collisions

    Higher temperature → faster-moving particles → more frequent collisions AND more collisions with energy ≥ Ea → increased rate.

  28. A chemical reaction between iron atoms and oxygen molecules can only occur if

    • the particles are heated above 100°C
    • there are effective collisions between the particles
    • a catalyst is always present
    • atmospheric pressure decreases

    Collision theory: reactions require collisions with proper orientation AND sufficient energy. Not all reactions need heating or a catalyst.

Unit 13: Acids, Bases & Salts (29)
  1. [H⁺] = 1×10⁻⁵ M. The pH is:

    • −5
    • 9
    • 5
    • 10

    pH = −log[H⁺] = −log(10⁻⁵) = 5.

  2. A solution has pH = 9. It is:

    • Acidic
    • Neutral
    • Strongly acidic
    • Basic

    pH > 7 = basic.

  3. pOH of a solution with pH = 3 is:

    • 11
    • 3
    • 7
    • 14

    pH + pOH = 14 → pOH = 14 − 3 = 11.

  4. Which substance is classified as a strong acid?

    • Acetic acid (CH₃COOH)
    • Nitric acid (HNO₃)
    • Hydrofluoric acid (HF)
    • Carbonic acid (H₂CO₃)

    HNO₃ is one of the 6 strong acids (HCl, HBr, HI, HNO₃, H₂SO₄, HClO₄). The others listed are weak acids.

  5. An Arrhenius base in water releases:

    • H⁺
    • H₂
    • OH⁻
    • Na⁺

    Arrhenius base releases hydroxide ions (OH⁻) in aqueous solution.

  6. A Brønsted-Lowry acid is defined as a proton:

    • Acceptor
    • Carrier
    • Neutralizer
    • Donor

    Brønsted-Lowry acid donates an H⁺ (proton) to a base.

  7. Acid + base → ??? + water

    • Salt
    • Acid
    • Base
    • Oxide

    Neutralization: acid + base → salt + water. The salt contains the cation from the base and anion from the acid.

  8. In a titration, 25.0 mL of 0.40 M HCl neutralizes a NaOH solution. If 50.0 mL of NaOH was used, its molarity is:

    • 0.10 M
    • 0.20 M
    • 0.40 M
    • 0.80 M

    M_A×V_A = M_B×V_B → 0.40×25.0 = M_B×50.0 → M_B = 10/50 = 0.20 M.

  9. The indicator phenolphthalein is colorless in acid and pink in base. At pH = 5, it is:

    • Pink
    • Red
    • Colorless
    • Yellow

    Phenolphthalein is colorless in acid (pH < 8.2) and pink in base. pH 5 is acidic → colorless.

  10. How much more acidic is a solution at pH 2 compared to pH 4?

    • 10×
    • 1000×
    • 100×

    pH is logarithmic: difference of 2 pH units = 10² = 100× difference in [H⁺].

  11. The Kw of water at 25°C is:

    • 1×10⁻¹⁴
    • 1×10⁻⁷
    • 7
    • 14

    Kw = [H⁺][OH⁻] = 1×10⁻¹⁴ at 25°C. In pure water: [H⁺] = [OH⁻] = 1×10⁻⁷.

  12. Which substance can act as both an acid and a base (amphoteric)?

    • HCl
    • H₂O
    • NaOH
    • NaCl

    Water is amphoteric: can donate H⁺ (act as acid) or accept H⁺ (act as base). Also: HCO₃⁻.

  13. A weak acid in water:

    • Fully dissociates
    • Does not dissolve
    • Partially dissociates, reaches equilibrium
    • Has pH < 0

    Weak acids only partially ionize — an equilibrium is established between the acid and its ions.

  14. Litmus is red in acid and blue in base. A litmus paper turns RED in an unknown solution. The solution is:

    • Basic (pH > 7)
    • Neutral (pH = 7)
    • Unknown
    • Acidic (pH < 7)

    Litmus turns red in acid (pH < 7).

  15. The conjugate base of H₂CO₃ is:

    • HCO₃⁻
    • CO₃²⁻
    • H₂O
    • OH⁻

    Conjugate base = acid minus one H⁺. H₂CO₃ − H⁺ = HCO₃⁻ (bicarbonate).

  16. [OH⁻] in a solution with pH = 11 is:

    • 1×10⁻¹¹ M
    • 1×10⁻³ M
    • 1×10⁻⁷ M
    • 11 M

    pOH = 14 − 11 = 3. [OH⁻] = 10⁻³ = 1×10⁻³ M.

  17. When HCl dissolves in water, it produces:

    • H₂ gas
    • OH⁻ ions
    • H⁺ (H₃O⁺) and Cl⁻ ions
    • Cl₂ gas

    HCl is a strong acid: HCl → H⁺ + Cl⁻. The H⁺ combines with water to form H₃O⁺.

  18. In a neutralization reaction, the salt that forms contains

    • the cation of the acid and the anion of the base
    • the hydrogen ion from the acid and the hydroxide from the base
    • equal parts of the acid and base unchanged
    • the anion of the acid and the cation of the base

    Salt = anion from the acid + cation from the base. HCl + NaOH → NaCl: Cl⁻ (from acid) + Na⁺ (from base).

  19. A solution with [H⁺] = 1×10⁻⁷ M is:

    • Neutral
    • Acidic
    • Basic
    • Strongly acidic

    pH = −log(10⁻⁷) = 7. pH = 7 = neutral.

  20. In a 1:1 titration, the equivalence point is reached when:

    • pH = 7
    • Moles of acid = moles of base
    • Indicator changes color
    • The solution is neutral

    Equivalence point: mol H⁺ = mol OH⁻ (complete neutralization). For HCl + NaOH, this happens at pH 7, but not always (depends on acid/base strengths).

  21. When pH changes from 4.0 to 7.0, what happens to the concentration of hydronium ions?

    • Increases by factor of 3
    • Increases by factor of 1000
    • Decreases by factor of 1000
    • Decreases by factor of 3

    pH increases by 3 units → [H⁺] decreases by 10³ = 1000. pH 4 to pH 7 = 1000× less acidic.

  22. NH₃ + H₂O ⇌ NH₄⁺ + OH⁻. In the reverse reaction, which species donates an H⁺ ion?

    • NH₃
    • H₂O
    • OH⁻
    • NH₄⁺

    In the reverse reaction, NH₄⁺ → NH₃ + H⁺ (donates a proton) → NH₄⁺ is the Brønsted-Lowry acid in the reverse direction.

  23. What color is methyl orange indicator in a basic solution (e.g., NaOH)?

    • Yellow
    • Red
    • Orange
    • Blue

    Methyl orange: red in acid (pH < 3.1), yellow in base (pH > 4.4). NaOH is strongly basic → methyl orange is YELLOW.

  24. 15.0 mL of HCl(aq) is neutralized by 25.2 mL of 0.50 M NaOH. What is the molarity of the HCl?

    • 0.50 M
    • 0.84 M
    • 1.0 M
    • 1.7 M

    M_A × V_A = M_B × V_B → M_A × 15.0 = 0.50 × 25.2 → M_A = 12.6/15.0 = 0.84 M.

  25. In the reversible reaction CH₃COOH + H₂O ⇌ CH₃COO⁻ + H₃O⁺, the two species that can donate an H⁺ in the equation are

    • CH₃COOH and H₂O
    • CH₃COO⁻ and H₂O
    • CH₃COOH and H₃O⁺
    • CH₃COO⁻ and H₃O⁺

    In the forward reaction: CH₃COOH donates H⁺. In the reverse reaction: H₃O⁺ donates H⁺ back. These two are both H⁺ donors (Brønsted-Lowry acids) in the overall equation.

  26. Which solution is the best conductor of electric current?

    • 0.001 mol NaCl in 1000 mL water
    • 0.005 mol NaCl in 1000 mL water
    • 0.05 mol NaCl in 1000 mL water
    • 0.1 mol NaCl in 1000 mL water

    More dissolved ions → better conductivity. 0.1 mol NaCl provides the most ions (0.1 mol Na⁺ + 0.1 mol Cl⁻) → best conductor.

  27. Phenolphthalein indicator is pink in an aqueous solution with a pH of

    • 12
    • 5
    • 2
    • 7

    Phenolphthalein is colorless at pH < 8.2 and pink at pH > 10. pH = 12 is strongly basic → pink/fuchsia.

  28. What is the color of bromcresol green indicator in a solution with a pH of 2.0?

    • Blue
    • Yellow
    • Green
    • Red

    Table M: Bromcresol green is yellow in acid (pH < 3.8) and blue in base (pH > 5.4). pH 2.0 is acidic → yellow.

  29. Compared to a 1.0-liter solution at pH 7.0, a 1.0-liter solution at pH 5.0 contains

    • 100 times fewer H⁺ ions
    • 2 times more H⁺ ions
    • 100 times more H⁺ ions
    • the same number of H⁺ ions

    pH 5.0 vs pH 7.0: difference of 2 units → [H⁺] differs by 10² = 100×. pH 5 has 100× more H⁺ than pH 7.

Unit 14: Redox & Electrochemistry (30)
  1. In the mnemonic OIL RIG, 'RIG' means:

    • loss of electrons
    • transfer of protons
    • release of photons
    • gain of electrons

    OIL RIG: Oxidation Is Loss, Reduction Is Gain of electrons.

  2. The oxidation number of Cr in Cr₂O₃ is:

    • +3
    • +2
    • +6
    • −2

    O = −2 (×3 = −6 per Cr). For neutral compound: 2(Cr) + (−6) = 0 → 2Cr = +6 → Cr = +3.

  3. In Cu + 2AgNO₃ → Cu(NO₃)₂ + 2Ag, copper is:

    • Reduced
    • Oxidized
    • Unchanged
    • The oxidizing agent

    Cu → Cu²⁺: loses 2 electrons → oxidized. Cu is the REDUCING agent (it donates electrons to reduce Ag⁺).

  4. In a voltaic cell, the electron flow in the external circuit is from:

    • Cathode to anode
    • Salt bridge to cathode
    • Anode to cathode
    • Solution to wire

    Electrons are produced at the anode (oxidation) and flow through external wire to cathode (reduction).

  5. Which half-reaction represents a reduction?

    • Zn → Zn²⁺ + 2e⁻
    • Na → Na⁺ + e⁻
    • Al → Al³⁺ + 3e⁻
    • Fe³⁺ + e⁻ → Fe²⁺

    Fe³⁺ + e⁻ → Fe²⁺: electrons GAINED by Fe³⁺ → reduction.

  6. What is the oxidation number of S in H₂SO₄?

    • +6
    • −2
    • +4
    • 0

    H=+1(×2=+2), O=−2(×4=−8). Sum=0 → +2 + S − 8 = 0 → S = +6.

  7. An electrolytic cell is used for:

    • Generating spontaneous electrical energy
    • Driving nonspontaneous reactions using external power (electroplating, electrolysis)
    • Measuring pH
    • Storing nuclear energy

    Electrolytic cells use external electrical energy to drive nonspontaneous reactions (electroplating, electrolysis of water).

  8. In ANY electrochemical cell, oxidation always occurs at the

    • Positive electrode
    • Negative electrode
    • Anode
    • Cathode

    Oxidation ALWAYS at the anode — regardless of cell type. (Anode starts with vowel, as does Oxidation.)

  9. What is the oxidation state of Mn in MnO₄⁻ (permanganate)?

    • +4
    • +6
    • −2
    • +7

    O=−2(×4=−8). Ion charge=−1. Mn + (−8) = −1 → Mn = +7.

  10. A reducing agent:

    • Loses electrons and causes reduction of another substance
    • Gains electrons and is reduced
    • Gains protons
    • Is always a metal

    Reducing agent: loses electrons (is itself OXIDIZED) → causes another substance to be reduced.

  11. In the half-reaction Zn²⁺ + 2e⁻ → Zn, electrons appear as reactants. This half-reaction represents

    • Oxidation
    • Reduction
    • Neither
    • Neutralization

    Electrons as reactants (on the left) = electrons being GAINED = reduction.

  12. The salt bridge in a voltaic cell allows:

    • Electron flow between half-cells
    • Energy storage
    • Ion flow to maintain electrical neutrality
    • Prevention of reactions

    Salt bridge: ions (not electrons) flow through it to maintain charge balance in each half-cell.

  13. To balance a redox equation, the number of electrons lost must equal:

    • The number of protons gained
    • The number of atoms changed
    • The activation energy
    • The number of electrons gained

    In any redox reaction: e⁻ lost by reducing agent = e⁻ gained by oxidizing agent. Charge must be conserved.

  14. What is the oxidation number of Fe in Fe₂O₃?

    • +3
    • +1
    • +2
    • −2

    O=−2(×3=−6). For neutral: 2Fe + (−6) = 0 → 2Fe = +6 → Fe = +3.

  15. Table J (activity series) is used to determine whether:

    • A double replacement reaction occurs
    • A single replacement reaction is spontaneous
    • An acid-base reaction occurs
    • A gas forms in decomposition

    Table J: a single replacement reaction is spontaneous if the replacing element is HIGHER (more active) on the list.

  16. In a voltaic cell, at the cathode, the mass of the electrode

    • Decreases (metal dissolves)
    • Stays the same
    • Increases (metal deposits)
    • Becomes an ion

    At the cathode: metal ions in solution gain electrons → deposit as solid metal → electrode mass increases.

  17. Identify the oxidizing agent in: Fe + CuSO₄ → FeSO₄ + Cu

    • Fe
    • FeSO₄
    • SO₄²⁻
    • Cu²⁺ (in CuSO₄)

    Cu²⁺ is REDUCED (gains electrons, goes to Cu). The oxidizing agent is the species that accepts electrons → Cu²⁺.

  18. In electrolysis of water, which gas forms at the cathode?

    • H₂
    • O₂
    • Cl₂
    • N₂

    Cathode = reduction. 2H⁺ + 2e⁻ → H₂. Hydrogen gas forms at cathode; oxygen at anode.

  19. The oxidation number of H in NaH (sodium hydride) is:

    • +1
    • −1
    • 0
    • +2

    In metal hydrides (NaH, CaH₂), hydrogen is −1 (the metal is more electropositive than H).

  20. In a voltaic cell, the anode terminal is:

    • Positive (+)
    • Neutral
    • Negative (−)
    • Alternates

    In a voltaic (galvanic) cell: anode = negative (−); cathode = positive (+). Signs flip in electrolytic cells.

  21. What is the oxidation state of chlorine in KClO₃?

    • +1
    • −1
    • +7
    • +5

    K = +1, O = −2 (×3 = −6). Sum must = 0: +1 + Cl − 6 = 0 → Cl = +5.

  22. In the voltaic cell: Ni²⁺(aq) + Zn(s) → Ni(s) + Zn²⁺(aq), which electrode is the anode?

    • Zn electrode
    • Ni electrode
    • Salt bridge
    • Voltmeter

    Zn is oxidized (Zn → Zn²⁺ + 2e⁻) → oxidation occurs at the anode → Zn electrode is the anode.

  23. In the voltaic cell above, what form of energy is converted to electrical energy?

    • Nuclear energy
    • Chemical energy
    • Light energy
    • Heat energy

    Voltaic cells convert chemical energy (from spontaneous redox reactions) into electrical energy.

  24. Write the half-reaction at the nickel electrode when the cell operates: Ni²⁺(aq) + Zn(s) → Ni(s) + Zn²⁺(aq)

    • Ni → Ni²⁺ + 2e⁻ (oxidation)
    • Zn → Zn²⁺ + 2e⁻
    • Ni²⁺ + 2e⁻ → Ni (reduction)
    • Zn²⁺ + 2e⁻ → Zn

    Ni electrode is the cathode (Ni²⁺ is reduced). Half-reaction: Ni²⁺(aq) + 2e⁻ → Ni(s).

  25. In the reaction 4HCl + MnO₂ → MnCl₂ + 2H₂O + Cl₂, what happens to manganese?

    • Mn is reduced, oxidation number changes from +2 to +4
    • Mn is oxidized, oxidation number changes from +2 to +4
    • Mn is oxidized, oxidation number changes from +4 to +2
    • Mn is reduced, oxidation number changes from +4 to +2

    In MnO₂: Mn = +4. In MnCl₂: Mn = +2. Oxidation number decreased (+4 → +2) → gained electrons → reduction.

  26. In the reaction 3CuCl₂ + 2Al → 3Cu + 2AlCl₃, what change occurs to the oxidation number of copper?

    • +2 to 0
    • +2 to +1
    • +6 to +3
    • +1 to 0

    Cu in CuCl₂ = +2. Cu in product = 0 (free element). Cu²⁺ gains 2 electrons → reduced. Oxidation number: +2 → 0.

  27. In the reaction Mg(s) + 2H⁺(aq) + 2Cl⁻(aq) → Mg²⁺(aq) + 2Cl⁻(aq) + H₂(g), which species undergoes oxidation?

    • Cl⁻(aq)
    • Mg(s)
    • H⁺(aq)
    • H₂(g)

    Mg(s) → Mg²⁺: loses 2 electrons → oxidation. Cl⁻ is a spectator; H⁺ gains electrons (reduction).

  28. In 2KClO₃(s) → 2KCl(s) + 3O₂(g), the oxidation state of chlorine changes from

    • −1 to +5
    • −1 to +1
    • +5 to −1
    • +1 to −1

    In KClO₃: K=+1, O=−2(×3=−6) → Cl = +5. In KCl: K=+1, Cl=−1. Cl goes from +5 → −1 (gains 6 electrons per Cl → reduction).

  29. In the reaction 2Al + 3Cu²⁺ → 2Al³⁺ + 3Cu, the reduction half-reaction is

    • Cu²⁺ → Cu + 2e⁻
    • Al → Al³⁺ + 3e⁻
    • Al + 3e⁻ → Al³⁺
    • Cu²⁺ + 2e⁻ → Cu

    Reduction = gain of electrons. Cu²⁺ gains 2e⁻ → Cu. Half-reaction: Cu²⁺ + 2e⁻ → Cu.

  30. In an electrolytic cell, the anode is the

    • positive electrode where oxidation occurs
    • negative electrode where reduction occurs
    • positive electrode where reduction occurs
    • negative electrode where oxidation occurs

    In an electrolytic cell: anode = positive (+) terminal, and oxidation ALWAYS occurs at the anode. (Signs flip from voltaic cell, but anode = oxidation never changes.)

Unit 15: Nuclear Chemistry (30)
  1. In alpha decay, the mass number changes by:

    • −1
    • −4
    • 0
    • +2

    Alpha particle = ⁴₂He: mass number decreases by 4.

  2. Which type of radiation has no mass and no charge?

    • Alpha
    • Beta
    • Gamma
    • Positron

    Gamma radiation: photon (⁰₀γ) — no mass, no charge, most penetrating.

  3. In beta (β⁻) decay, atomic number:

    • Decreases by 2
    • Decreases by 1
    • Stays the same
    • Increases by 1

    Beta decay: neutron → proton + electron. One more proton → atomic number +1.

  4. The half-life of a substance is constant. What does it NOT depend on?

    • Both the temperature and the mass of the sample
    • The identity of the isotope
    • The temperature of the sample
    • The mass of the original sample

    Half-life is constant for a given isotope and is unaffected by temperature, pressure, or the amount of sample present — only the isotope's identity determines it.

  5. 80 g of a radioisotope decays to 5 g. How many half-lives passed?

    • 3
    • 4
    • 5
    • 16

    80→40→20→10→5: 4 half-lives. Each step = one half-life.

  6. In ²¹⁰₈₃Bi → ⁴₂He + X, what is X?

    • ²⁰⁶₈₅At
    • ²¹⁴₈₅At
    • ²⁰⁶₈₁Tl
    • ²¹⁰₈₁Tl

    Mass: 210−4=206. Atomic#: 83−2=81. Element 81 = Thallium → ²⁰⁶₈₁Tl.

  7. Which has the greatest penetrating power?

    • Alpha
    • Beta
    • Neutrons
    • Gamma

    Gamma has no charge and no mass → penetrates deeply. Stopped only by thick lead or concrete.

  8. Fission produces energy because:

    • Small amounts of mass are converted to energy (E=mc²)
    • Electrons are lost
    • Bonds are formed in a solution
    • Entropy decreases

    In fission, the products have slightly less mass than reactants → mass deficit converted to energy via E = mc².

  9. Which isotope is used in carbon dating? (t₁/₂ ≈ 5715 yr)

    • C-12
    • C-14
    • C-13
    • C-11

    C-14 is radioactive with t₁/₂ = 5715 yr. Living organisms maintain constant C-14; after death it decays.

  10. In nuclear fission of U-235, what sustains the chain reaction?

    • Electrons emitted
    • Alpha particles
    • Neutrons released by each fission event trigger more fissions
    • Gamma radiation

    Each fission releases 2-3 neutrons → these collide with other U-235 nuclei → chain reaction.

  11. A positron (β⁺) has the same mass as an electron but:

    • Same charge
    • No charge
    • Double the charge
    • Opposite charge (+1)

    Positron: same mass as electron (~0 amu) but opposite charge (+1). It is the antiparticle of the electron.

  12. After 3 half-lives, what fraction of original sample remains?

    • 1/8
    • 1/2
    • 1/4
    • 1/16

    (½)³ = 1/8 remains after 3 half-lives.

  13. Gamma radiation is stopped by:

    • A sheet of paper
    • Thick lead or concrete
    • Thin aluminum
    • Skin

    Gamma: most penetrating. Requires thick lead or concrete to attenuate significantly.

  14. Which process involves combining light nuclei to form a heavier nucleus?

    • Fission
    • Alpha decay
    • Fusion
    • Transmutation

    Fusion: light nuclei (e.g., H isotopes) combine → heavier nucleus + enormous energy. Powers the sun.

  15. In ¹⁴₆C → ⁰₋₁e + X, element X is:

    • ¹⁴₆C
    • ¹⁴₅B
    • ¹³₆C
    • ¹⁴₇N

    Mass: 14−0=14. Atomic#: 6+1=7 → element 7 = Nitrogen. ¹⁴₇N.

  16. Which medical application uses radiation from I-131?

    • Thyroid treatment and imaging
    • Brain imaging
    • Bone density scans
    • Anesthesia

    I-131 (half-life: 8.1 days) is used for diagnosing and treating thyroid conditions — it concentrates in the thyroid.

  17. Nuclear reactions differ from chemical reactions in that nuclear reactions:

    • Involve electrons
    • Change the identity of elements (transmutation)
    • Obey conservation of mass
    • Require catalysts

    Nuclear reactions change proton count → change the element identity (transmutation). Chemical reactions never change the element.

  18. Fusion requires extreme temperatures because:

    • Nuclei have negative charges that attract
    • Electrons must be removed first
    • Protons must overcome electrostatic REPULSION to get close enough to fuse
    • Gravity is needed

    Nuclei are positively charged → repel each other. Extreme KE (temperature) is needed to overcome this repulsion and bring nuclei close enough to fuse.

  19. Which type of decay does NOT change the mass number?

    • Alpha only
    • Alpha and beta
    • Only gamma
    • Beta and positron (and gamma)

    Beta: mass unchanged, atomic# +1. Positron: mass unchanged, atomic# −1. Gamma: no changes. Alpha: mass −4. So beta, positron, and gamma don't change mass number.

  20. A 100 g sample with t₁/₂ = 20 years. How much remains after 60 years?

    • 12.5 g
    • 50 g
    • 25 g
    • 6.25 g

    60 ÷ 20 = 3 half-lives. (½)³ × 100 = 12.5 g.

  21. A radioactive emission travels straight through an electric field without being deflected. It is:

    • Alpha particle
    • Gamma radiation
    • Beta particle
    • Positron

    Gamma radiation has no charge → not deflected by electric or magnetic fields. Alpha (+2) deflects toward negative plate; beta (−1) and positron (+1) deflect in opposite directions.

  22. Based on Table N, what is the decay mode of tritium (H-3)?

    • Alpha
    • Gamma
    • Beta (β⁻)
    • Positron

    Table N: H-3 (tritium) undergoes beta-minus (β⁻) decay. A neutron converts to a proton + high-speed electron.

  23. H-3 has a half-life of 12.31 years. What fraction of an original sample remains after 36.93 years?

    • 1/2
    • 1/4
    • 1/16
    • 1/8

    36.93 ÷ 12.31 = 3 half-lives. Fraction remaining = (½)³ = 1/8.

  24. In the nuclear equation: ⁶₃Li + ¹₀n → ³₁H + ⁴₂He, this reaction is an example of:

    • Artificial transmutation
    • Beta decay
    • Nuclear fission
    • Nuclear fusion

    A neutron bombards the nucleus of a light, stable isotope (Li-6) and converts it into different nuclei (H-3 and He-4). Since a light target is transformed by particle bombardment — not decaying spontaneously, and not the splitting of a heavy nucleus like U-235 — this is an artificial transmutation.

  25. Nuclear fusion in the Sun results from the conversion of:

    • Energy to matter
    • Matter to energy
    • Atoms to molecules
    • Molecules to atoms

    E = mc². In fusion, mass of products is slightly less than mass of reactants → this mass deficit is converted to enormous energy (Einstein's equation).

  26. Which radioisotope is used for diagnosing thyroid disorders?

    • U-238
    • Co-60
    • I-131
    • Pb-206

    I-131 concentrates in the thyroid gland and is used for diagnosing and treating thyroid conditions (Table N).

  27. The ratio of the mass of U-238 to the mass of Pb-206 in a rock sample can be used to

    • date once-living things
    • diagnose thyroid disorders
    • diagnose kidney function
    • date geological formations

    U-238 decays through a series of steps to Pb-206. The U-238/Pb-206 ratio reflects how long the process has been occurring → geological dating.

  28. Which pair of nuclides is used to date the remains of a once-living organism?

    • C-14 and C-12
    • U-238 and Pb-206
    • I-131 and Xe-131
    • Co-60 and Co-59

    C-14 (radioactive, t½ = 5715 yr) decays after death. Comparing C-14 to stable C-12 gives the age. U-238 is for geological (inorganic) dating.

  29. In a nuclear fusion reaction, mass is lost because

    • energy is converted to mass
    • mass is converted to energy (E = mc²)
    • atoms combine to form molecules
    • molecules split into atoms

    E = mc². In fusion, the product nuclei have slightly less mass than the original nuclei. This mass deficit is converted to enormous energy.

  30. Which sample of radioisotope emits particles with the greatest mass?

    • ⁵³Fe (iron-53)
    • ¹³⁷Cs (cesium-137)
    • ²²⁰Fr (francium-220)
    • ³H (tritium)

    Fr-220 is a heavy isotope — it decays by alpha emission (mass 4). Fr-220 emits the most massive particles. Tritium emits beta particles (mass ≈ 0).

Unit 16: Organic Chemistry (34)
  1. Which general formula represents the alkene homologous series?

    • CₙH₂ₙ₊₂
    • CₙH₂ₙ₋₂
    • CₙHₙ
    • CₙH₂ₙ

    Alkenes have one double bond: CₙH₂ₙ. Alkanes = CₙH₂ₙ₊₂; Alkynes = CₙH₂ₙ₋₂.

  2. Which compound belongs to the homologous series with general formula CₙH₂ₙ?

    • C₃H₆
    • C₂H₂
    • C₄H₁₀
    • C₅H₈

    CₙH₂ₙ: n=3 → C₃H₆ ✓. C₂H₂ = alkyne (CₙH₂ₙ₋₂). C₄H₁₀ = alkane (CₙH₂ₙ₊₂). C₅H₈ doesn't fit.

  3. Which reaction produces an alcohol from glucose?

    • Combustion
    • Fermentation
    • Esterification
    • Saponification

    Fermentation: C₆H₁₂O₆ → 2C₂H₅OH + 2CO₂. Glucose → ethanol (an alcohol) using yeast, anaerobic conditions.

  4. The element that makes a compound organic is:

    • Oxygen
    • Nitrogen
    • Carbon
    • Hydrogen

    Organic compounds are defined by the presence of carbon. All organic compounds contain C (usually with H).

  5. A carboxylic acid reacts with an alcohol. What type of reaction is this?

    • Fermentation
    • Combustion
    • Saponification
    • Esterification

    Acid + alcohol → ester + water. This is esterification.

  6. What are the products of esterification?

    • Ester and water
    • Acid and water
    • Alcohol and CO₂
    • Salt and water

    Esterification: carboxylic acid + alcohol → ester + H₂O.

  7. Propanoic acid (CH₃CH₂COOH) and ethyl methanoate (HCOOCH₂CH₃) are isomers because they:

    • Have identical structural formulas
    • Have the same molecular formula but different structures
    • Contain the same functional groups
    • Have the same boiling point

    Isomers: same molecular formula (C₃H₆O₂) but different structural formulas (atoms connected differently) → different compounds.

  8. Which functional group is present in ethanol (CH₃CH₂OH)?

    • −COOH (carboxylic acid)
    • −CHO (aldehyde)
    • −OH (alcohol)
    • −COO− (ester)

    The −OH group is the alcohol functional group. Ethanol = CH₃CH₂OH.

  9. A reaction in which atoms are added across a double bond is called:

    • Substitution
    • Fermentation
    • Saponification
    • Addition

    Addition reaction: atoms (like H₂, Cl₂) add across a C=C double bond. Alkene + H₂ → alkane (hydrogenation).

  10. What is the IUPAC name for the compound with a 6-carbon chain and a CH₃ branch on carbon 3?

    • 3-methylhexane
    • 3-methylpentane
    • 2-methylhexane
    • 4-methylhexane

    6-carbon chain = hex; CH₃ branch on C3 = 3-methyl. Name: 3-methylhexane.

  11. A compound has the formula CₙH₂ₙ₊₂. What class of organic compounds does it belong to?

    • Alkenes
    • Alkanes
    • Alkynes
    • Cycloalkanes

    CₙH₂ₙ₊₂ = alkanes (saturated hydrocarbons, single bonds only).

  12. In organic naming, the prefix 'but-' indicates how many carbon atoms?

    • 2
    • 3
    • 4
    • 5

    Table Q prefixes: meth=1, eth=2, prop=3, but=4, pent=5, hex=6.

  13. Which is a correct statement about homologous series?

    • Members have the same molecular formula
    • Members have identical physical properties
    • Members have different functional groups
    • Each successive member differs by CH₂

    Homologous series: each member differs from the next by one CH₂ unit (14 g/mol). Same functional group, gradually changing properties.

  14. Which substance is a product of the complete combustion of a hydrocarbon?

    • CO₂ and H₂O
    • CO and H₂
    • C and H₂O
    • CO₂ and O₂

    Complete combustion of any hydrocarbon: CₓHᵧ + O₂ → CO₂ + H₂O. Always CO₂ and H₂O.

  15. A student is given a structural formula showing H−C−OH with additional H atoms. What functional group is present?

    • Ester
    • Alcohol
    • Aldehyde
    • Ketone

    −OH attached to a carbon chain = alcohol functional group.

  16. Based on Table R, methanoic acid (HCOOH) belongs to which class of compound is it?

    • Alcohol
    • Ester
    • Carboxylic acid
    • Aldehyde

    HCOOH = methanoic acid = simplest carboxylic acid. Functional group: −COOH.

  17. Which organic compound is formed when a carboxylic acid reacts with an alcohol and water is removed?

    • Ether
    • Ketone
    • Alcohol
    • Ester

    Esterification: R−COOH + HO−R' → R−COO−R' (ester) + H₂O.

  18. How many electrons are shared in a C−C single bond?

    • 2
    • 1
    • 4
    • 6

    A single bond = 1 shared pair = 2 electrons.

  19. Two compounds with the same molecular formula but different structural formulas are:

    • Isotopes
    • Isomers
    • Allotropes
    • Polymers

    Isomers: same molecular formula (e.g., C₄H₁₀), different structural formulas → different compounds with different properties.

  20. Which is NOT an organic compound?

    • CH₄
    • C₂H₅OH
    • CO₂
    • C₆H₁₂O₆

    CO₂ is considered inorganic (along with CO, carbonates, cyanides) even though it contains carbon. The others are organic.

  21. In esterification, what small molecule is released as a product?

    • HCl
    • NH₃
    • CO₂
    • H₂O

    Acid + alcohol → ester + WATER. The H from the acid's −OH and the −OH from the alcohol combine to form H₂O.

  22. What type of organic reaction joins many small monomer molecules into a large polymer?

    • Polymerization
    • Fermentation
    • Addition
    • Combustion

    Polymerization: monomers (small repeating units) bond together to form a polymer (e.g., ethene → polyethylene, amino acids → proteins).

  23. Ethane (C₂H₆) belongs to the alkane series. Its molecular formula fits CₙH₂ₙ₊₂ with n=2. What is the next member of the series?

    • C₂H₄
    • C₃H₈
    • C₃H₆
    • C₄H₁₀

    Next alkane after ethane (C₂H₆): add CH₂ → C₃H₈ = propane. Fits CₙH₂ₙ₊₂ with n=3: 2(3)+2 = 8 ✓.

  24. Which compound is an alcohol?

    • CH₃COOH
    • CH₃CHO
    • CH₃OH
    • CH₃COCH₃

    CH₃OH = methanol. Contains −OH group → alcohol. CH₃COOH = acid; CH₃CHO = aldehyde; CH₃COCH₃ = ketone.

  25. A substance reacts with NaOH (saponification). What type of organic compound is it?

    • Alcohol
    • Alkene
    • Carboxylic acid
    • Ester

    Saponification: ester + base (NaOH) → soap (fatty acid salt) + alcohol. The reactant that undergoes saponification is an ester.

  26. What is the name for a reaction where one atom in an organic molecule is replaced by another atom?

    • Substitution
    • Addition
    • Fermentation
    • Esterification

    Substitution: one atom (e.g., H) is replaced by another (e.g., Cl) in an organic molecule. Common with alkanes + halogens.

  27. Ethanol (C₂H₅OH) and dimethyl ether (CH₃OCH₃) both have molecular formula C₂H₆O. They are:

    • Isotopes
    • Isomers
    • Allotropes
    • Identical compounds

    Same molecular formula (C₂H₆O) but different structural formulas → isomers.

  28. What is the name for the series of organic compounds where each member has one more CH₂ than the previous member?

    • Isomers
    • Allotropes
    • Homologous series
    • Polymers

    A homologous series is a family of organic compounds each differing by CH₂, sharing the same functional group and general formula.

  29. The functional group −COOH is found in:

    • Alcohols
    • Aldehydes
    • Ketones
    • Carboxylic acids

    −COOH (carboxyl group) is the defining functional group of carboxylic acids (e.g., acetic acid, methanoic acid).

  30. Ethene (C₂H₄) undergoes addition with H₂. The product is:

    • Ethane
    • Ethyne
    • Ethanol
    • Propane

    Addition: C₂H₄ + H₂ → C₂H₆ (ethane). The double bond is broken and H atoms add across it, converting the alkene to an alkane.

  31. Which formula represents an unsaturated hydrocarbon?

    • C₅H₁₂
    • C₃H₄
    • C₄H₁₀
    • C₃H₈

    Unsaturated = has at least one double or triple bond. C₃H₄ fits CₙH₂ₙ₋₂ (alkyne: n=3 → 2(3)−2=4). The others all fit CₙH₂ₙ₊₂ (alkanes = saturated).

  32. Which pair of compounds are isomers of each other?

    • CH₄ and C₂H₆
    • C₂H₄ and C₂H₆
    • C₂H₅OH and CH₃OCH₃
    • C₃H₆ and C₄H₈

    C₂H₅OH (ethanol) and CH₃OCH₃ (dimethyl ether) both have formula C₂H₆O — same molecular formula, different structures → isomers.

  33. According to Table R, which type of reaction produces an ester?

    • Fermentation
    • Saponification
    • Substitution
    • Esterification

    Esterification: carboxylic acid + alcohol → ester + water. The product is an ester (R-COO-R').

  34. Which organic compound is classified as an alcohol?

    • C₂H₅OH
    • HCOOH
    • CH₃CHO
    • CH₃COCH₃

    C₂H₅OH = ethanol. It contains the −OH functional group → classified as an alcohol. HCOOH = acid; CH₃CHO = aldehyde; CH₃COCH₃ = ketone.

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Unit 1: Matter & Change

Element
Pure substance made of only ONE type of atom; cannot be broken down chemically (e.g., Fe, O₂, Cu, Ne)
Compound
Pure substance made of two or more elements CHEMICALLY combined in a fixed ratio; separated only by chemical means (e.g., H₂O, NaCl)
Homogeneous mixture
Uniform throughout; looks like one phase (e.g., salt water, air, brass, vinegar). Also called a solution.
Heterogeneous mixture
Non-uniform; visible different parts that can be physically separated (e.g., sand+water, salad, granite)
Physical change
Change in form, shape, or phase without changing chemical composition (melting, dissolving, cutting). Original substance can be recovered.
Chemical change
A new substance with new properties is formed. Signs: color change, gas, precipitate, irreversible temperature change, light/sound.
Intensive property
Property that does NOT depend on sample size: density, temperature, melting point, color, boiling point
Extensive property
Property that DOES depend on sample size: mass, volume, length, total heat
Distillation
Separation technique for two liquids with different boiling points — one evaporates first, then condenses separately
Chromatography
Separation technique based on polarity differences — separates dissolved substances (e.g., ink pigments)

Unit 2: Measurements & Math

Significant figures
The digits in a measurement that are known with certainty plus one estimated digit. Indicate precision of a measurement.
Accuracy
How close a measurement is to the TRUE/accepted value. Measured by percent error.
PrecisStudyion
How close REPEATED measurements are to each other. Consistency of results, regardless of accuracy.
Percent error
|measured − accepted| / accepted × 100. Always positive. Measures accuracy.
Mole (mol)
SI unit = 6.02×10²³ particles (Avogadro's number). Like a 'dozen' but for atoms/molecules.
Gram formula mass (GFM)
The molar mass of a substance — sum of all atomic masses in the formula, in g/mol
Avogadro's number
6.02×10²³ — the number of particles in one mole of any substance
Dimensional analysis
Method of converting units by multiplying by conversion factors (fractions = 1) so unwanted units cancel

Unit 3: Atomic Concepts

Atomic number
Number of PROTONS in the nucleus. Defines the element's identity. Equal to number of electrons in a neutral atom.
Mass number
Number of PROTONS + NEUTRONS in the nucleus. Varies between isotopes of the same element.
Isotopes
Atoms of the same element (same protons) with DIFFERENT numbers of neutrons → different mass numbers
Ground state
Lowest energy electron configuration — electrons in the lowest available orbitals
Excited state
Electron absorbed energy and jumped to a higher energy level. Total electron count unchanged; config ≠ lowest.
Bright-line spectrum
Unique pattern of discrete wavelengths of light emitted when excited electrons fall to lower energy levels — fingerprint of each element
Rutherford gold foil experiment
Most alpha particles passed through gold foil; few were deflected back → proved atoms have a small, dense, positive nucleus with mostly empty space
Wave-mechanical model
Current atomic model — electrons exist in probability clouds (orbitals), not fixed paths. Explains all elements.
Valence electrons
Electrons in the outermost energy level (highest principal quantum number). Determine chemical reactivity.
Orbital
Region of space where an electron is most likely to be found. Each orbital holds max 2 electrons (opposite spins).

Unit 4: Periodic Table

Electronegativity
Tendency of an atom to attract shared electrons toward itself. Highest = F (4.0). Increases across period, decreases down group.
Ionization energy
Energy required to remove ONE electron from a gaseous atom. Increases across period, decreases down group.
Atomic radius
Size of an atom. DECREASES across a period (more protons, same shell); INCREASES down a group (more shells).
Metallic character
Tendency to lose electrons and form cations. Increases down and to the left on the periodic table. Opposite of electronegativity.
Isoelectronic
Atoms or ions with the same number of electrons and same electron configuration (e.g., Na⁺, Mg²⁺, and Ne all have 10 e⁻)
Cation
Positively charged ion formed when an atom LOSES electrons. Smaller than parent atom (same protons, fewer electrons).
Anion
Negatively charged ion formed when an atom GAINS electrons. Larger than parent atom (same protons, more electrons).
Noble gas
Group 18 elements with full valence shells (8 e⁻, or 2 for He). Chemically inert/nonreactive. Used as reference configs for ions.

Unit 5: Chemical Bonding

Ionic bond
Electrostatic attraction between oppositely charged ions. Forms between metals and nonmetals (ΔEN ≥ 1.7). Electron TRANSFER.
Covalent bond
Sharing of electron pairs between nonmetal atoms. Polar if ΔEN 0.4–1.7; nonpolar if ΔEN < 0.4.
Metallic bond
Attraction between positive metal ion cores and a 'sea' of delocalized valence electrons. Explains conductivity, malleability, luster.
Polar molecule
Molecule with unequal charge distribution (net dipole) due to polar bonds AND asymmetric geometry (e.g., H₂O, NH₃, HCl)
Nonpolar molecule
Molecule with equal charge distribution — either nonpolar bonds (Cl₂) or symmetric cancellation of polar bonds (CO₂, CH₄, CCl₄)
Lewis dot structure
Diagram showing valence electrons as dots; bonding pairs between atoms, lone pairs on individual atoms. Satisfies octet rule.
VSEPR theory
Valence Shell Electron Pair Repulsion — electron groups repel, so molecules adopt shapes that minimize repulsion
Hydrogen bond
Extra-strong dipole-dipole force between H bonded to N, O, or F and another electronegative atom. Explains water's high boiling point.
London dispersion forces
Weakest IMF — temporary dipoles in all molecules; increases with molar mass and surface area. ONLY force in nonpolar molecules.
Octet rule
Atoms tend to gain, lose, or share electrons to achieve 8 valence electrons (exceptions: H=2, B=6, expanded for period 3+ elements)

Unit 6: Chemical Quantities

Stoichiometry
Using balanced equation coefficients (mole ratios) to calculate amounts of reactants or products in a chemical reaction
Empirical formula
Simplest whole-number ratio of atoms in a compound. May differ from molecular formula (CH₂ vs C₄H₈).
Molecular formula
Actual number of atoms of each element in one molecule of a compound (e.g., C₄H₈, H₂O₂, C₆H₁₂O₆)
Percent composition
Mass percentage of each element in a compound. (mass of element in 1 mol / molar mass) × 100
Limiting reagent
Reactant that is completely consumed first, determining the maximum amount of product that can form
Theoretical yield
Maximum amount of product that could form based on stoichiometry from the limiting reagent
Percent yield
(actual yield / theoretical yield) × 100. Measures reaction efficiency. Cannot exceed 100%.
Hydrate
Ionic compound with water molecules trapped in the crystal structure (e.g., CuSO₄·5H₂O). Water is released on heating.
Limiting reagent
The reactant that is completely consumed first in a reaction. Determines the maximum (theoretical) yield of product.
Excess reagent
The reactant that is NOT fully consumed — some remains after the limiting reagent is used up.
Theoretical yield
Maximum mass of product calculated from the limiting reagent using stoichiometry. Actual yield ≤ theoretical yield always.
Stoichiometry 4-step roadmap
1) g given ÷ GFM → mol given. 2) × mole ratio (coeff wanted / coeff given). 3) × GFM wanted → g wanted. Moles are always the bridge.
Volume–volume stoichiometry (STP)
At STP, gas volumes react in the same ratio as their coefficients: 2 L H₂ + 1 L O₂ → 2 L H₂O (Gay-Lussac's Law of Combining Volumes).

Unit 7: Chemical Reactions

Synthesis reaction
Two or more reactants combine to form a single product: A + B → AB (e.g., 2Na + Cl₂ → 2NaCl)
Decomposition reaction
Single compound breaks into simpler substances: AB → A + B (e.g., 2H₂O → 2H₂ + O₂)
Single replacement reaction
One element displaces another from a compound: A + BC → AC + B. Spontaneous only if A is higher than B on Table J.
Double replacement reaction
Ions from two compounds switch partners: AB + CD → AD + CB. Occurs if a precipitate, gas, or water forms.
Combustion reaction
Hydrocarbon + O₂ → CO₂ + H₂O (complete). Produces CO or C soot in incomplete combustion.
Precipitate
Insoluble solid that forms and settles out when two aqueous solutions are mixed. Predicted using Table F.
Activity series (Table J)
Ranking of metals/halogens by reactivity. A higher element will spontaneously replace a lower one in a compound.
Spectator ions
Ions present in solution that do not participate in the reaction — they appear unchanged on both sides of the equation

Unit 8: Phases of Matter

Kinetic energy (KE)
Energy of motion. KE = ½mv². Temperature is a measure of average KE of particles.
Potential energy (PE)
Stored energy based on position or arrangement. Changes during phase transitions (not during temperature changes within a phase).
Phase change
Change in state of matter (solid↔liquid↔gas). Temperature stays CONSTANT during a phase change; PE changes.
Heat of fusion (Hf)
Energy required to melt (or released on freezing) 1 gram of a substance at its melting point. q = mHf. For water: 334 J/g.
Heat of vaporization (Hv)
Energy required to vaporize (or released on condensing) 1 gram of a substance at its boiling point. q = mHv. For water: 2260 J/g.
Specific heat capacity (C)
Energy needed to raise 1 gram of a substance by 1°C (or 1 K). q = mCΔT. For water: 4.18 J/g·K.
Vapor pressure
Pressure exerted by vapor above a liquid in a closed system. Increases with temperature. Lower vapor pressure = stronger IMFs.
Intermolecular forces (IMFs)
Attractive forces BETWEEN molecules (not within). Determine boiling point, melting point, vapor pressure. H-bond > dipole > LDF.

Unit 9: Gas Laws

Boyle's Law
P₁V₁ = P₂V₂ (constant T, n). Pressure and volume are INVERSELY proportional. Double pressure → half volume.
Charles's Law
V₁/T₁ = V₂/T₂ (constant P, n). Volume and temperature (Kelvin) are DIRECTLY proportional.
Gay-Lussac's Law
P₁/T₁ = P₂/T₂ (constant V, n). Pressure and temperature (Kelvin) are directly proportional.
Combined Gas Law
P₁V₁/T₁ = P₂V₂/T₂. Combines Boyle's, Charles's, and Gay-Lussac's laws. Always use Kelvin.
STP
Standard Temperature and Pressure: 273 K (0°C) and 101.3 kPa (1 atm). At STP, 1 mol of ideal gas = 22.4 L.
Ideal gas
Hypothetical gas that perfectly follows KMT — no volume, no intermolecular forces. Best modeled by H₂ and He at high T, low P.
Absolute zero
0 Kelvin (−273°C) — theoretical point where all particle motion stops and KE = 0. Cannot actually reach it.
KMT (Kinetic Molecular Theory)
Model describing ideal gas behavior: random straight-line motion, no forces between particles, elastic collisions, KE ∝ T(Kelvin)

Unit 10: Solutions

Solubility
Maximum amount of solute that can dissolve in a given amount of solvent at a specific temperature. Shown on Table G curves.
Saturated solution
Contains maximum dissolved solute at that temperature — ON the solubility curve line
Unsaturated solution
Contains LESS solute than maximum — BELOW the solubility curve. More can still dissolve.
Supersaturated solution
Contains MORE solute than normally possible — ABOVE the curve. Unstable; crystallizes if disturbed.
Molarity (M)
M = moles of solute / liters of solution. Unit: mol/L. The most common concentration unit.
Electrolyte
Substance that ionizes/dissociates in solution and conducts electricity (strong: HCl, NaOH, NaCl; weak: acetic acid)
Colligative property
Property that depends on the NUMBER of dissolved particles, not their type. Examples: BP elevation, FP depression, vapor pressure lowering.
Henry's Law
Solubility of a gas increases with increasing pressure. Explains carbonation of beverages.
Crystallization
Process where dissolved solute comes out of solution and forms solid crystals. A physical change. Triggered by cooling, evaporation, or adding a seed crystal.
Seed crystal
A small crystal of the same substance added to a supersaturated solution to initiate crystallization by providing a nucleation surface.
Fractional crystallization
Separation technique that exploits differences in solubility curves — cooling a mixture crystallizes the substance whose solubility drops most, leaving others dissolved.
Amount crystallized
= solubility at T_high − solubility at T_low (per 100 g H₂O). Only possible if starting solution was saturated at T_high.

Unit 11: Thermochemistry

Endothermic reaction
Absorbs energy from surroundings. ΔH = positive (+). Heat is a REACTANT. Surroundings feel cold. Products at higher PE.
Exothermic reaction
Releases energy to surroundings. ΔH = negative (−). Heat is a PRODUCT. Surroundings feel warm. Products at lower PE.
Activation energy (Ea)
Minimum energy required for a reaction to occur. Height from reactants to peak on a PE diagram. Catalyst lowers Ea.
Activated complex
Unstable intermediate at the peak of the PE diagram. Transition state — can either form products or revert to reactants.
Catalyst
Substance that lowers Ea (both forward and reverse directions) without being consumed. Does NOT change ΔH or equilibrium position.
Entropy (S)
Measure of disorder/randomness in a system. Increases: solid→liquid→gas, dissolving, more moles of gas, higher temperature.
ΔH
Enthalpy change = H_products − H_reactants. Negative = exothermic (energy released); Positive = endothermic (energy absorbed).
Bond energy
Energy required to BREAK one mole of a specific bond in the gas phase. Breaking bonds = endothermic; forming bonds = exothermic.

Unit 12: Equilibrium & Kinetics

Chemical equilibrium
State where forward rate = reverse rate; concentrations remain constant; occurs in a closed system. Dynamic, not static.
Le Chatelier's Principle
When a stress is applied to a system at equilibrium, the system shifts to COUNTERACT (relieve) that stress.
Collision theory
For a reaction to occur: particles must collide, with proper orientation, AND with energy ≥ Ea. All three required.
Equilibrium constant (Keq)
Ratio of product concentrations to reactant concentrations (each raised to their coefficients) at equilibrium. Pure solids/liquids excluded.
Effective collision
Collision that results in a chemical reaction — has correct orientation AND energy ≥ activation energy
Reaction rate
Speed at which reactants are converted to products. Affected by: temperature, concentration, surface area, catalysts, nature of reactants.

Unit 13: Acids, Bases & Salts

Arrhenius acid
Substance that produces H⁺ (H₃O⁺) in aqueous solution (HCl, H₂SO₄, HNO₃)
Arrhenius base
Substance that produces OH⁻ in aqueous solution (NaOH, KOH, Ca(OH)₂)
Brønsted-Lowry acid
Proton (H⁺) DONOR in a reaction. Broader definition than Arrhenius — works in non-aqueous systems too.
Brønsted-Lowry base
Proton (H⁺) ACCEPTOR in a reaction.
pH
pH = −log[H⁺]. Scale 0–14. Acidic < 7; Neutral = 7; Basic > 7. Logarithmic: each unit = 10× change in [H⁺].
Strong acid
Completely dissociates (100%) in water: HCl, HBr, HI, HNO₃, H₂SO₄, HClO₄. Produces maximum H⁺.
Weak acid
Partially dissociates (<100%) in water, reaching equilibrium. Examples: HF, CH₃COOH (acetic acid), H₂CO₃.
Neutralization
Reaction between an acid and a base to produce a salt and water: HCl + NaOH → NaCl + H₂O
Titration
Lab technique to find unknown concentration using M_A×V_A = M_B×V_B (1:1). Equivalence point: moles H⁺ = moles OH⁻.
Conjugate acid-base pair
Two species that differ by ONE proton (H⁺). Example: HCl and Cl⁻; NH₄⁺ and NH₃.

Unit 14: Redox & Electrochemistry

Oxidation
Loss of electrons. Oxidation number INCREASES. Occurs at the ANODE. OIL (Oxidation Is Loss).
Reduction
Gain of electrons. Oxidation number DECREASES. Occurs at the CATHODE. RIG (Reduction Is Gain).
Oxidizing agent
Species that ACCEPTS electrons (gets reduced). Causes oxidation of the other substance.
Reducing agent
Species that DONATES electrons (gets oxidized). Causes reduction of the other substance.
Half-reaction
Shows either the oxidation or reduction half of a redox reaction separately, with electrons explicitly shown
Voltaic (galvanic) cell
SPONTANEOUS redox reaction that generates electrical energy. Converts chemical → electrical energy. Anode = (−), cathode = (+).
Electrolytic cell
Uses EXTERNAL electrical energy to drive a NONSPONTANEOUS reaction (electroplating, water electrolysis). Anode = (+), cathode = (−).
Salt bridge
Connects two half-cells; allows ions to flow to maintain electrical neutrality. Ions flow; electrons flow through external wire.
Anode
Electrode where OXIDATION occurs in ANY electrochemical cell. In voltaic: negative (−). In electrolytic: positive (+).
Cathode
Electrode where REDUCTION occurs in ANY electrochemical cell (RED-CAT). In voltaic: positive (+). In electrolytic: negative (−).

Unit 15: Nuclear Chemistry

Alpha decay (α)
Emission of ⁴₂He nucleus. Mass number decreases by 4, atomic number decreases by 2. Stopped by paper.
Beta decay (β⁻)
Emission of high-speed electron (⁰₋₁e). Neutron → proton + electron. Mass unchanged, atomic number +1. Stopped by aluminum.
Gamma radiation (γ)
High-energy photon emission. NO change in mass number or atomic number. Most penetrating — needs lead/concrete to stop.
Positron emission (β⁺)
Emission of ⁰₊₁e (antielectron). Proton → neutron + positron. Mass unchanged, atomic number −1.
Half-life (t₁/₂)
Time for HALF of a radioactive sample to decay. Constant — independent of temperature, pressure, or chemical state.
Nuclear fission
Splitting of a HEAVY nucleus (U-235, Pu-239) into smaller nuclei + neutrons + large amounts of energy. Used in reactors.
Nuclear fusion
Combining LIGHT nuclei (H isotopes) into a heavier nucleus + enormous energy. Powers the sun and stars. Requires extreme conditions.
Transmutation
Conversion of one element to another through nuclear decay or particle bombardment. Changes atomic number.
Carbon-14 dating
Uses C-14 half-life (5715 yr) to date once-living organic material. Works because C-14 intake stops at death and decays at a known rate.
Radioactive decay series
Sequential decay of a heavy nucleus through multiple steps until a stable nucleus is reached (U-238 eventually → Pb-206)

Unit 16: Organic Chemistry

Organic compound
Any compound that contains carbon (usually with hydrogen). Exceptions: CO, CO₂, carbonates, cyanides are considered inorganic.
Homologous series
A family of organic compounds with the same general formula and functional group, each differing by one CH₂ unit. Members have gradually changing properties.
Alkanes
Saturated hydrocarbons — single bonds only. General formula CₙH₂ₙ₊₂. Suffix: -ane. Examples: methane (CH₄), ethane (C₂H₆), propane (C₃H₈).
Alkenes
Unsaturated hydrocarbons — one double bond. General formula CₙH₂ₙ. Suffix: -ene. Examples: ethene (C₂H₄), propene (C₃H₆).
Alkynes
Unsaturated hydrocarbons — one triple bond. General formula CₙH₂ₙ₋₂. Suffix: -yne. Example: ethyne (C₂H₂ = acetylene).
Functional group
An atom or group of atoms in an organic molecule that determines the compound's chemical properties. Examples: −OH (alcohol), −COOH (carboxylic acid), −COO− (ester).
Alcohol (−OH)
Organic functional group: −OH attached to a carbon. Suffix: -ol. Example: ethanol (C₂H₅OH). Produced by fermentation or addition of H₂O to alkene.
Carboxylic acid (−COOH)
Organic acid functional group. Suffix: -oic acid. Example: methanoic acid (HCOOH), ethanoic acid (CH₃COOH = acetic acid). Weak acids.
Ester (−COO−)
Formed from carboxylic acid + alcohol → ester + water (esterification). Suffix: -anoate. Often have pleasant fruity odors.
Fermentation
Reaction: C₆H₁₂O₆ → 2C₂H₅OH + 2CO₂. Glucose → ethanol + carbon dioxide. Uses yeast, anaerobic (no oxygen). Produces alcoholic beverages.
Esterification
Carboxylic acid + alcohol → ester + water. Reversible reaction. The −OH from the acid and the H from the alcohol's −OH combine to form H₂O.
Isomers
Compounds with the SAME molecular formula but DIFFERENT structural formulas. Same atoms, connected differently → different properties. Example: butane and 2-methylpropane (both C₄H₁₀).
Addition reaction
Atoms are added across a double or triple bond. Converts unsaturated → saturated. Example: C₂H₄ + H₂ → C₂H₆ (hydrogenation of ethene to ethane).
Substitution reaction
One atom in an organic molecule is replaced by another. Example: CH₄ + Cl₂ → CH₃Cl + HCl. Common with alkanes and halogens.
Polymerization
Many small monomer units join together to form a large polymer chain. Example: ethene (C₂H₄) → polyethylene. Also: amino acids → proteins; nucleotides → DNA.
Allotropes
Different structural forms of the same element with different properties. Example: O₂ and O₃ (both oxygen); diamond and graphite (both carbon).

Core Formulas (Table T)

Density
D = m / V
% Error
|meas − accept| / accept × 100
Moles
n = m / GFM
Avogadro
1 mol = 6.02×10²³ particles
Kelvin
K = °C + 273
q = mCΔT
Sloped sections — T changing
q = mH_f
Melting/freezing (flat at MP)
q = mH_v
Boiling/condensing (flat at BP)
pH
pH = −log[H⁺]
pH + pOH
= 14 (at 25°C)
Kw
[H⁺][OH⁻] = 1×10⁻¹⁴
Titration (1:1)
M_A × V_A = M_B × V_B
Molarity
M = mol solute / L solution
ppm
(m_solute / m_solution) × 10⁶
Dilution
M₁V₁ = M₂V₂
Combined Gas
P₁V₁/T₁ = P₂V₂/T₂
% Composition
(mass part / total mass) × 100
Half-Life
A = A₀ × (½)^(t/t₁/₂)
ΔH (bonds)
ΔH = bonds broken − bonds formed
Atomic Mass
Σ(mass × fractional abundance)
Molar Volume (STP)
1 mol gas = 22.4 L
% Yield
actual / theoretical × 100
ΔG (Gibbs)
ΔG = ΔH − TΔS (spont. if < 0)
Stoichiometry
g ÷ GFM_given × ratio × GFM_want

Nuclear Particle Changes

Decay TypeSymbolMass # ChangeAtomic # ChangePenetration
Alpha (α)⁴₂He−4−2Stopped by paper
Beta⁻ (β⁻)⁰₋₁e0+1Stopped by aluminum
Positron (β⁺)⁰₊₁e0−1Stopped by aluminum
Gamma (γ)⁰₀γ00Needs lead/concrete

Indicator Table (Table M)

IndicatorTransition pHAcid ColorBase Color
Methyl orange3.1–4.4RedYellow
Bromcresol green3.8–5.4YellowBlue
Litmus4.5–8.3RedBlue
Bromthymol blue6.0–7.6YellowBlue
Thymol blue8.0–9.6YellowBlue
Phenolphthalein8.2–10.0ColorlessPink/Fuchsia

Oxidation Number Rules (Priority Order)

  1. Free elements: any uncombined element = 0 (Na, O₂, Cl₂, Fe)
  2. Monatomic ions: oxidation # = ion charge (Na⁺=+1, Cl⁻=−1, Fe³⁺=+3)
  3. Group 1 in compounds: always +1 (Li, Na, K, Rb, Cs)
  4. Group 2 in compounds: always +2 (Mg, Ca, Ba, Sr)
  5. Fluorine: always −1 (most electronegative element)
  6. Hydrogen: +1 usually; −1 in metal hydrides (NaH, CaH₂, LiH)
  7. Oxygen: −2 usually; −1 in peroxides (H₂O₂, Na₂O₂); +2 with F only
  8. Sum rule: sum of all oxidation numbers = 0 (neutral) or = ion charge (polyatomic)

Half-Life Reference Table

# Half-LivesFraction Left% Remaining% Decayed
01100%0%
11/250%50%
21/425%75%
31/812.5%87.5%
41/166.25%93.75%
51/323.125%96.875%

VSEPR Molecular Geometry

Bonding PairsLone PairsGeometryBond AngleExample
20Linear180°CO₂, BeCl₂
30Trigonal planar120°BF₃, SO₃
40Tetrahedral109.5°CH₄, CCl₄
31Trigonal pyramidal107°NH₃
22Bent/V-shaped104.5°H₂O

Electrochemistry Summary

PropertyVoltaic (Galvanic) CellElectrolytic Cell
Energy conversionChemical → ElectricalElectrical → Chemical
Spontaneous?YesNo (needs external power)
Anode signNegative (−)Positive (+)
Cathode signPositive (+)Negative (−)
At anodeOxidation (always)Oxidation (always)
At cathodeReduction (always)Reduction (always)
Electron flowAnode → Cathode (wire)Cathode ← Anode (wire)

Strong Acids & Bases (Memorize)

Strong Acids (6)
HCl, HBr, HI, HNO₃, H₂SO₄, HClO₄
Strong Bases
NaOH, KOH, Ca(OH)₂, Ba(OH)₂, LiOH
Weak Acid examples
HF, CH₃COOH, H₂CO₃, H₃PO₄
Weak Base examples
NH₃, Al(OH)₃

Reference Table Guide (All Tables)

Table A
STP: 273 K, 101.3 kPa, 1 atm, 760 mmHg
Table B
Water constants: C=4.18 J/g·K, H_f=334 J/g, H_v=2260 J/g
Table C
Selected polyatomic ions (NH₄⁺, OH⁻...)
Table D
Selected units and measurements
Table E
Polyatomic ions (NO₃⁻, SO₄²⁻, CO₃²⁻, PO₄³⁻...)
Table F
Solubility rules — predicts precipitates
Table G
Solubility curves (g/100g H₂O vs temp)
Table H
Vapor pressure curves (BP = where VP = 101.3 kPa)
Table I
Heats of reaction (ΔH values in kJ/mol)
Table J
Activity series — metal/halogen reactivity ranking
Table K
Common acids and their formulas
Table L
Common bases and their formulas
Table M
Indicators — pH ranges and color changes
Table N
Radioisotopes — half-lives, decay modes, medical uses
Table O
Nuclear symbols (α, β, γ, positron)
Table P
Organic functional groups
Table Q
Organic prefixes (meth=1, eth=2, prop=3...)
Table R
Organic reactions
Table S
Properties of selected elements (EN, radius, ionization E)
Table T
Important formulas (density, gas laws, pH, etc.)

Electronegativity & Bond Type

ΔEN RangeBond TypeExample
0 – 0.4Nonpolar covalentCl-Cl, C-H, H-H
0.4 – 1.7Polar covalentH-O, H-N, H-Cl
≥ 1.7IonicNa-Cl, Mg-O, Ca-F

Gas Laws Quick Reference

LawFormulaConstantRelationship
Boyle'sP₁V₁ = P₂V₂T, nP and V inverse
Charles'sV₁/T₁ = V₂/T₂P, nV and T direct
Gay-Lussac'sP₁/T₁ = P₂/T₂V, nP and T direct
CombinedP₁V₁/T₁ = P₂V₂/T₂nAll three
Avogadro'sEqual V at same T,P = equal nT, PV and n direct

Organic Chemistry Quick Reference

SeriesGeneral FormulaBond TypeExample
AlkanesCₙH₂ₙ₊₂Single only (saturated)CH₄, C₂H₆, C₃H₈
AlkenesCₙH₂ₙOne double bondC₂H₄, C₃H₆
AlkynesCₙH₂ₙ₋₂One triple bondC₂H₂ (acetylene)
CycloalkanesCₙH₂ₙRing, single bondsC₃H₆ (cyclopropane)
Functional GroupName ClassSuffixExample
−OHAlcohol-olethanol (C₂H₅OH)
−COOHCarboxylic acid-oic acidethanoic acid (CH₃COOH)
−COO−Ester-anoateethyl ethanoate
−CHOAldehyde-almethanal (formaldehyde)
C=O (chain)Ketone-onepropanone (acetone)
−NH₂Amine-aminemethylamine
Reaction (Table R)ReactantsProductsKey fact
FermentationC₆H₁₂O₆2C₂H₅OH + 2CO₂Yeast, anaerobic, makes alcohol
EsterificationAcid + AlcoholEster + H₂OReversible
SaponificationEster + NaOHSoap + AlcoholReverse of esterification
AdditionAlkene + H₂/Cl₂Saturated productBreaks double bond
SubstitutionAlkane + halogenHaloalkane + HXReplaces H with halogen
CombustionCₓHᵧ + O₂CO₂ + H₂OComplete combustion always
Polymerizationn(monomer)PolymerEthene → polyethylene
Naming prefixes
meth=1, eth=2, prop=3, but=4, pent=5, hex=6, hept=7, oct=8
Isomers rule
Same molecular formula, different structural formula → isomers
Allotropes (Q7 exam)
O₂ vs O₃: same element, different structure → different properties
Organic = contains C
Exceptions: CO, CO₂, CO₃²⁻, CN⁻ are inorganic

Crystallization & Stoichiometry Quick Reference

Crystallization trigger
Cool saturated solution OR evaporate solvent → supersaturated → crystals form
Amount crystallized
Solubility(T_high) − Solubility(T_low) per 100 g H₂O
Seed crystal
Nucleation surface; triggers crystallization from supersaturated solution
Best candidate for recrystallization
Substance with steep solubility curve (e.g., KNO₃)
Stoichiometry roadmap
g ÷ GFM_given × (mol wanted/mol given) × GFM_wanted
Limiting reagent test
Convert both reactants to mol of product → smaller answer = limiting
% yield
actual ÷ theoretical × 100 (never > 100%)
Gas stoichiometry (STP)
Volumes react in same ratio as coefficients; 1 mol = 22.4 L

Periodic Trends Summary

PropertyAcross Period (L→R)Down Group (↓)Largest Value
Atomic radiusDecreasesIncreasesFr (bottom-left)
Ionization energyIncreasesDecreasesHe (top-right)
ElectronegativityIncreasesDecreasesF (4.0)
Metallic characterDecreasesIncreasesFr (bottom-left)
Ionic radius (cations)DecreasesIncreasesCs⁺

Table I — Heats of Dissolving

CompoundΔH (dissolving)TypeEffect on solution
NaOH(s)Negative (−)ExothermicSolution gets WARM
NH₄NO₃(s)Positive (+)EndothermicSolution gets COLD (cold packs)
KNO₃(s)Positive (+)EndothermicSolution gets COLD
NH₄Cl(s)Positive (+)EndothermicSolution gets COLD

Physical vs Chemical Equilibrium

TypeExampleWhat's equalClosed system?
Physical equilibriumSealed flask with liquid H₂OEvaporation rate = condensation rateYes
Chemical equilibriumN₂ + 3H₂ ⇌ 2NH₃Forward rate = reverse rateYes
Reading conc-vs-time graph
Equilibrium = where ALL lines become flat and stay flat
PE during evaporation
PE INCREASES as molecules escape IMFs; KE (temp) of remaining liquid DECREASES → cooling
Heat flow direction
Always flows from HIGH temperature to LOW temperature
Control group (lab)
The unchanged baseline — e.g., dry towel in evaporation experiment

Top 15 Exam Traps

  1. Always convert °C to Kelvin before using gas law formulas (K = °C + 273).
  2. Dissolving is a PHYSICAL change — NaCl can be recovered by evaporation.
  3. Activation energy (Ea) is measured from REACTANTS up to the peak — not from zero.
  4. Catalyst lowers Ea but does NOT change ΔH or shift equilibrium position.
  5. CO₂ has polar bonds but is a nonpolar MOLECULE — linear geometry cancels dipoles.
  6. Ionic solids do NOT conduct electricity — only when molten or dissolved (ions mobile).
  7. Saturated ≠ concentrated. Saturated = at maximum capacity (on the solubility curve line).
  8. pH scale is LOGARITHMIC: each 1-unit difference = 10× change in [H⁺].
  9. Single replacement: check Table J first. If replacing element is lower → NR.
  10. Only COEFFICIENTS can be changed when balancing — never subscripts.
  11. Voltaic vs. electrolytic: anode terminal signs flip, but oxidation is ALWAYS at the anode.
  12. Nuclear equations: BOTH mass numbers AND atomic numbers must balance.
  13. Half-life is constant — unaffected by temperature, pressure, or chemical form.
  14. Excited state still has the correct number of electrons — they're just not in lowest levels.
  15. Strength ≠ concentration — a dilute HCl solution is still a STRONG acid (100% ionized).

Exam Day Checklist

  • Use Table T first — it lists all the formulas you'll need.
  • Know which Reference Table to use: J (activity series), F (precipitates), M (indicators), N (radioisotopes), G (solubility curves).
  • Show all work with units. Dimensional analysis prevents errors.
  • Start with questions you know best; circle and skip difficult ones.
  • Gas laws: write down given values, identify what's constant, pick the right formula.
  • Nuclear equations: always verify mass numbers AND atomic numbers balance.
  • For PE diagrams: mark reactants, peak, and products before reading Ea or ΔH.
  • Treat heat as a substance (reactant or product) for Le Chatelier problems.
  • Oxidation number assignments: use the 8 rules in priority order.
  • Check units in your final answer before moving on.
Quick ways to lock in the facts you keep forgetting. Read the big trick, then the small note tells you what it unlocks. Say them out loud — silly is memorable.

Matter, Measurement & Atoms

Can you get it back?
Physical change: the original substance can be recovered (melt ice, freeze it back). Chemical change: you can't un-burn wood — a genuinely new substance formed.
Fixed = compound, flexible = mixture
Compounds have a fixed ratio of elements (H₂O is always 2:1). Mixtures can be any ratio — that's what makes them physically separable.
Distill by degree, filter what's firm
Distillation separates liquids by different boiling points. Filtration catches an insoluble solid in a filter.
Zeros: leading lies, trailing tells, captive counts
Leading zeros (0.0025) are never significant. Trailing zeros only count WITH a decimal point (1500. = 4 sig figs). Captive zeros (2005) always count.
Add keeps the least decimal, multiply keeps the least digit
Adding/subtracting: round to the fewest decimal places among your numbers. Multiplying/dividing: round to the fewest total sig figs.
Same P, different N = isotope
Isotopes have the same number of protons but a different number of neutrons — mass number varies, atomic number doesn't.

Periodic Table & Bonding

Down gets big, across gets small
Atomic radius increases going down a group (more energy levels) and decreases going across a period (more protons pull electrons in).
Ionization energy is the opposite of radius
Small atom = electrons held tight = high ionization energy. IE increases across a period, decreases down a group — the reverse of atomic radius.
Fluorine is the greediest
Electronegativity peaks at fluorine (top-right of the table, excluding noble gases) — it pulls shared electrons hardest of any element.
Metal + nonmetal = ionic, nonmetal + nonmetal = covalent
Ionic bonds transfer electrons (big electronegativity gap). Covalent bonds share electrons (both nonmetals, similar electronegativity).
Symmetric cancels, lopsided doesn't
A molecule with polar bonds can still be nonpolar overall if its shape is symmetric (like CO₂) — the bond dipoles cancel out.
VSEPR: count the groups around the center
4 bonding groups, 0 lone pairs = tetrahedral. 4 groups, 1 lone pair = trigonal pyramidal. 4 groups, 2 lone pairs = bent.

Quantities & Reactions

Moles are always the bridge
Every stoichiometry problem goes grams → moles → moles → grams. You can never skip straight from one substance's grams to another's.
Limiting runs out first, excess is left over
Whichever reactant produces the smaller amount of product is the limiting reagent — it runs out first and stops the reaction.
Yield can't beat 100%
% yield = actual ÷ theoretical × 100. An answer over 100% means a math error somewhere.
One becomes many, many become one
Synthesis: two reactants → one product. Decomposition: one reactant → many products — think of them as opposites.
Higher on the list wins
Table J's activity series: a metal can only replace a less active metal below it. Asking it to replace something above it means "no reaction."
Balance coefficients, never subscripts
Only the big numbers in front of formulas can change when balancing. Changing a subscript changes the substance itself.

Phases & Gases

Flat means it's changing phase
On a heating curve, a flat plateau means energy is breaking intermolecular forces, not raising temperature — melting or boiling in progress.
Gas particles don't care about each other
KMT: gas particles have negligible volume and no attraction to each other — that's why gases compress easily and fill any container.
Tyndall = you can see the beam
A light beam becomes visible passing through a colloid because its particles are big enough to scatter light — true solutions don't do this.
Squeeze it, it heats up pressure-wise
Boyle's Law: P and V are inversely related at constant T — squeeze the volume down, pressure goes up.
Charles says heat it, it grows
Charles's Law: V and T are directly related at constant P — heat a balloon, it expands.
STP is the universal starting line
At STP (0°C, 1 atm), 1 mole of any gas = 22.4 L. Always convert Celsius to Kelvin before plugging into a gas law.

Solutions & Thermochemistry

Above the line, it won't all dissolve
On a solubility curve, a point above the curve means undissolved solid remains — the solution at that point is saturated at most.
Concentrated ≠ saturated
Saturated means at the max the solvent can hold. Concentrated just means "a lot of solute" — a dilute solution can still be saturated if the solute barely dissolves.
Dilution: moles don't change
M₁V₁ = M₂V₂ works because adding water changes concentration, not the actual moles of solute present.
Exo EXits heat, endo takes it IN
Exothermic reactions release heat to the surroundings. Endothermic reactions absorb heat from the surroundings.
Flat parts on a PE diagram are phase changes
Sloped line = temperature changing (q = mCΔT). Flat line = phase changing at constant temperature (q = mH_f or mH_v).
Activation energy is measured from where you start
Ea is measured from the reactants up to the peak of the curve, not from zero — a common exam trap.

Equilibrium & Acids/Bases

Stress it, it shifts away
Le Chatelier's Principle: add stress (more reactant, less product, heat, pressure) and equilibrium shifts to relieve it, away from the stress.
Catalysts speed up, don't show up
A catalyst lowers activation energy and speeds a reaction, but isn't consumed and does NOT change ΔH or shift the equilibrium position.
Down the pH scale, up the acid
Each drop of 1 on the pH scale means [H⁺] is 10× bigger — pH is logarithmic, not linear.
Arrhenius: acids give H⁺, bases give OH⁻
That's the whole definition — an Arrhenius acid donates H⁺ ions in water, an Arrhenius base donates OH⁻ ions.
Strong means it splits all the way
Strong acids/bases ionize 100% in water. A dilute strong acid is still STRONG — don't confuse concentration with strength.
More collisions, more successful hits
Reaction rate increases with more concentration, more surface area, higher temperature, or a catalyst — all mean more effective collisions.

Redox & Nuclear

LEO the lion says GER
Lose Electrons = Oxidation. Gain Electrons = Reduction. Oxidation number goes up when you lose electrons, down when you gain them.
An OX and a RED CAT
Anode = OXidation (always). Cathode = REDuction (always) — true in both voltaic and electrolytic cells, even though the charge signs flip between them.
Free elements start at zero
Any uncombined element (Na, O₂, Fe) has an oxidation number of 0 — rule #1 before anything else.
Alpha is heavy, beta is light, gamma is nothing
Alpha decay: mass −4, atomic number −2. Beta decay: mass unchanged, atomic number +1. Gamma: neither changes — pure energy.
Half-life doesn't care about anything else
Half-life is constant no matter the temperature, pressure, or chemical form the isotope is in — a purely nuclear property.
Fission splits big, fusion joins small
Fission breaks a heavy nucleus (like U-235) into smaller pieces. Fusion joins light nuclei (like hydrogen) into a bigger one — the sun runs on fusion.

Organic Chemistry

Meth-Eth-Prop-But: count the carbons
Methane(1)-Ethane(2)-Propane(3)-Butane(4) — the prefix always tells you the carbon count, no matter the functional group.
-ane is full, -ene has one, -yne has two
Saturated hydrocarbons (all single bonds) end in -ane. One double bond = -ene. One triple bond = -yne.
Same family, one CH₂ apart
A homologous series is a family with the same general formula and functional group, where each member differs from the next by exactly one CH₂ unit.
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